2. MATHS P.P.T
TOPIC :- “Lateral Surface
Area And Total Surface Area Of
Cylinder, Cone, Cube And
Cuboid”
By :SANKALP . R . ANGADI
4. What is a Cylinder
• The term Cylinder refers to a right
circular cylinder.
• Like a right prism, its altitude is
perpendicular to the bases and has an
endpoint in each base.
7. Notice that we had formed 2
circles and a 1 rectangle…….
The 2 circles serves as our bases of our Cylinder and the rectangular
region represent the body.
9. EXAMPLE
Find the surface area of a cylindrical
water tank given the height of 20m and
the radius of 5m? {Use π as 3.14}
o Given: H= 20m
R= 5m
SA= V=2πr2 +2πrh
=2(3.14)(5m) 2 +2(3.14)(5m)(20m)
=157m2 + 628m2
SA = 785m2
12. Faces of Cuboid
To find the surface area of a shape, we calculate
the total area of all of the faces.
• A Cuboid has 6 faces.
The top and the bottom of the
Cuboid have the same
area.
13. Faces of Cuboid
To find the surface area of a shape, we calculate
the total area of all of the faces.
A Cuboid has 6 faces.
The front and the back of the
Cuboid have the same
area.
14. Faces of Cuboid
To find the surface area of a shape, we calculate
the total area of all of the faces.
A Cuboid has 6 faces.
The left hand side and the right hand side of
the Cuboid have the same
area.
20. What is a Cube
A cube is a three-dimensional shape that has
equal width, height, and length measurements.
A cube has six square faces, all of which have
sides of equal length and all of which meet at right
angles.
Finding the volume of a cube is a snap - generally,
all that's needed is to multiply the cube's length ×
width × height.
Since a cube's sides are all equal in length,
another way of thinking of a cube's volume is s3,
where s is the length of one of the cube's sides.
21. SURFACE AREA OF A
CUBE
All six faces of a cube
have the same area.
• The area of each face
is
x x x= x 2
Surface Area of a
Cube = 6 x 2
30. FORMULAES
• cube = a 3
• rectangular prism = a b c
• irregular prism = b h
• cylinder = b h = pi r 2 h
• pyramid = (1/3) b h
• cone = (1/3) b h = 1/3 pi r 2 h
• sphere = (4/3) pi r 3
• ellipsoid = (4/3) pi r1 r2 r3