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Lecture 3 
Fundamental Limitations of Solar Cells 
R. Treharne 
Nov 5th 2014
Key Question 
L3 
Why can't a solar cell have a 
100% efficiency? 
(Or even close to 100%?) 
Can you answer this?
Lecture Outline 
L3 
● Black Body Radiation 
● Detailed Balance 
● The Shockley-Queisser Limit 
● Requirements for real physical systems 
● Exceeding the SQ limit (funky solar)
Black Body Radiation 
L3 
A black body absorbs all radiation regardless of frequency or angle of incidence. 
A black body in thermal equilibrium emits radiation according to Planck's Law.
Planck's Law 
L3 
Photon Flux – Number of photons of energy E per unit area per second 
h3 c2 ( E2 
b(E)= 2F 
eE/ kB T−1 ) 
Units – Number of photons of energy E per unit area per second
Planck's Law 
L3 
Photon Flux density from a spherical black body 
h3 c2 ( E2 
b(E)= 2F 
eE/ kB T−1 ) 
Look familiar? 
c.f. Ideal diode 
Units – Number of photons of energy E per unit area per second
Planck's Law 
L3 
Photon Flux – Number of photons of energy E per unit area per second 
h3 c2 ( E2 
b(E)= 2F 
eE/ kB T−1 ) 
What the heck is this? 
Units – Number of photons of energy E per unit area per second
Planck's Law 
L3 
F=π sin2 θ Geometrical factor 
A θB B 
FFA=π 
A=FB=π sin2(θB) 
Black body
Irradiance 
L3 
Irradiance - Emitted energy flux density 
L(E)=Eb(E) 
This is what solar spectrum data is measured in
Irradiance 
L3 
Irradiance - Emitted energy flux density 
L(E)=Eb(E) 
This is what solar spectrum data is measured in 
Power Density given by 
P=∫0 
∞ 
L( E)dE
Irradiance 
L3 
Irradiance - Emitted energy flux density 
L(E)=Eb(E) 
This is what solar spectrum data is measured in 
Power Density given by 
P=∫0 
Stefan-Boltzmann Law 
∞ 
L( E)dE=σsT 4 
σS= 
2π5 kB 4 
15c2 h3 
Stefan's constant
The Sun (again) 
L3 
The sun is a black body emitter with a temperature of 5760K 
At its surface, the Power density is: 
PS = 62 MW m-2 
what is the power density of the Sun's emitted 
radiation at the Earth's surface, PE? 
PE= 
FE 
FS 
PS ~ 1353 m-2
L3 
Detailed Balance 
What are we doing? 
● Counting all photons going in 
● Counting all photons going out 
● Difference must be converted into electrical 
(electrochemical potential) 
Key Assumptions 
● Mobility of carriers is infinite 
● All absorbed photons promote electrons 
● Only one interface absorbs/emits – other side 
contacted to a “perfect reflector”
L3 
Detailed Balance 
In equillibrium (i.e. in the dark) 
ambient photon flux (thermal photons) 
ba(E) 
hypothetical solar 
absorbing material 
perfect reflector 
Ambient emits like black-body 
ba= 
2Fa 
h3c2 ( E2 
eE/ kB T a−1 ) 
Fa=π
L3 
Detailed Balance 
In equillibrium (i.e. in the dark) 
ambient photon flux (thermal photons) 
ba(E) 
Ambient emits like black-body 
ba= 
2Fa 
h3c2 ( E2 
eE/ kB T a−1 ) 
Fa=π 
Reflectance Absorbance 
jab s=q(1−R(E))a(E)ba(E) 
Absorbed ambient results in an 
equivalent current density
L3 
Detailed Balance 
In equillibrium (i.e. in the dark) 
ambient photon flux (thermal photons) 
ba(E) 
emitted photon flux 
Device emits like black-body too! 
Can think of as current in opposite direction to jabs 
Reflectance Emissivity 
jrad=−q (1−R(E))ε (E)ba (E)
L3 
Detailed Balance 
In equillibrium (i.e. in the dark) 
jab s+ jrad=0 a(E)=ε(E) 
spontaneous 
absorption emission 
hν hν 
Absorption Rate = Spontaneous Emission Rate
L3 
Detailed Balance 
Under Illumination (still steady state) 
emitted photon flux 
ambient photon flux (thermal photons) 
ba(E) 
bs(E) 
jab s> jrad 
bs= 
θ 
2 Fs 
h3 c2 ( E2 
e E/k BT s−1 ) Fs=π sin2θ 
But does emitted flux change? - YOU BETCHA! 
Why? (if emitted flux remained the same as under thermal 
equilibrium conditions then you could have a solar cell 
with 100% efficiency)
L3 
Detailed Balance 
Under illumination part of the electron population has raised 
electrochemical potential energy – i.e. Δμ > 0 
This means that spontaneous emission is increased! 
The emitted flux is increased by: 
h3 c2 ( E2 
bes= 2π 
e(E−Δμ)/ kB Ta−1 ) 
This is the reason why absorbed solar radiant energy can never be fully utilised 
in a solar cell. 
RADIATIVE RECOMBINATION 
Max efficiency ~ 86% 
This is all a bit abstract – I hope this will become more obvious when we talk about 
junctions.
L3 
Two Level System 
thermalisation 
Conduction Band (empty) 
hν = E Eg g 
Valence Band (full) 
hν > Eg 
spontaneous 
emission 
What sort of materials do we use for solar cells? 
Semiconductors 
Why? 
Because they have a band gap! 
No longer a perfect system because of: 
THERMALISATION
L3 
Key Point 
THERMALISATION: 
Photons with E > Eg promote carriers that relax to 
bottom of conduction band through scattering 
interactions with phonons (transfer of kinetic 
energy – heat!) 
Absorbed photon with E > Eg achieves the same 
result as E = Eg 
Thermalisation is the most dominant loss 
mechanism that limits the efficiency
L3 
Photocurrent 
Photo-current is due to the net absorbed flux due to the sun. 
Can calculate by integrating jabs over all photon energies: 
∞ 
C(E)(1−R( E))a (E)bs(E)dE 
J SC=q∫0 
Probability that promoted carriers are collected to “do work”
L3 
Photocurrent 
Photo-current is due to the net absorbed flux due to the sun. 
Can calculate by integrating jabs over all photon energies: 
∞ 
C(E)(1−R( E))a (E)bs(E)dE 
J SC=q∫0 
Probability that promoted carriers are collected to “do work” 
LOOK FAMILIAR? 
This is the Quantum Efficiency (external)
L3 
Photocurrent 
Photo-current is due to the net absorbed flux due to the sun. 
Can calculate by integrating jabs over all photon energies: 
∞ 
C(E)(1−R( E))a (E)bs(E)dE 
J SC=q∫0 
Probability that promoted carriers are collected to “do work” 
LOOK FAMILIAR? 
This is the Quantum Efficiency (external)
L3 
Photocurrent 
Photo-current is due to the net absorbed flux due to the sun. 
Can calculate by integrating jabs over all photon energies: 
∞ 
C(E)(1−R( E))a (E)bs(E)dE 
J SC=q∫0 
Probability that promoted carriers are collected to “do work” 
LOOK FAMILIAR? 
This is the Quantum Efficiency (external) 
∞ 
QE(E)bs(E)dE 
J SC=q∫0 
Now you know how to calculate JSC from an EQE curve (hint hint)
L3 
Photocurrent 
In a perfect world: 
C(E)=1 
and 
R(E)=0 
therefore 
QE(E)=a(E)={10 
E⩾Eg 
E< Eg 
∞ 
bs(E)dE 
J SC=q∫Eg 
so 
In other words JSC is dependent only on the band gap of the material 
(for a given spectrum)
L3 
Photocurrent 
From last lecture
L3 
VOC 
Is the VOC related to the band gap too? - Heck Yes! 
Remember from diode equation 
VOC= 
nk T 
Bq 
ln(J SC 
J0 
+1) This is much more sensitive 
to Ethan Jis. 
g SC J 0= q 
k B 
15σs 
π4 T3∫u 
∞ x2 
ex−1 
dx 
u= 
EG 
k BT 
where 
http://www.sciencedirect.com/science/article/pii/0927024895800042 
From the detailed 
balance
L3 
VOC 
J0 decreases exponentially with respect to band gap
L3 
VOC 
Therefore: 
VOC increases with Eg
L3 
Limiting Efficiency 
JSC 
VOC
L3 
Limiting Efficiency 
W. Shockley and H. Queisser, Detailed Balance Limit of Efficiency of p-n 
Junction Solar Cells”, JAP, 32(3) 0.510 (1961)
L3 
Requirements for ideal PV devices 
● PV material has energy gap 
● All incident light with E > EG is absorbed 
● 1 photon = 1 electron-hole pair 
● Radiative recombination only (i.e. spontaneous emission) 
● Generated charges are completely separated 
● Charge is transported to external circuit without loss 
J. Nelson, “The Physics of Solar Cells”, pp 35 - 39
L3 
Real World Device Limitations 
● Incomplete absorbtion: C(E) < 1 and R(E) > 0 
● Non-radiative recombination. (L4) 
● Lossless transport? No such thing as perfect conductor. 
C. Li et al., Phys. Rev. Lett. 112, 156103 (2014) 
Electron Beam 
Induced Current 
(EBIC) imaging of 
CdTe/CdS solar cell 
cross section. Grain 
Boundaries = 
Recombination!
Beating the SQ limit 
L3 
● Tandem Cells 
● Multi-junctions 
● Concentrator PV 
● Hot Carrier solar cells 
● Down and up conversion
Beating the SQ limit 
L3
Tandem Cells 
L3 
Why have one junction when you can have two? 
T. Takamoto et. al. “Over 30% Efficient 
InGaP/GaAs tandem solar cells”, APL, 70 381 
(1997) 
GaAs/InGaP
L3 
Tandem Cells 
Detailed balance calculations for two band gap system: 
Maximum theoretical efficiency ~ 46%
L3 
Tandem Cells 
Disadvantages of tandems based on III-V's 
● High precision fabrication required 
● Materials balance (tunnel junction) 
● High cost (materials + deposition) 
● Not practical for concentrator systems 
Are there other strategies?
L3 
Tandem Cells 
Inorganic/Organic Hybrid Tandems 
● Cheap 
● Easy to make (non-vacuum dep) 
● Can apply to existing Si technology 
Watch this space 
c-Si efficiency boosted by 20% (by using perovskites)
L3 
Multi-junctions 
Why have two junctions when you can have three (or more)? 
Ge/InGaAs/InGaP – Max η ~ 35%
L3 
Multi-junctions 
S. P. Bremner et. al. Prog. PV. 16:225-233 (2008)
L3 
Concentrators 
Fresnel Lenses 
200 – 300 suns 
1 axis tracking
L3 
Concentrators 
Parabolic Mirror Array 
~ 500 suns 
25kW output 
2 axis tracking
L3 
Concentrators 
Increase photon flux increase efficiency 
Theoretical prediction for two junction system @ T = 320K
L3 
44.7%! 
● Four junction cell based on III-V 
● Fraunhofer Institute 
Concentrators
L3 
Concentrators 
Disadvantages of concentrator PV 
● Need to deal with high Temperatures 
i.e. cooling required 
● High installation cost 
● Need direct sunlight 
● Don't put one on your roof in UK.
L3 
Hot Carrier Solar Cells 
Can we get the promoted carriers out before they thermalise? 
Use “selective” contacts that allow “hot” carriers to be 
collected before they thermalise (picoseconds!) to 
bottom of C.B. through scattering with phonon modes
L3 
Hot Carrier Solar Cells 
Advantages of Hot Carrier Solar Cells 
● Max efficiency ~63% 
Disadvantages 
● They don't exist! 
● Completely Theoretical to date 
● Lots of computational DFT studies 
● Expect real devices soon!
L3 
Hot Carrier Solar Cells 
WOW! Real hot carrier device demonstrated this 2014 
http://scitation.aip.org/content/aip/journal/apl/104/23/10.1063/1.4883648
L3 
Up and down conversion 
Take Parts of the spectrum that are not used by the device 
and covert to wavelengths/energies that are. How?
L3 
Lecture Summary 
Luminescent Dyes 
Quantum Dots/nanowires 
http://www.nature.com/srep/2013/131007/srep02874/full/srep02874.html 
Aluminium dots on GaAs solar cell 
“Lego Brick” Structure. 
Plasmonic Enhancement
Lecture Summary 
L3 
● Black Body Radiation 
● Detailed Balance 
● The Shockley-Queisser Limit 
● Requirements for real physical systems 
● Exceeding the SQ limit (funky solar)
Key Question 
L3 
Why can't a solar cell have a 
100% efficiency? 
(Or even close to 100%?) 
Can you answer this?

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Lecture 3: Fundamental Limitations of Solar Cells

  • 1. Lecture 3 Fundamental Limitations of Solar Cells R. Treharne Nov 5th 2014
  • 2. Key Question L3 Why can't a solar cell have a 100% efficiency? (Or even close to 100%?) Can you answer this?
  • 3. Lecture Outline L3 ● Black Body Radiation ● Detailed Balance ● The Shockley-Queisser Limit ● Requirements for real physical systems ● Exceeding the SQ limit (funky solar)
  • 4. Black Body Radiation L3 A black body absorbs all radiation regardless of frequency or angle of incidence. A black body in thermal equilibrium emits radiation according to Planck's Law.
  • 5. Planck's Law L3 Photon Flux – Number of photons of energy E per unit area per second h3 c2 ( E2 b(E)= 2F eE/ kB T−1 ) Units – Number of photons of energy E per unit area per second
  • 6. Planck's Law L3 Photon Flux density from a spherical black body h3 c2 ( E2 b(E)= 2F eE/ kB T−1 ) Look familiar? c.f. Ideal diode Units – Number of photons of energy E per unit area per second
  • 7. Planck's Law L3 Photon Flux – Number of photons of energy E per unit area per second h3 c2 ( E2 b(E)= 2F eE/ kB T−1 ) What the heck is this? Units – Number of photons of energy E per unit area per second
  • 8. Planck's Law L3 F=π sin2 θ Geometrical factor A θB B FFA=π A=FB=π sin2(θB) Black body
  • 9. Irradiance L3 Irradiance - Emitted energy flux density L(E)=Eb(E) This is what solar spectrum data is measured in
  • 10. Irradiance L3 Irradiance - Emitted energy flux density L(E)=Eb(E) This is what solar spectrum data is measured in Power Density given by P=∫0 ∞ L( E)dE
  • 11. Irradiance L3 Irradiance - Emitted energy flux density L(E)=Eb(E) This is what solar spectrum data is measured in Power Density given by P=∫0 Stefan-Boltzmann Law ∞ L( E)dE=σsT 4 σS= 2π5 kB 4 15c2 h3 Stefan's constant
  • 12. The Sun (again) L3 The sun is a black body emitter with a temperature of 5760K At its surface, the Power density is: PS = 62 MW m-2 what is the power density of the Sun's emitted radiation at the Earth's surface, PE? PE= FE FS PS ~ 1353 m-2
  • 13. L3 Detailed Balance What are we doing? ● Counting all photons going in ● Counting all photons going out ● Difference must be converted into electrical (electrochemical potential) Key Assumptions ● Mobility of carriers is infinite ● All absorbed photons promote electrons ● Only one interface absorbs/emits – other side contacted to a “perfect reflector”
  • 14. L3 Detailed Balance In equillibrium (i.e. in the dark) ambient photon flux (thermal photons) ba(E) hypothetical solar absorbing material perfect reflector Ambient emits like black-body ba= 2Fa h3c2 ( E2 eE/ kB T a−1 ) Fa=π
  • 15. L3 Detailed Balance In equillibrium (i.e. in the dark) ambient photon flux (thermal photons) ba(E) Ambient emits like black-body ba= 2Fa h3c2 ( E2 eE/ kB T a−1 ) Fa=π Reflectance Absorbance jab s=q(1−R(E))a(E)ba(E) Absorbed ambient results in an equivalent current density
  • 16. L3 Detailed Balance In equillibrium (i.e. in the dark) ambient photon flux (thermal photons) ba(E) emitted photon flux Device emits like black-body too! Can think of as current in opposite direction to jabs Reflectance Emissivity jrad=−q (1−R(E))ε (E)ba (E)
  • 17. L3 Detailed Balance In equillibrium (i.e. in the dark) jab s+ jrad=0 a(E)=ε(E) spontaneous absorption emission hν hν Absorption Rate = Spontaneous Emission Rate
  • 18. L3 Detailed Balance Under Illumination (still steady state) emitted photon flux ambient photon flux (thermal photons) ba(E) bs(E) jab s> jrad bs= θ 2 Fs h3 c2 ( E2 e E/k BT s−1 ) Fs=π sin2θ But does emitted flux change? - YOU BETCHA! Why? (if emitted flux remained the same as under thermal equilibrium conditions then you could have a solar cell with 100% efficiency)
  • 19. L3 Detailed Balance Under illumination part of the electron population has raised electrochemical potential energy – i.e. Δμ > 0 This means that spontaneous emission is increased! The emitted flux is increased by: h3 c2 ( E2 bes= 2π e(E−Δμ)/ kB Ta−1 ) This is the reason why absorbed solar radiant energy can never be fully utilised in a solar cell. RADIATIVE RECOMBINATION Max efficiency ~ 86% This is all a bit abstract – I hope this will become more obvious when we talk about junctions.
  • 20. L3 Two Level System thermalisation Conduction Band (empty) hν = E Eg g Valence Band (full) hν > Eg spontaneous emission What sort of materials do we use for solar cells? Semiconductors Why? Because they have a band gap! No longer a perfect system because of: THERMALISATION
  • 21. L3 Key Point THERMALISATION: Photons with E > Eg promote carriers that relax to bottom of conduction band through scattering interactions with phonons (transfer of kinetic energy – heat!) Absorbed photon with E > Eg achieves the same result as E = Eg Thermalisation is the most dominant loss mechanism that limits the efficiency
  • 22. L3 Photocurrent Photo-current is due to the net absorbed flux due to the sun. Can calculate by integrating jabs over all photon energies: ∞ C(E)(1−R( E))a (E)bs(E)dE J SC=q∫0 Probability that promoted carriers are collected to “do work”
  • 23. L3 Photocurrent Photo-current is due to the net absorbed flux due to the sun. Can calculate by integrating jabs over all photon energies: ∞ C(E)(1−R( E))a (E)bs(E)dE J SC=q∫0 Probability that promoted carriers are collected to “do work” LOOK FAMILIAR? This is the Quantum Efficiency (external)
  • 24. L3 Photocurrent Photo-current is due to the net absorbed flux due to the sun. Can calculate by integrating jabs over all photon energies: ∞ C(E)(1−R( E))a (E)bs(E)dE J SC=q∫0 Probability that promoted carriers are collected to “do work” LOOK FAMILIAR? This is the Quantum Efficiency (external)
  • 25. L3 Photocurrent Photo-current is due to the net absorbed flux due to the sun. Can calculate by integrating jabs over all photon energies: ∞ C(E)(1−R( E))a (E)bs(E)dE J SC=q∫0 Probability that promoted carriers are collected to “do work” LOOK FAMILIAR? This is the Quantum Efficiency (external) ∞ QE(E)bs(E)dE J SC=q∫0 Now you know how to calculate JSC from an EQE curve (hint hint)
  • 26. L3 Photocurrent In a perfect world: C(E)=1 and R(E)=0 therefore QE(E)=a(E)={10 E⩾Eg E< Eg ∞ bs(E)dE J SC=q∫Eg so In other words JSC is dependent only on the band gap of the material (for a given spectrum)
  • 27. L3 Photocurrent From last lecture
  • 28. L3 VOC Is the VOC related to the band gap too? - Heck Yes! Remember from diode equation VOC= nk T Bq ln(J SC J0 +1) This is much more sensitive to Ethan Jis. g SC J 0= q k B 15σs π4 T3∫u ∞ x2 ex−1 dx u= EG k BT where http://www.sciencedirect.com/science/article/pii/0927024895800042 From the detailed balance
  • 29. L3 VOC J0 decreases exponentially with respect to band gap
  • 30. L3 VOC Therefore: VOC increases with Eg
  • 32. L3 Limiting Efficiency W. Shockley and H. Queisser, Detailed Balance Limit of Efficiency of p-n Junction Solar Cells”, JAP, 32(3) 0.510 (1961)
  • 33. L3 Requirements for ideal PV devices ● PV material has energy gap ● All incident light with E > EG is absorbed ● 1 photon = 1 electron-hole pair ● Radiative recombination only (i.e. spontaneous emission) ● Generated charges are completely separated ● Charge is transported to external circuit without loss J. Nelson, “The Physics of Solar Cells”, pp 35 - 39
  • 34. L3 Real World Device Limitations ● Incomplete absorbtion: C(E) < 1 and R(E) > 0 ● Non-radiative recombination. (L4) ● Lossless transport? No such thing as perfect conductor. C. Li et al., Phys. Rev. Lett. 112, 156103 (2014) Electron Beam Induced Current (EBIC) imaging of CdTe/CdS solar cell cross section. Grain Boundaries = Recombination!
  • 35. Beating the SQ limit L3 ● Tandem Cells ● Multi-junctions ● Concentrator PV ● Hot Carrier solar cells ● Down and up conversion
  • 36. Beating the SQ limit L3
  • 37. Tandem Cells L3 Why have one junction when you can have two? T. Takamoto et. al. “Over 30% Efficient InGaP/GaAs tandem solar cells”, APL, 70 381 (1997) GaAs/InGaP
  • 38. L3 Tandem Cells Detailed balance calculations for two band gap system: Maximum theoretical efficiency ~ 46%
  • 39. L3 Tandem Cells Disadvantages of tandems based on III-V's ● High precision fabrication required ● Materials balance (tunnel junction) ● High cost (materials + deposition) ● Not practical for concentrator systems Are there other strategies?
  • 40. L3 Tandem Cells Inorganic/Organic Hybrid Tandems ● Cheap ● Easy to make (non-vacuum dep) ● Can apply to existing Si technology Watch this space c-Si efficiency boosted by 20% (by using perovskites)
  • 41. L3 Multi-junctions Why have two junctions when you can have three (or more)? Ge/InGaAs/InGaP – Max η ~ 35%
  • 42. L3 Multi-junctions S. P. Bremner et. al. Prog. PV. 16:225-233 (2008)
  • 43. L3 Concentrators Fresnel Lenses 200 – 300 suns 1 axis tracking
  • 44. L3 Concentrators Parabolic Mirror Array ~ 500 suns 25kW output 2 axis tracking
  • 45. L3 Concentrators Increase photon flux increase efficiency Theoretical prediction for two junction system @ T = 320K
  • 46. L3 44.7%! ● Four junction cell based on III-V ● Fraunhofer Institute Concentrators
  • 47. L3 Concentrators Disadvantages of concentrator PV ● Need to deal with high Temperatures i.e. cooling required ● High installation cost ● Need direct sunlight ● Don't put one on your roof in UK.
  • 48. L3 Hot Carrier Solar Cells Can we get the promoted carriers out before they thermalise? Use “selective” contacts that allow “hot” carriers to be collected before they thermalise (picoseconds!) to bottom of C.B. through scattering with phonon modes
  • 49. L3 Hot Carrier Solar Cells Advantages of Hot Carrier Solar Cells ● Max efficiency ~63% Disadvantages ● They don't exist! ● Completely Theoretical to date ● Lots of computational DFT studies ● Expect real devices soon!
  • 50. L3 Hot Carrier Solar Cells WOW! Real hot carrier device demonstrated this 2014 http://scitation.aip.org/content/aip/journal/apl/104/23/10.1063/1.4883648
  • 51. L3 Up and down conversion Take Parts of the spectrum that are not used by the device and covert to wavelengths/energies that are. How?
  • 52. L3 Lecture Summary Luminescent Dyes Quantum Dots/nanowires http://www.nature.com/srep/2013/131007/srep02874/full/srep02874.html Aluminium dots on GaAs solar cell “Lego Brick” Structure. Plasmonic Enhancement
  • 53. Lecture Summary L3 ● Black Body Radiation ● Detailed Balance ● The Shockley-Queisser Limit ● Requirements for real physical systems ● Exceeding the SQ limit (funky solar)
  • 54. Key Question L3 Why can't a solar cell have a 100% efficiency? (Or even close to 100%?) Can you answer this?