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In the name of God
Hossein Gholizadeh
Power engineering student
SBU
Find the Fourier series of below functions
𝑓 𝑥 = ቊ
𝑥 − 𝜋 < 𝑥 < 0
ℎ 0 < 𝑥 < 𝜋
𝑓 𝑥 = 𝑥 + sin 𝑥 − 𝜋 < 𝑥 < 𝜋
𝑓 𝑥 = 𝑒 𝑥 − 𝜋 < 𝑥 < 𝜋
𝑓 𝑥 = sin 𝑥 − 𝜋 < 𝑥 < 𝜋
𝑓 𝑥 = sin 𝑥 0 < 𝑥 < 𝜋
Find the sine Fourier series of below functions
𝑓 𝑥 = 𝑥2 0 < 𝑥 < 𝜋
𝑓 𝑥 = 𝑒 𝑥 0 < 𝑥 < 𝜋
𝑓 𝑥 = 𝑥 0 < 𝑥 < 𝑎
Find the cosine Fourier series of below functions
𝑓 𝑥 = cos ℎ𝑥 0 < 𝑥 < 𝜋
𝑓 𝑥 = 𝑥 0 < 𝑥 < 𝜋
𝑓 𝑥 = 𝑥 0 < 𝑥 < 𝑎
Find the Fourier series of below functions
𝑓 𝑥 = 𝑒−𝑥 0 < 𝑥 < 1
𝑓 𝑥 = sin ℎ𝑥 − 1 < 𝑥 < 1
Find the complex Fourier series of below functions
𝑓 𝑥 = 𝑒2𝑥 − 𝜋 < 𝑥 < 𝜋
𝑓 𝑥 = cos ℎ𝑥 − 𝜋 < 𝑥 < 𝜋
Find the Fourier series of below functions by derivation of other functions Fourier series
𝑓 𝑥 = 𝑠𝑖𝑛2 𝑥 0 < 𝑥 < 𝜋
𝑓 𝑥 = sin 𝑥 cos 𝑥 0 < 𝑥 < 𝜋
Find the Fourier series of functions by integration of below functions and series
෍
𝑘=1
∞
(−1) 𝑘+1
𝑘
sin 𝑘𝑥 =
𝑥
2
− 𝜋 < 𝑥 < 𝜋
4
𝜋
෍
𝑘=1
∞
sin 2𝑘 − 1 𝑥
2𝑘 − 1
= ቊ
−1 − 𝜋 < 𝑥 < 0
1 0 < 𝑥 < 𝜋
𝑥2 =
𝜋2
3
+ 4 ෍
𝑛=1
∞
(−1) 𝑛
𝑛2
𝑐𝑜𝑠𝑛𝑥 − 𝜋 < 𝑥 < 𝜋
According to written equation solve the written series.
𝜋
4
න
−𝜋
𝜋
(sin 𝑥)2 𝑑𝑥 = 2 + ෍
𝑘=1
∞
(1 + cos(2𝑘𝑥))2
( 2𝑘 2 − 1)2
1
12∗32 +
1
32∗52 +
1
52∗72+…
According to written equations, find answer of the question
𝑓 𝑡 = ൝
1 𝑡 < 1
0 𝑡 > 1
𝑓 𝑡 =
2
𝜋
න
0
∞
𝑠𝑖𝑛𝑤
𝑤
𝑐𝑜𝑠𝑤𝑡 𝑑𝑤
න
0
∞
𝑠𝑖𝑛𝑥2
𝑥
𝑑𝑥 =?
𝑓 𝑥 = න
0
∞
𝑎 𝑤 𝑐𝑜𝑠𝑤𝑥𝑑𝑤
𝑥𝑓 𝑥 = න
0
∞
𝐴 𝑤 𝑠𝑖𝑛𝑤𝑥𝑑𝑤 =?
• Is it possible to find Fourier integration for the below function?
𝑓 𝑥 = ቊ
0 𝑥 < 𝜋
−𝑠𝑖𝑛𝑥 𝑥 > 𝜋
Solve the below PDEs
𝑢 𝑥𝑥 − 𝑐2
𝑢 𝑡𝑡 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠 ቊ
𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝑙
𝑢 𝑡 𝑥, 0 = 𝑔 𝑥 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 0 𝑡 > 0
𝑢 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑥𝑥 − 𝑐2 𝑢 𝑡𝑡 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠 ቊ
𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝑙
𝑢 𝑡 𝑥, 0 = 0 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 0 𝑡 > 0
𝑢 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑥𝑥 − 𝑐2 𝑢 𝑡𝑡 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠 ቊ
𝑢 𝑥, 0 = 0 0 < 𝑥 < 𝑙
𝑢 𝑡 𝑥, 0 = 𝑔 𝑥 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 0 𝑡 > 0
𝑢 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑥𝑥 − 𝑐2 𝑢 𝑡𝑡 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠 ቊ
𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝑙
𝑢 𝑡 𝑥, 0 = 0 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 0 𝑡 > 0
𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑡𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠 ቊ
𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝑙
𝑢 𝑡 𝑥, 0 = 0 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 𝑥 0, 𝑡 = 0 𝑡 > 0
𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑡𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠 ቊ
𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝑙
𝑢 𝑡 𝑥, 0 = 𝑔(𝑥) 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 𝑥 0, 𝑡 = 0 𝑡 > 0
𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑥𝑥 − 𝑐2 𝑢 𝑡𝑡 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠 ቊ
𝑢 𝑥, 0 = 0 0 < 𝑥 < 𝑙
𝑢 𝑡 𝑥, 0 = 𝑔(𝑥) 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 𝑥 0, 𝑡 = 0 𝑡 > 0
𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑥𝑥 − 𝑐2 𝑢 𝑡𝑡 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠 ቊ
𝑢 𝑥, 0 = 0 0 < 𝑥 < 𝑙
𝑢 𝑡 𝑥, 0 = 𝑔(𝑥) 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 0 𝑡 > 0
𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑥𝑥 − 𝑐2 𝑢 𝑡𝑡 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠 ቊ
𝑢 𝑥, 0 = 𝑓(𝑥) 0 < 𝑥 < 𝑙
𝑢 𝑡 𝑥, 0 = 𝑔(𝑥) 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 0 𝑡 > 0
𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑡𝑡 + 𝑎𝑢 𝑡 + 𝑏𝑢 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠 ቊ
𝑢 𝑥, 0 = 𝑓(𝑥) 0 < 𝑥 < 𝑙
𝑢 𝑡 𝑥, 0 = 0 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 0 𝑡 > 0
𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑡𝑡 + 𝑎𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠 ቊ
𝑢 𝑥, 0 = 0 0 < 𝑥 < 𝑙
𝑢 𝑡 𝑥, 0 = 𝑔(𝑥) 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 0 𝑡 > 0
𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑓(𝑥) 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 0 𝑡 > 0
𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑓(𝑥) 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 𝑥 0, 𝑡 = 0 𝑡 > 0
𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑓(𝑥) 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 𝑥 0, 𝑡 = 0 𝑡 > 0
𝑢 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑓(𝑥) 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 0 𝑡 > 0
𝑢 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑡𝑡 − 𝑐2
𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠 ቊ
𝑢 𝑥, 0 = 𝑥 0 < 𝑥 < 1
𝑢 𝑡 𝑥, 0 = 0 0 < 𝑥 < 1
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 𝑡2
𝑡 > 0
𝑢 1, 𝑡 = 𝑐𝑜𝑠𝑡 𝑡 > 0
𝑢 𝑡𝑡 − 𝑐2
𝑢 𝑥𝑥 = ℎ(𝑥, 𝑡) 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠 ቊ
𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝑙
𝑢 𝑡 𝑥, 0 = 𝑔 𝑥 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 𝑥 0, 𝑡 = 𝑝(𝑡) 𝑡 > 0
𝑢 𝑥 𝑙, 𝑡 = 𝑞(𝑡) 𝑡 > 0
𝑢 𝑡𝑡 − 𝑐2
𝑢 𝑥𝑥 = ℎ(𝑥) 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠 ቊ
𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝑙
𝑢 𝑡 𝑥, 0 = 𝑔 𝑥 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 𝐴 𝑡 > 0
𝑢 𝑙, 𝑡 = 𝐵 𝑡 > 0
𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑥(1 − 𝑥) 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 𝑡 𝑡 > 0
𝑢 𝑙, 𝑡 = 𝑠𝑖𝑛𝑡 𝑡 > 0
𝑢 𝑡 − 𝑐2
𝑢 𝑥𝑥 = 𝑥𝑡 0 < 𝑥 < 1 𝑡 > 0
𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑠𝑖𝑛𝜋𝑥 0 < 𝑥 < 1
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 𝑡 𝑡 > 0
𝑢 1, 𝑡 = 𝑡2 𝑡 > 0
𝑢 𝑡 − 𝑐2
𝑢 𝑥𝑥 = ℎ 0 < 𝑥 < 1 𝑡 > 0
𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑢0 1 − 𝑐𝑜𝑠𝜋𝑥 0 < 𝑥 < 1
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 0 𝑡 > 0
𝑢 1, 𝑡 = 2 𝑢0 𝑡 > 0
𝑢 𝑡 − 𝑐2
𝑢 𝑥𝑥 = 𝐴𝑒−𝑎𝑥
0 < 𝑥 < 𝜋 𝑡 > 0
𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑠𝑖𝑛𝑥 0 < 𝑥 < 𝜋
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 0 𝑡 > 0
𝑢 𝜋, 𝑡 = 0 𝑡 > 0
𝑢 𝑡 − 𝑐2
𝑢 𝑥𝑥 = ℎ(𝑥, 𝑡) 0 < 𝑥 < 𝑙 𝑡 > 0
𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑓(𝑥) 0 < 𝑥 < 𝑙
𝐵𝐶𝑠 ቊ
𝑢 0, 𝑡 = 𝑝(𝑡) 𝑡 > 0
𝑢 𝑙, 𝑡 = 𝑞(𝑡) 𝑡 > 0
𝑢 𝑥𝑥 + 𝑢 𝑦𝑦 = 0 0 < 𝑥 < ∞ , 0 < 𝑦 < ∞
𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < ∞
𝑢 𝑥 0, 𝑦 = 𝑔 𝑦 0 < 𝑦 < ∞
lim
𝑥→∞
𝑢 𝑥, 𝑦 = 0
𝑢 𝑡 − 𝑢 𝑥𝑥 + ℎ 𝑡 𝑢 𝑥 = 𝛿 𝑥 𝛿 𝑡 0 < 𝑥 < ∞ 𝑡 > 0
𝑢 𝑥 0, 𝑡 = 𝑢 𝑥, 0 = 0
lim
𝑥→∞
𝑢 𝑥, 𝑡 = 0
𝑢 𝑥𝑥 + 𝑢 𝑦𝑦 = 0 𝑥 > 0 0 < 𝑦 < 1
𝑢 𝑥, 0 = 𝑓 𝑥 𝑢 𝑥, 1 = 0 𝑥 > 0
𝑢 0, 𝑦 = 0,
lim
𝑦→∞
𝑢(𝑥, 𝑦) = 0
𝑢 𝑡𝑡 = 𝑐2 𝑢 𝑥𝑥 0 < 𝑥 < ∞ 𝑡 > 0
𝑢 𝑥, 0 = 𝑓 𝑥 𝑢 𝑡 𝑥, 0 = 0
𝑢 0, 𝑡 = 0 lim
𝑥→∞
𝑢(𝑥, 𝑡) = 0
𝑢 𝑡𝑡 = 𝑐2 𝑢 𝑥𝑥 0 < 𝑥 < 𝑙 𝑡 > 0
𝑢 𝑥, 0 = 0 𝑢 𝑡 𝑥, 0 = 0
𝑢 0, 𝑡 = 𝑓 𝑡 , 𝑢 𝑙, 𝑡 = 0 𝑡 > 0
𝑢 𝑡 = 𝑘𝑢 𝑥𝑥 0 < 𝑥 < ∞ 𝑡 > 0
𝑢 𝑥, 0 = 𝑓0 0 < 𝑥 < ∞
𝑢 0, 𝑡 = 𝑓1 lim
𝑥→∞
𝑢(𝑥, 𝑡) = 𝑓0 𝑡 > 0
𝑢 𝑡 = 𝑘𝑢 𝑥𝑥 0 < 𝑥 < ∞ 𝑡 > 0
𝑢 𝑥, 0 = 𝑥 0 < 𝑥 < ∞
𝑢 0, 𝑡 = 0 lim
𝑥→∞
𝑢(𝑥, 𝑡) = 𝑥 𝑡 > 0
𝑢 𝑡 = 𝑘𝑢 𝑥𝑥 0 < 𝑥 < ∞ 𝑡 > 0
𝑢 𝑥, 0 = 𝑥 0 < 𝑥 < ∞
𝑢 0, 𝑡 = 𝑡2
lim
𝑥→∞
𝑢(𝑥, 𝑡) = 0 𝑡 > 0
𝑢 𝑡 = 𝑘𝑢 𝑥𝑥 − ℎ𝑢 0 < 𝑥 < ∞ 𝑡 > 0 ℎ 𝑖𝑠 𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡
𝑢 𝑥, 0 = 𝑓0 0 < 𝑥 < ∞
𝑢 0, 𝑡 = 0 lim
𝑥→∞
𝑢 𝑥(𝑥, 𝑡) = 0 𝑡 > 0
𝑢 𝑡𝑡 = 𝑐2 𝑢 𝑥𝑥 0 < 𝑥 < ∞ 𝑡 > 0
𝑢 𝑥, 0 = 0 𝑢 𝑡 𝑥, 0 = 𝑓0
𝑢 0, 𝑡 = 0 lim
𝑥→∞
𝑢 𝑡(𝑥, 𝑡) = 0
𝑢 𝑡 = 𝑢 𝑥𝑥 + 𝑔 𝑥, 𝑡 0 < 𝑥 < 𝜋 𝑡 > 0
𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝜋
𝑢 0, 𝑡 = 𝑢 𝜋, 𝑡 = 0
𝑢 𝑡 = 𝑢 𝑥𝑥 + 𝑔 𝑥, 𝑡 0 < 𝑥 < 𝜋 𝑡 > 0
𝑢 𝑥, 0 = 0 0 < 𝑥 < 𝜋
𝑢 0, 𝑡 = 0 𝑢 𝑥 𝜋, 𝑡 + ℎ𝑢 𝜋, 𝑡 = 0 𝑡 > 0
𝑢 𝑡 = 𝑢 𝑥𝑥 + 𝑔 𝑥, 𝑡 0 < 𝑥 < 𝜋 𝑡 > 0
𝑢 𝑥, 0 = 0 0 < 𝑥 < 𝜋
𝑢 0, 𝑡 = 𝑢 𝑥 𝜋, 𝑡 = 0
𝑢 𝑡𝑡 = 𝑢 𝑥𝑥 + ℎ 0 < 𝑥 < 𝜋 𝑡 > 0
𝑢 𝑥, 0 = 0 𝑢 𝑡 𝑥, 0 = 0 0 < 𝑥 < 𝜋
𝑢 𝑥 0, 𝑡 = 𝑢 𝑥 𝜋, 𝑡 = 0
𝑢 𝑡𝑡 = 𝑢 𝑥𝑥 + 𝑔(𝑥) 0 < 𝑥 < 𝜋 𝑡 > 0
𝑢 𝑥, 0 = 0 𝑢 𝑡 𝑥, 0 = 0 0 < 𝑥 < 𝜋
𝑢 0, 𝑡 = 𝑢 𝜋, 𝑡 = 0
• Find the Fourier transform of the below functions
𝑓 𝑥 = 𝛿 𝑥
𝑓 𝑥 = 𝑢 𝑥
𝑓 𝑥 = 𝑋[−𝑎,𝑎] = ቊ
1 − 𝑎 < 𝑥 < 𝑎
0 𝑜𝑡ℎ𝑒𝑟𝑠
𝑓 𝑥 =
𝑠𝑖𝑛𝑥
𝑥
= 𝑠𝑖𝑛𝑐 𝑥
𝑓 𝑥 = 𝑠𝑖𝑛𝑥
𝑓 𝑥 = 𝑐𝑜𝑠𝑥
𝑓 𝑥 = 𝑒−𝑎|𝑥|
𝑓 𝑥 = 𝑒−𝑎𝑥2
𝑓 𝑥 = 𝑒−𝑎𝑥 𝑢 𝑥
𝑓 𝑥 = 𝛿 𝑥 − 𝑎
𝑓 𝑥 = Λ(
𝑥
2𝑎
)
𝑓 𝑥 = 𝑠𝑔𝑛 𝑥
𝑓 𝑥 = 𝛿′ 𝑥
𝑓 𝑥 = 𝛿(𝑥)(𝑛)
𝑓 𝑥 =
1
𝑥
𝑓 𝑥 = 𝑒 𝑗𝑎𝑥
𝑓 𝑥 = 𝑠𝑖𝑛𝑐2 𝑥
෍
−∞
∞
𝛿(𝑥 − 𝑛𝑇0)
• Prove the below equalities
න
−∞
∞
𝐹 𝑘 𝑔 𝑘 𝑒 𝑗𝑘𝑥
𝑑𝑘 = න
−∞
∞
𝑓 𝑦 𝐺 𝑦 − 𝑥 𝑑𝑦
𝑠𝑖𝑛𝑥 ∗ 𝑒−𝑎 𝑥
=
2
𝜋
𝑎𝑠𝑖𝑛𝑥
1 + 𝑎2
න
−∞
∞
𝐹 𝑘 𝑔 𝑘 𝑑𝑘 = න
−∞
∞
𝑓 𝑦 𝐺 𝑦 𝑑𝑦
න
0
∞
𝑒−𝑎2 𝑥2
𝑐𝑜𝑠𝑏𝑥𝑑𝑥 =
𝜋
2𝑎
𝑒
−𝑏2
4𝑎2
න
−∞
∞
(𝑓 ∗ 𝑔)(𝑥) = න
−∞
∞
𝑓 𝑢 𝑑𝑢 න
−∞
∞
𝑔 𝑣 𝑑𝑣
𝑓 ∗ 𝑔 𝑚+𝑛 𝑥 = 𝑓 𝑚 𝑥 ∗ 𝑔 𝑛 (𝑥)
𝐹 𝑓 𝑎𝑥 − 𝑏 =
1
𝑎
𝑒
𝑗𝑘𝑏
𝑎 𝐹
𝑘
𝑎
Thanks for your attention

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Fourier series and pde

  • 1. In the name of God Hossein Gholizadeh Power engineering student SBU
  • 2. Find the Fourier series of below functions 𝑓 𝑥 = ቊ 𝑥 − 𝜋 < 𝑥 < 0 ℎ 0 < 𝑥 < 𝜋 𝑓 𝑥 = 𝑥 + sin 𝑥 − 𝜋 < 𝑥 < 𝜋 𝑓 𝑥 = 𝑒 𝑥 − 𝜋 < 𝑥 < 𝜋 𝑓 𝑥 = sin 𝑥 − 𝜋 < 𝑥 < 𝜋 𝑓 𝑥 = sin 𝑥 0 < 𝑥 < 𝜋
  • 3. Find the sine Fourier series of below functions 𝑓 𝑥 = 𝑥2 0 < 𝑥 < 𝜋 𝑓 𝑥 = 𝑒 𝑥 0 < 𝑥 < 𝜋 𝑓 𝑥 = 𝑥 0 < 𝑥 < 𝑎
  • 4. Find the cosine Fourier series of below functions 𝑓 𝑥 = cos ℎ𝑥 0 < 𝑥 < 𝜋 𝑓 𝑥 = 𝑥 0 < 𝑥 < 𝜋 𝑓 𝑥 = 𝑥 0 < 𝑥 < 𝑎
  • 5. Find the Fourier series of below functions 𝑓 𝑥 = 𝑒−𝑥 0 < 𝑥 < 1 𝑓 𝑥 = sin ℎ𝑥 − 1 < 𝑥 < 1
  • 6. Find the complex Fourier series of below functions 𝑓 𝑥 = 𝑒2𝑥 − 𝜋 < 𝑥 < 𝜋 𝑓 𝑥 = cos ℎ𝑥 − 𝜋 < 𝑥 < 𝜋
  • 7. Find the Fourier series of below functions by derivation of other functions Fourier series 𝑓 𝑥 = 𝑠𝑖𝑛2 𝑥 0 < 𝑥 < 𝜋 𝑓 𝑥 = sin 𝑥 cos 𝑥 0 < 𝑥 < 𝜋
  • 8. Find the Fourier series of functions by integration of below functions and series ෍ 𝑘=1 ∞ (−1) 𝑘+1 𝑘 sin 𝑘𝑥 = 𝑥 2 − 𝜋 < 𝑥 < 𝜋 4 𝜋 ෍ 𝑘=1 ∞ sin 2𝑘 − 1 𝑥 2𝑘 − 1 = ቊ −1 − 𝜋 < 𝑥 < 0 1 0 < 𝑥 < 𝜋 𝑥2 = 𝜋2 3 + 4 ෍ 𝑛=1 ∞ (−1) 𝑛 𝑛2 𝑐𝑜𝑠𝑛𝑥 − 𝜋 < 𝑥 < 𝜋
  • 9. According to written equation solve the written series. 𝜋 4 න −𝜋 𝜋 (sin 𝑥)2 𝑑𝑥 = 2 + ෍ 𝑘=1 ∞ (1 + cos(2𝑘𝑥))2 ( 2𝑘 2 − 1)2 1 12∗32 + 1 32∗52 + 1 52∗72+…
  • 10. According to written equations, find answer of the question 𝑓 𝑡 = ൝ 1 𝑡 < 1 0 𝑡 > 1 𝑓 𝑡 = 2 𝜋 න 0 ∞ 𝑠𝑖𝑛𝑤 𝑤 𝑐𝑜𝑠𝑤𝑡 𝑑𝑤 න 0 ∞ 𝑠𝑖𝑛𝑥2 𝑥 𝑑𝑥 =? 𝑓 𝑥 = න 0 ∞ 𝑎 𝑤 𝑐𝑜𝑠𝑤𝑥𝑑𝑤 𝑥𝑓 𝑥 = න 0 ∞ 𝐴 𝑤 𝑠𝑖𝑛𝑤𝑥𝑑𝑤 =?
  • 11. • Is it possible to find Fourier integration for the below function? 𝑓 𝑥 = ቊ 0 𝑥 < 𝜋 −𝑠𝑖𝑛𝑥 𝑥 > 𝜋
  • 12. Solve the below PDEs 𝑢 𝑥𝑥 − 𝑐2 𝑢 𝑡𝑡 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠 ቊ 𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝑙 𝑢 𝑡 𝑥, 0 = 𝑔 𝑥 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 0 𝑡 > 0 𝑢 𝑙, 𝑡 = 0 𝑡 > 0
  • 13. 𝑢 𝑥𝑥 − 𝑐2 𝑢 𝑡𝑡 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠 ቊ 𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝑙 𝑢 𝑡 𝑥, 0 = 0 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 0 𝑡 > 0 𝑢 𝑙, 𝑡 = 0 𝑡 > 0
  • 14. 𝑢 𝑥𝑥 − 𝑐2 𝑢 𝑡𝑡 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠 ቊ 𝑢 𝑥, 0 = 0 0 < 𝑥 < 𝑙 𝑢 𝑡 𝑥, 0 = 𝑔 𝑥 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 0 𝑡 > 0 𝑢 𝑙, 𝑡 = 0 𝑡 > 0
  • 15. 𝑢 𝑥𝑥 − 𝑐2 𝑢 𝑡𝑡 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠 ቊ 𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝑙 𝑢 𝑡 𝑥, 0 = 0 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 0 𝑡 > 0 𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
  • 16. 𝑢 𝑡𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠 ቊ 𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝑙 𝑢 𝑡 𝑥, 0 = 0 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 𝑥 0, 𝑡 = 0 𝑡 > 0 𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
  • 17. 𝑢 𝑡𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠 ቊ 𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝑙 𝑢 𝑡 𝑥, 0 = 𝑔(𝑥) 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 𝑥 0, 𝑡 = 0 𝑡 > 0 𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
  • 18. 𝑢 𝑥𝑥 − 𝑐2 𝑢 𝑡𝑡 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠 ቊ 𝑢 𝑥, 0 = 0 0 < 𝑥 < 𝑙 𝑢 𝑡 𝑥, 0 = 𝑔(𝑥) 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 𝑥 0, 𝑡 = 0 𝑡 > 0 𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
  • 19. 𝑢 𝑥𝑥 − 𝑐2 𝑢 𝑡𝑡 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠 ቊ 𝑢 𝑥, 0 = 0 0 < 𝑥 < 𝑙 𝑢 𝑡 𝑥, 0 = 𝑔(𝑥) 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 0 𝑡 > 0 𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
  • 20. 𝑢 𝑥𝑥 − 𝑐2 𝑢 𝑡𝑡 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠 ቊ 𝑢 𝑥, 0 = 𝑓(𝑥) 0 < 𝑥 < 𝑙 𝑢 𝑡 𝑥, 0 = 𝑔(𝑥) 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 0 𝑡 > 0 𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
  • 21. 𝑢 𝑡𝑡 + 𝑎𝑢 𝑡 + 𝑏𝑢 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠 ቊ 𝑢 𝑥, 0 = 𝑓(𝑥) 0 < 𝑥 < 𝑙 𝑢 𝑡 𝑥, 0 = 0 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 0 𝑡 > 0 𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
  • 22. 𝑢 𝑡𝑡 + 𝑎𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠 ቊ 𝑢 𝑥, 0 = 0 0 < 𝑥 < 𝑙 𝑢 𝑡 𝑥, 0 = 𝑔(𝑥) 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 0 𝑡 > 0 𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
  • 23. 𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑓(𝑥) 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 0 𝑡 > 0 𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
  • 24. 𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑓(𝑥) 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 𝑥 0, 𝑡 = 0 𝑡 > 0 𝑢 𝑥 𝑙, 𝑡 = 0 𝑡 > 0
  • 25. 𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑓(𝑥) 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 𝑥 0, 𝑡 = 0 𝑡 > 0 𝑢 𝑙, 𝑡 = 0 𝑡 > 0
  • 26. 𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑓(𝑥) 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 0 𝑡 > 0 𝑢 𝑙, 𝑡 = 0 𝑡 > 0
  • 27. 𝑢 𝑡𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠 ቊ 𝑢 𝑥, 0 = 𝑥 0 < 𝑥 < 1 𝑢 𝑡 𝑥, 0 = 0 0 < 𝑥 < 1 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 𝑡2 𝑡 > 0 𝑢 1, 𝑡 = 𝑐𝑜𝑠𝑡 𝑡 > 0 𝑢 𝑡𝑡 − 𝑐2 𝑢 𝑥𝑥 = ℎ(𝑥, 𝑡) 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠 ቊ 𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝑙 𝑢 𝑡 𝑥, 0 = 𝑔 𝑥 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 𝑥 0, 𝑡 = 𝑝(𝑡) 𝑡 > 0 𝑢 𝑥 𝑙, 𝑡 = 𝑞(𝑡) 𝑡 > 0
  • 28. 𝑢 𝑡𝑡 − 𝑐2 𝑢 𝑥𝑥 = ℎ(𝑥) 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠 ቊ 𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝑙 𝑢 𝑡 𝑥, 0 = 𝑔 𝑥 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 𝐴 𝑡 > 0 𝑢 𝑙, 𝑡 = 𝐵 𝑡 > 0 𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = 0 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑥(1 − 𝑥) 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 𝑡 𝑡 > 0 𝑢 𝑙, 𝑡 = 𝑠𝑖𝑛𝑡 𝑡 > 0
  • 29. 𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = 𝑥𝑡 0 < 𝑥 < 1 𝑡 > 0 𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑠𝑖𝑛𝜋𝑥 0 < 𝑥 < 1 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 𝑡 𝑡 > 0 𝑢 1, 𝑡 = 𝑡2 𝑡 > 0 𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = ℎ 0 < 𝑥 < 1 𝑡 > 0 𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑢0 1 − 𝑐𝑜𝑠𝜋𝑥 0 < 𝑥 < 1 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 0 𝑡 > 0 𝑢 1, 𝑡 = 2 𝑢0 𝑡 > 0
  • 30. 𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = 𝐴𝑒−𝑎𝑥 0 < 𝑥 < 𝜋 𝑡 > 0 𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑠𝑖𝑛𝑥 0 < 𝑥 < 𝜋 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 0 𝑡 > 0 𝑢 𝜋, 𝑡 = 0 𝑡 > 0 𝑢 𝑡 − 𝑐2 𝑢 𝑥𝑥 = ℎ(𝑥, 𝑡) 0 < 𝑥 < 𝑙 𝑡 > 0 𝐼𝐶𝑠: 𝑢 𝑥, 0 = 𝑓(𝑥) 0 < 𝑥 < 𝑙 𝐵𝐶𝑠 ቊ 𝑢 0, 𝑡 = 𝑝(𝑡) 𝑡 > 0 𝑢 𝑙, 𝑡 = 𝑞(𝑡) 𝑡 > 0
  • 31. 𝑢 𝑥𝑥 + 𝑢 𝑦𝑦 = 0 0 < 𝑥 < ∞ , 0 < 𝑦 < ∞ 𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < ∞ 𝑢 𝑥 0, 𝑦 = 𝑔 𝑦 0 < 𝑦 < ∞ lim 𝑥→∞ 𝑢 𝑥, 𝑦 = 0 𝑢 𝑡 − 𝑢 𝑥𝑥 + ℎ 𝑡 𝑢 𝑥 = 𝛿 𝑥 𝛿 𝑡 0 < 𝑥 < ∞ 𝑡 > 0 𝑢 𝑥 0, 𝑡 = 𝑢 𝑥, 0 = 0 lim 𝑥→∞ 𝑢 𝑥, 𝑡 = 0
  • 32. 𝑢 𝑥𝑥 + 𝑢 𝑦𝑦 = 0 𝑥 > 0 0 < 𝑦 < 1 𝑢 𝑥, 0 = 𝑓 𝑥 𝑢 𝑥, 1 = 0 𝑥 > 0 𝑢 0, 𝑦 = 0, lim 𝑦→∞ 𝑢(𝑥, 𝑦) = 0 𝑢 𝑡𝑡 = 𝑐2 𝑢 𝑥𝑥 0 < 𝑥 < ∞ 𝑡 > 0 𝑢 𝑥, 0 = 𝑓 𝑥 𝑢 𝑡 𝑥, 0 = 0 𝑢 0, 𝑡 = 0 lim 𝑥→∞ 𝑢(𝑥, 𝑡) = 0 𝑢 𝑡𝑡 = 𝑐2 𝑢 𝑥𝑥 0 < 𝑥 < 𝑙 𝑡 > 0 𝑢 𝑥, 0 = 0 𝑢 𝑡 𝑥, 0 = 0 𝑢 0, 𝑡 = 𝑓 𝑡 , 𝑢 𝑙, 𝑡 = 0 𝑡 > 0
  • 33. 𝑢 𝑡 = 𝑘𝑢 𝑥𝑥 0 < 𝑥 < ∞ 𝑡 > 0 𝑢 𝑥, 0 = 𝑓0 0 < 𝑥 < ∞ 𝑢 0, 𝑡 = 𝑓1 lim 𝑥→∞ 𝑢(𝑥, 𝑡) = 𝑓0 𝑡 > 0 𝑢 𝑡 = 𝑘𝑢 𝑥𝑥 0 < 𝑥 < ∞ 𝑡 > 0 𝑢 𝑥, 0 = 𝑥 0 < 𝑥 < ∞ 𝑢 0, 𝑡 = 0 lim 𝑥→∞ 𝑢(𝑥, 𝑡) = 𝑥 𝑡 > 0 𝑢 𝑡 = 𝑘𝑢 𝑥𝑥 0 < 𝑥 < ∞ 𝑡 > 0 𝑢 𝑥, 0 = 𝑥 0 < 𝑥 < ∞ 𝑢 0, 𝑡 = 𝑡2 lim 𝑥→∞ 𝑢(𝑥, 𝑡) = 0 𝑡 > 0 𝑢 𝑡 = 𝑘𝑢 𝑥𝑥 − ℎ𝑢 0 < 𝑥 < ∞ 𝑡 > 0 ℎ 𝑖𝑠 𝑐𝑜𝑛𝑠𝑡𝑎𝑛𝑡 𝑢 𝑥, 0 = 𝑓0 0 < 𝑥 < ∞ 𝑢 0, 𝑡 = 0 lim 𝑥→∞ 𝑢 𝑥(𝑥, 𝑡) = 0 𝑡 > 0
  • 34. 𝑢 𝑡𝑡 = 𝑐2 𝑢 𝑥𝑥 0 < 𝑥 < ∞ 𝑡 > 0 𝑢 𝑥, 0 = 0 𝑢 𝑡 𝑥, 0 = 𝑓0 𝑢 0, 𝑡 = 0 lim 𝑥→∞ 𝑢 𝑡(𝑥, 𝑡) = 0 𝑢 𝑡 = 𝑢 𝑥𝑥 + 𝑔 𝑥, 𝑡 0 < 𝑥 < 𝜋 𝑡 > 0 𝑢 𝑥, 0 = 𝑓 𝑥 0 < 𝑥 < 𝜋 𝑢 0, 𝑡 = 𝑢 𝜋, 𝑡 = 0 𝑢 𝑡 = 𝑢 𝑥𝑥 + 𝑔 𝑥, 𝑡 0 < 𝑥 < 𝜋 𝑡 > 0 𝑢 𝑥, 0 = 0 0 < 𝑥 < 𝜋 𝑢 0, 𝑡 = 0 𝑢 𝑥 𝜋, 𝑡 + ℎ𝑢 𝜋, 𝑡 = 0 𝑡 > 0 𝑢 𝑡 = 𝑢 𝑥𝑥 + 𝑔 𝑥, 𝑡 0 < 𝑥 < 𝜋 𝑡 > 0 𝑢 𝑥, 0 = 0 0 < 𝑥 < 𝜋 𝑢 0, 𝑡 = 𝑢 𝑥 𝜋, 𝑡 = 0
  • 35. 𝑢 𝑡𝑡 = 𝑢 𝑥𝑥 + ℎ 0 < 𝑥 < 𝜋 𝑡 > 0 𝑢 𝑥, 0 = 0 𝑢 𝑡 𝑥, 0 = 0 0 < 𝑥 < 𝜋 𝑢 𝑥 0, 𝑡 = 𝑢 𝑥 𝜋, 𝑡 = 0 𝑢 𝑡𝑡 = 𝑢 𝑥𝑥 + 𝑔(𝑥) 0 < 𝑥 < 𝜋 𝑡 > 0 𝑢 𝑥, 0 = 0 𝑢 𝑡 𝑥, 0 = 0 0 < 𝑥 < 𝜋 𝑢 0, 𝑡 = 𝑢 𝜋, 𝑡 = 0
  • 36. • Find the Fourier transform of the below functions 𝑓 𝑥 = 𝛿 𝑥 𝑓 𝑥 = 𝑢 𝑥 𝑓 𝑥 = 𝑋[−𝑎,𝑎] = ቊ 1 − 𝑎 < 𝑥 < 𝑎 0 𝑜𝑡ℎ𝑒𝑟𝑠 𝑓 𝑥 = 𝑠𝑖𝑛𝑥 𝑥 = 𝑠𝑖𝑛𝑐 𝑥
  • 37. 𝑓 𝑥 = 𝑠𝑖𝑛𝑥 𝑓 𝑥 = 𝑐𝑜𝑠𝑥 𝑓 𝑥 = 𝑒−𝑎|𝑥| 𝑓 𝑥 = 𝑒−𝑎𝑥2 𝑓 𝑥 = 𝑒−𝑎𝑥 𝑢 𝑥 𝑓 𝑥 = 𝛿 𝑥 − 𝑎 𝑓 𝑥 = Λ( 𝑥 2𝑎 )
  • 38. 𝑓 𝑥 = 𝑠𝑔𝑛 𝑥 𝑓 𝑥 = 𝛿′ 𝑥 𝑓 𝑥 = 𝛿(𝑥)(𝑛) 𝑓 𝑥 = 1 𝑥 𝑓 𝑥 = 𝑒 𝑗𝑎𝑥 𝑓 𝑥 = 𝑠𝑖𝑛𝑐2 𝑥 ෍ −∞ ∞ 𝛿(𝑥 − 𝑛𝑇0)
  • 39. • Prove the below equalities න −∞ ∞ 𝐹 𝑘 𝑔 𝑘 𝑒 𝑗𝑘𝑥 𝑑𝑘 = න −∞ ∞ 𝑓 𝑦 𝐺 𝑦 − 𝑥 𝑑𝑦 𝑠𝑖𝑛𝑥 ∗ 𝑒−𝑎 𝑥 = 2 𝜋 𝑎𝑠𝑖𝑛𝑥 1 + 𝑎2 න −∞ ∞ 𝐹 𝑘 𝑔 𝑘 𝑑𝑘 = න −∞ ∞ 𝑓 𝑦 𝐺 𝑦 𝑑𝑦 න 0 ∞ 𝑒−𝑎2 𝑥2 𝑐𝑜𝑠𝑏𝑥𝑑𝑥 = 𝜋 2𝑎 𝑒 −𝑏2 4𝑎2 න −∞ ∞ (𝑓 ∗ 𝑔)(𝑥) = න −∞ ∞ 𝑓 𝑢 𝑑𝑢 න −∞ ∞ 𝑔 𝑣 𝑑𝑣
  • 40. 𝑓 ∗ 𝑔 𝑚+𝑛 𝑥 = 𝑓 𝑚 𝑥 ∗ 𝑔 𝑛 (𝑥) 𝐹 𝑓 𝑎𝑥 − 𝑏 = 1 𝑎 𝑒 𝑗𝑘𝑏 𝑎 𝐹 𝑘 𝑎 Thanks for your attention