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 Brief introduction to Merchant’s Circle.
Assumptions for Merchant’s Circle Diagram.
 Construction of Merchant’s Circle.
 Solutions of Merchant’s Circle.

 Advantages of Merchant’s Circle.
 Need for the analysis of cutting forces.
 Limitations of Merchant’s Circle.

 Conclusion
 Merchant’s Circle Diagram is
constructed to ease the analysis of
cutting forces acting during
orthogonal (Two Dimensional)
cutting of work piece.
 Ernst and Merchant do this
scientific analysis for the first time
in 1941 and gives the following
relation in 1944

 It is convenient to determine
various force and angles.
Metal Cutting is the process of removing unwanted material from the workpiece
in the form of chips

 Cutting Edge is normal to tool feed.
 Here only two force components are
considered i.e. cutting force and thrust
force. Hence known as two dimensional
cutting.
 Shear force acts on smaller area.

 Cutting Edge is inclined at an acute
angle to tool feed.
 Here only three force components are
considered i.e. cutting force, radial force
and thrust force. Hence known as three
dimensional cutting.
 Shear force acts on larger area.
 α : Rack angle

Fc: Cutting Force

 λ : Frictional angle

 Fs: Shear Force

 ϕ : Shear angle

 F: Frictional Force

 Ft : Thrust Force

 N: Normal Frictional Force

 Fn: Normal Shear Force

 V: Feed velocity

Back Rake Angle

Side Rake Angle

Fs

Fn

Fc N φ
Ft

λ

V

R
Front View
F

P

N

F

Normal FrictionForce
Normal Shear Force
FrictionalForce
FrictionForce
RAKE ANGLE
Shear Angle
CuttingForce
ThrustAngle
Resisting the alongnormal metal in
Force on angle madebetweenshear
It is force Angle: provided to tool
act acted angle chip theby
at chip is at angle
 Thisis Rake theshear thetheinterface
Backthethe toactsactedbyvelocitythe
ResistanceforcetoolItof the the of
normal force chip. the to and
workpiece face Frictionalalong
workpiece. the of It face ofForce &
resultanttheActsdirectiontoresistshear
cutting tool
plane withthethe normal oftheof the
betweento,ofinterface velocitythe tool
tool
cutting
forming the or the acts the
and is
motion
plane.plane.
Normalof in a by the tool. Normal
Force,
and
travel.provided
measured tool. plane perpendicular
tool.
shear
Reaction. force edge
to the side cuttingincreases as speed
 Cutting
 Side Rake Angle: It is the as rake
increases and decreases angle
-1
 λ = decreases
tan μ
between the face of the tool and
angle
μ: coefficient of friction
measured in a plane perpendicular
to the base
 Tool edge is sharp.
 The work material undergoes deformation across a
thin shear plane.
 There is uniform distribution of normal and shear
stress on shear plane.
The work material is rigid and perfectly plastic.
 The shear angle ϕ adjusts itself to minimum work.
 The friction angle λ remains constant and is
independent of ϕ.
 The chip width remains constant.
 The chip does not flow to side, or there is no side
spread.
Fs
α

Fn
Fc
Ft φ

λ-α

α

R

λ

F
N

V

φ
 Fs , Resistance to shear of the metal in forming the chip. It
acts along the shear plane.

 Fn , ‘Backing up’ force on the chip provided by the
workpiece. Acts normal to the shear plane.
 N, It at the tool chip interface normal to the cutting face of
the tool and is provided by the tool.
 F, It is the frictional resistance of the tool acting on the chip.
It acts downward against the motion of the chip as it glides
upwards along the tool face.
Knowing Fc , Ft , α and ϕ, all other component forces
can be calculated as:

The coefficient of friction will be then given as :

Fs
α

Fn
On Shear plane,

Fc
Ft φ
λ

Now,

λ-α

α

R
F
N

V

φ
Let ϕ be the shear angle

Where,

Fs

Now shear plane angle

α

Fn
Fc
The average stresses on the
shear plane area are:

Ft

φ

λ-α

α

R
λ

F
N

V

φ
Now the shear force can be written as:
Fs

and

α

Fn
Fc
Ft

φ

λ

Assuming that λ is independent of ϕ ,
for max. shear stress

λ-α

α

R
F
N

V

φ
Analysis of cutting forces is helpful as:-

 Design of stiffness etc. for the machine tolerance.
Whether work piece can withstand the cutting force
can be predicted.
 In study of behavior and machinability
characterization of the work piece.
 Estimation of cutting power consumption, which
also enables selection of the power source(s) during
design of the machine tool.
 Condition monitoring of the cutting tools and
machine tool.
Proper use of MCD enables the followings :-

 Easy, quick and reasonably accurate determination
of several other forces from a few forces involved in
machining.
 Friction at chip-tool interface and dynamic yield
shear strength can be easily determined.
 Equations relating the different forces are easily
developed.
Some limitations of use of MCD are :-

 Merchant’s Circle Diagram (MCD) is valid only for
orthogonal cutting.
 By the ratio, F/N, the MCD gives apparent (not
actual) coefficient of friction.
 It is based on single shear plane theory.
Following conclusions/results are drawn from MCD :-

 Shear angle is given by

 For practical purpose, the following values of ϕ has
been suggested:
ϕ = α for α>15o
ϕ = 15o for α<15o
Merchant's circle

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Merchant's circle

  • 1.
  • 2.  Brief introduction to Merchant’s Circle. Assumptions for Merchant’s Circle Diagram.  Construction of Merchant’s Circle.  Solutions of Merchant’s Circle.  Advantages of Merchant’s Circle.  Need for the analysis of cutting forces.  Limitations of Merchant’s Circle.  Conclusion
  • 3.  Merchant’s Circle Diagram is constructed to ease the analysis of cutting forces acting during orthogonal (Two Dimensional) cutting of work piece.  Ernst and Merchant do this scientific analysis for the first time in 1941 and gives the following relation in 1944  It is convenient to determine various force and angles.
  • 4. Metal Cutting is the process of removing unwanted material from the workpiece in the form of chips  Cutting Edge is normal to tool feed.  Here only two force components are considered i.e. cutting force and thrust force. Hence known as two dimensional cutting.  Shear force acts on smaller area.  Cutting Edge is inclined at an acute angle to tool feed.  Here only three force components are considered i.e. cutting force, radial force and thrust force. Hence known as three dimensional cutting.  Shear force acts on larger area.
  • 5.  α : Rack angle Fc: Cutting Force  λ : Frictional angle  Fs: Shear Force  ϕ : Shear angle  F: Frictional Force  Ft : Thrust Force  N: Normal Frictional Force  Fn: Normal Shear Force  V: Feed velocity Back Rake Angle Side Rake Angle Fs Fn Fc N φ Ft λ V R Front View F P N F Normal FrictionForce Normal Shear Force FrictionalForce FrictionForce RAKE ANGLE Shear Angle CuttingForce ThrustAngle Resisting the alongnormal metal in Force on angle madebetweenshear It is force Angle: provided to tool act acted angle chip theby at chip is at angle  Thisis Rake theshear thetheinterface Backthethe toactsactedbyvelocitythe ResistanceforcetoolItof the the of normal force chip. the to and workpiece face Frictionalalong workpiece. the of It face ofForce & resultanttheActsdirectiontoresistshear cutting tool plane withthethe normal oftheof the betweento,ofinterface velocitythe tool tool cutting forming the or the acts the and is motion plane.plane. Normalof in a by the tool. Normal Force, and travel.provided measured tool. plane perpendicular tool. shear Reaction. force edge to the side cuttingincreases as speed  Cutting  Side Rake Angle: It is the as rake increases and decreases angle -1  λ = decreases tan μ between the face of the tool and angle μ: coefficient of friction measured in a plane perpendicular to the base
  • 6.  Tool edge is sharp.  The work material undergoes deformation across a thin shear plane.  There is uniform distribution of normal and shear stress on shear plane. The work material is rigid and perfectly plastic.  The shear angle ϕ adjusts itself to minimum work.  The friction angle λ remains constant and is independent of ϕ.  The chip width remains constant.  The chip does not flow to side, or there is no side spread.
  • 8.  Fs , Resistance to shear of the metal in forming the chip. It acts along the shear plane.  Fn , ‘Backing up’ force on the chip provided by the workpiece. Acts normal to the shear plane.  N, It at the tool chip interface normal to the cutting face of the tool and is provided by the tool.  F, It is the frictional resistance of the tool acting on the chip. It acts downward against the motion of the chip as it glides upwards along the tool face.
  • 9. Knowing Fc , Ft , α and ϕ, all other component forces can be calculated as: The coefficient of friction will be then given as : Fs α Fn On Shear plane, Fc Ft φ λ Now, λ-α α R F N V φ
  • 10. Let ϕ be the shear angle Where, Fs Now shear plane angle α Fn Fc The average stresses on the shear plane area are: Ft φ λ-α α R λ F N V φ
  • 11. Now the shear force can be written as: Fs and α Fn Fc Ft φ λ Assuming that λ is independent of ϕ , for max. shear stress λ-α α R F N V φ
  • 12. Analysis of cutting forces is helpful as:-  Design of stiffness etc. for the machine tolerance. Whether work piece can withstand the cutting force can be predicted.  In study of behavior and machinability characterization of the work piece.  Estimation of cutting power consumption, which also enables selection of the power source(s) during design of the machine tool.  Condition monitoring of the cutting tools and machine tool.
  • 13. Proper use of MCD enables the followings :-  Easy, quick and reasonably accurate determination of several other forces from a few forces involved in machining.  Friction at chip-tool interface and dynamic yield shear strength can be easily determined.  Equations relating the different forces are easily developed.
  • 14. Some limitations of use of MCD are :-  Merchant’s Circle Diagram (MCD) is valid only for orthogonal cutting.  By the ratio, F/N, the MCD gives apparent (not actual) coefficient of friction.  It is based on single shear plane theory.
  • 15. Following conclusions/results are drawn from MCD :-  Shear angle is given by  For practical purpose, the following values of ϕ has been suggested: ϕ = α for α>15o ϕ = 15o for α<15o