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Concentric Winding (EED)

in this PPT I Gave Information To ac Concentric winding And its placing . and i gave solve example and calcution of concentric winding.

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Concentric Winding (EED)

  1. 1. Electrical Elements Design (2150904) Active Learning Assignment on Concentric Windings Prepared By: Patel RajalKumar H. (160123109013) Guided By : Prof. Purv Mistry Electrical Department Batch-B3Gandhinagar Institute of Technology1
  2. 2. Introduction Gandhinagar Institute of Technology2 • Three-phase concentric winding consists of coil groups laid in the slots so that all the coils of each group are concentric. • That is, the coil with the smallest slot pitch is surrounding by the coil with the next larger slot pitch and so on to make up a coil group. • Each coil consists of several turns and the cross-over from one coil to the next is indicated by a short slanted line (jumper).
  3. 3. AC Armature Windings Single layer winding Double layer winding Concentric winding Mush winding Lap winding Wave winding Hemitro -pic Whole coil winding Integral slot Fraction -al slot Integral slot Fraction -al slot Types of AC armature winding Gandhinagar Institute of Technology3
  4. 4. Concentrated armature winding • Concentrated winding is employed where number of slots on the armature is equal to number of poles in the machine. • This armature winding of alternator gives maximum output voltage but not exactly sinusoidal. • Here, number poles = number of slots = number of coil sides , which is shown in below fig. • Here, one coil side is inside one slot under one pole and other coil side inside other slot under next pole. Gandhinagar Institute of Technology4
  5. 5. Gandhinagar Institute of Technology5
  6. 6. Construction of concentrated winding Gandhinagar Institute of Technology6 • In order to construct the diagram for a winding, the following data must be known: S - The number of slots in the stator P – The number of poles m – The number of phases YS – The pitch of the winding a – The number of parallel circuits in the windings
  7. 7. • The pitch of the winding is determined by the formula • The pitch is the distance between two sides of a coil expressed as the difference between the numbers of the slots in which the sides lie. • Another important value of the winding of ac machines is the number of slot per phase per pole denoted by the letter q. It can be determined by the formula Pole-pitch Coil-sides q Start (S) Finish (F) Jumper A coil-group with 3-coils Y3 Y1 Y2 1 2 3 10 12 11 P S YS  mP S q   Gandhinagar Institute of Technology7
  8. 8. Example#1: on concentric winding Gandhinagar Institute of Technology8 Given data S=24; p=4;m=3; a=1; type=Concentric • Solution 1. The number of coil groups, K 2. The number of slots per pole per phase, q 3. Coil pitch ∴The shorter coil pitch = YS-1=6-1=5 Full-Pitch ( average pitch) i.e. there are two coils in a group i.e. there is two coil groups per phase6 2 4 3 2 3K  P 2 43 24 pm S q      6 4 24 p S YS 
  9. 9. The larger coil pitch = YS+1=6+1=7 1. The electrical angle, 𝛾 2. The angle between adjacent slots, 𝛼 3. The distance between the beginning of each phase,  4. If the beginning of Phase A is slot 1, then the beginning of phase B is slot 1+=5 and the beginning of phase C is slot 1+2=1+8=9  7204180180  P   30 24 720  S   slots4 30 120120      Gandhinagar Institute of Technology9
  10. 10. PROCEDURE FOR CONSTRUCTING OF CONCENTRIC WINDINGS Gandhinagar Institute of Technology10 Data: S= 24, P = 4, a = 1, q = 2, K = 6
  11. 11. Coil Groups of Phase A Gandhinagar Institute of Technology11 2. The first and second slots will be occupied by left-hand sides of the first coil group of phase A. 3. Leave four, or 2q slots free for other two phases occupy slots 7 & 8 with the right hand side of the first coil group. 4. Next to it will lie a second coil group of the same size which occupies slots 9,10,15,16. 1 2 8 7 6 5 4 3 9 10 19 18 11 17 1614 1513 12 23 22 21 20 24
  12. 12. Coil Groups of Phase B Gandhinagar Institute of Technology12 • In order to find, where the second phase (B) should begin, it is necessary to know the angle between slots in electrical degrees.  =180.P = 180.4 = 7200 – Electrical degree • The angle between adjacent slots, 𝛼 • The distance between phase beginnings will have 1 2 8 7 6 5 4 3 9 10 19 18 11 17 1614 1513 12 23 22 21 20 24 slots4 30 120120           30 24 720  S  
  13. 13. Coil Groups of Phase C Gandhinagar Institute of Technology13 1 2 8 7 6 5 4 3 9 10 19 18 11 17 1614 1513 12 23 22 21 20 24 3 4 3 4 22 21 21 22
  14. 14. Current direction Gandhinagar Institute of Technology14 N 1-6 N 13-18 S 7-12 S 19-24 1 2 8 7 6 5 4 3 9 10 19 18 11 17 1614 1513 12 23 22 21 20 24 21 22 3 4 22 21 3 4 N SNS
  15. 15. Phase A – Coil groups interconnection Gandhinagar Institute of Technology15 1 2 8 7 6 5 4 3 9 10 19 18 11 17 1614 1513 12 23 22 21 20 24 21 22 3 4 22 21 3 4 N SNS
  16. 16. Phase B – Coil groups interconnection Gandhinagar Institute of Technology16 1 2 8 7 6 5 4 3 9 10 19 18 11 17 1614 1513 12 23 22 21 20 24 21 22 3 4 22 21 3 4 N SNS
  17. 17. Phase C – Coil groups interconnection Gandhinagar Institute of Technology17 1 2 8 7 6 5 4 3 9 10 19 18 11 17 1614 1513 12 23 22 21 20 24 21 22 3 4 22 21 3 4 N SNS
  18. 18. Terminals Gandhinagar Institute of Technology18 1 2 8 7 6 5 4 3 9 10 19 18 11 17 1614 1513 12 23 22 21 20 24 21 22 3 4 22 21 3 4 N SNS A B’A’C’ CB
  19. 19. Gandhinagar Institute of Technology19

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in this PPT I Gave Information To ac Concentric winding And its placing . and i gave solve example and calcution of concentric winding.

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