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3. Do
you
know
why
a
100
W
bulb
glows
brighter
than
a
40
W
bulb?
Ohm’s
law
will
help
you
understand
this,
it
states
that
the
voltage
drop
across
a
component
equals
the
product
of
the
current
flowing
through
it
and
its
resistance
(
V=
I
R
).
Hence,
a
100
W
bulb
glows
brighter
as
it
offers
less
resistance
as
compared
to
a
40
W
bulb.
Now,
to
verify
this
law
one
needs
to
make
a
circuit
using
a
breadboard,
an
LED,
a
100
Ω
resistor,
a
9V
baQery
and
a
few
connecRng
wires.
A
mulRmeter
was
connected
in
series
to
complete
the
circuit.
The
current
across
the
resistor
was
calculated
using
a
mulRmeter
and
it
was
also
calculated
theoreRcally
using
Ohm’s
law.
Both
the
values
were
found
to
be
approximately
same.
Again,
if
a
100
Ω
resistor
was
replaced
by
a
1
kΩ,
and
likewise
its
current
value
was
calculated
(as
above),
both
the
theoreRcal
and
the
mulRmeter
values
were
approximately
the
same.
However,
it
was
also
observed
that
the
current
value
and
also
the
brightness
of
the
LED
decreased
as
compared
to
the
former
case.
AlternaRvely,
the
value
of
resistance
(R=V/I)
was
also
found
using
the
mulRmeter
readings
of
voltage
and
current
across
the
resistor,
which
was
nearly
equal
to
the
theoreRcal
value
of
the
resistance.
It
was
inferred
that
the
raRo
of
voltage
to
current
remains
the
same
for
a
fixed
resistance.
Hence,
Ohm’s
law
was
verified.
4. Have
a
look
at
our
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Kit!
CoolJunk
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Bootcamp-‐2011.
You
may
refer
to
this
video:
Ohm’s
Law
For
more
projects
visit
our
website:
CoolJunk
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and
Components
in
one
box.
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by
step
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