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‫ﻣﺎدة‬                    ‫ﻣﺆﺳﺴﺔ ﺑﻴﺘﺎﻏﻮر اﻟﺨﺼﻮﺹﻴﺔ / اﻟﻤﺤﻤﺪﻳﺔ‬                               ‫اﻟﻤﻮﺣــﺪ‬
    ‫اﻟﺮﻳﺎﺿﻴﺎت‬                                                                                 ‫اﻟﻤﺤــﻠﻲ‬
      ‫‪3AC‬‬                                                                                      ‫6002‬

                             ‫أﻧﺠﺰﻩ و أرﺳﻠﻪ اﻷﺳﺘﺎذان : ﻣﺤﻤﺪ ﺣﺒﻴﺐ اﷲ و ﻟﻄﻴﻔﺔ اﻟﻮهﺮاﻧﻲ‬


                                                                                                ‫ﺗﻤﺮﻳﻦ 1‬
                                                                  ‫1( – أﺣﺴﺐ ﻣﺎ ﻳﻠﻲ :‬
                                                       ‫7−‬          ‫9‬
                   ‫7 5 2−‬                     ‫⎞2 ⎛‬           ‫⎞2 ⎛‬                         ‫5‬
                ‫=‪A‬‬   ‫× +‬              ‫;;‬   ‫⎜= ‪B‬‬   ‫⎟‬         ‫⎜×‬   ‫⎟‬      ‫;;‬   ‫× 53 = ‪C‬‬
                   ‫6 7 3‬                      ‫⎠ 3 ⎝‬          ‫⎠ 3 ⎝‬                        ‫7‬
                                                     ‫2( – ﺑﺴﻂ ﻣﺎ ﻳﻠﻲ :‬
                                                     ‫‪a +a‬‬
                       ‫= ‪D = 2 63 + 2 7 − 175 ;; F‬‬              ‫) 0>‪( a‬‬
                                                    ‫‪a+ a‬‬
                ‫3( – ﻧﻌﺘﺒﺮ اﻟﻌﺪدﻳﻦ ‪ a‬و ‪ b‬ﺑﺤﻴﺚ : 2 + 3 = ‪ a‬و 6 + 1 = ‪. b‬‬
                                  ‫ا ( -- أﻧﺸﺮ و ﺑﺴﻂ ﻣﺎ ﻳﻠﻲ : 2 ‪ a‬و 2 ‪. b‬‬
                             ‫ب ( -- ﻗﺎرن اﻟﻌﺪدﻳﻦ اﻵﺕﻴﻴﻦ : 3 4 و 6 2 .‬
                               ‫ج ( -- اﺳﺘﻨﺘﺞ ﻣﻘﺎرﻧﺔ اﻟﻌﺪدﻳﻦ : ‪ a‬و ‪. b‬‬
                                       ‫3‬
                                             ‫4( – اﺣﺬف اﻟﺠﺬر اﻟﻤﺮﺑﻊ ﻣﻦ ﻣﻘﺎم ﻣﺎ ﻳﻠﻲ :‬
                                     ‫1− 3‬
                                                                                                ‫ﺗﻤﺮﻳﻦ 2‬
                                     ‫ﻧﻌﺘﺒﺮ اﻟﺘﻌﺒﻴﺮ : 2)5 − ‪. E = (3x − 5)(x + 2) − (3x‬‬
                                                         ‫1( – أﻧﺸﺮ ﺙﻢ ﺑﺴﻂ اﻟﺘﻌﺒﻴﺮ ‪. E‬‬
                                            ‫2( – ﺑﻴﻦ أن : )2 + ‪. E = (3x − 5)(−x‬‬
                                                   ‫3( – اﺳﺘﻨﺘﺞ ﺣﻞ اﻟﻤﻌﺎدﻟﺔ : 0 = ‪. E‬‬
                                                                                                ‫ﺗﻤﺮﻳﻦ 3‬
                                  ‫1( – إذا ﻋﻠﻤﺖ أن : 3 ≤ 5 ≤ 2 و 4 ≤ 11 ≤ 3 .‬
                                ‫5‬
                         ‫.‬        ‫و‬        ‫و 11 − 5‬         ‫ﻓﺄﻃﺮ : 11 + 5‬
                               ‫11‬
                                                                       ‫2( – ﺣﻞ ﻣﺎ ﻳﻠﻲ :‬
     ‫3 + ‪7x‬‬
    ‫.‬         ‫ج ( -- ‪< x‬‬    ‫ب ( -- 2 − ‪2(x − 3) ≤ 7x‬‬          ‫أ ( -- ‪7x − 20 = 5x‬‬
        ‫5‬
    ‫3( – ‪ ABC‬ﻣﺜﻠﺚ ﺑﺤﻴﺚ : ‪ AB = 4cm‬و ‪ AC = 5cm‬و ‪ BC = 6cm‬و ] ‪M ∈ [ AB‬‬
      ‫و ‪ . M C = y‬إذا ﻋﻠﻤﺖ أن ﻟﻠﻤﺜﻠﺜﻴﻦ ﻧﻔﺲ اﻟﻤﺤﻴﻂ ﻓﻘﺎرن : ‪ x‬و ‪. y‬‬
                                                                                                ‫ﺗﻤﺮﻳﻦ 4‬
‫‪ EFG‬ﻣﺜﻠﺚ ﻣﺘﺴﺎوي اﻟﺴﺎﻗﻴﻦ رأﺳﻪ ‪ E‬ﺑﺤﻴﺚ : ‪ EG = 6cm‬و ‪ FG = 8cm‬و ‪ I‬ﻣﻨﺘﺼﻒ ]‪[FG‬‬

  ‫ﻟﺘﻜﻦ ‪ M‬ﻧﻘﻄﺔ ﻣﻦ ]‪ [EG‬ﺑﺤﻴﺚ : ‪ EM = 1,8cm‬و ‪ N‬ﻧﻘﻄﺔ ﻣﻦ ]‪ [FG‬ﺑﺤﻴﺚ : ‪ FN = 2,4cm‬و ‪K‬‬
                                                               ‫ﻧﻘﻄﺔ ﺕﻘﺎﻃﻊ ]‪ [EI‬و ]‪. [MN‬‬
                                                              ‫1( – أﻧﺠﺰ اﻟﺸﻜــــﻞ.‬
                                          ‫2( -- أ ( -- ﺑﻴﻦ أن : )‪. (MN) // (EF‬‬
                                          ‫ب( -- أﺣﺴﺐ : ‪ KN‬و ‪. KM‬‬
‫‪gsm :063.15.37.85 / www.anissmaths.ift.cx‬‬    ‫ﻣﻮﻗﻊ اﻟﺮﻳﺎﺿﻴﺎت ﺑﺎﻟﺜﺎﻧﻮي اﻹﻋﺪادي ﻟﻸﺳﺘﺎذ : اﻟﻤﻬﺪي ﻋﻨﻴﺲ /‬
‫ﺗﻤﺮﻳﻦ 5‬

      ‫31 2 = ‪. BC‬‬        ‫‪ AC = 6cm‬و‬          ‫‪ ABC _ I‬ﻣﺜﻠﺚ ﺑﺤﻴﺚ : ‪ AB = 4cm‬و‬
                                             ‫1( – ﺑﻴﻦ أن اﻟﻤﺜﻠﺚ ‪ ABC‬ﻗﺎﺋﻢ اﻟﺰاوﻳﺔ.‬
                                                    ‫2( – ﻟﺘﻜﻦ ‪ M‬ﻣﻨﺘﺼﻒ ]‪. [AC‬‬
                                                         ‫أ( -- أﻧﺠﺰ اﻟﺸﻜﻞ.‬
                                        ‫ب( -- ﺕﺤﻘﻖ أن : .‪. BM = 5cm‬‬
                               ‫‪. cos AB‬‬ ‫‪ˆM‬‬                    ‫ˆ‬
                                                  ‫3( – أﺣﺴﺐ : ‪ sin ABM‬و‬
                      ‫4( – ﻟﺘﻜﻦ ‪ H‬اﻟﻤﺴﻘﻂ اﻟﻌﻤﻮدي ﻟﻠﻨﻘﻄﺔ ‪ C‬ﻋﻠﻰ اﻟﻤﺴﺘﻘﻴﻢ )‪. (BM‬‬
                                           ‫ˆ‬         ‫ˆ‬
                                      ‫أ ( -- ﺑﻴﻦ أن : ‪. ABM = MCH‬‬
                                                  ‫‪MH‬‬
                                                ‫.‬            ‫ب ( -- أﺣﺴﺐ :‬
                                                   ‫‪CH‬‬
                                                          ‫1‬
                          ‫= °05 ‪. tg 40° + tg‬‬                               ‫‪ _ II‬ﺑﻴﻦ أن :‬
                                               ‫°04 ‪cos 40° × sin‬‬




‫/ 58.73.51.360: ‪gsm‬‬   ‫‪www.anissmaths.ift.cx‬‬     ‫ﻣﻮﻗﻊ اﻟﺮﻳﺎﺿﻴﺎت ﺑﺎﻟﺜﺎﻧﻮي اﻹﻋﺪادي ﻟﻸﺳﺘﺎذ : اﻟﻤﻬﺪي ﻋﻨﻴﺲ /‬

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01

  • 1. ‫ﻣﺎدة‬ ‫ﻣﺆﺳﺴﺔ ﺑﻴﺘﺎﻏﻮر اﻟﺨﺼﻮﺹﻴﺔ / اﻟﻤﺤﻤﺪﻳﺔ‬ ‫اﻟﻤﻮﺣــﺪ‬ ‫اﻟﺮﻳﺎﺿﻴﺎت‬ ‫اﻟﻤﺤــﻠﻲ‬ ‫‪3AC‬‬ ‫6002‬ ‫أﻧﺠﺰﻩ و أرﺳﻠﻪ اﻷﺳﺘﺎذان : ﻣﺤﻤﺪ ﺣﺒﻴﺐ اﷲ و ﻟﻄﻴﻔﺔ اﻟﻮهﺮاﻧﻲ‬ ‫ﺗﻤﺮﻳﻦ 1‬ ‫1( – أﺣﺴﺐ ﻣﺎ ﻳﻠﻲ :‬ ‫7−‬ ‫9‬ ‫7 5 2−‬ ‫⎞2 ⎛‬ ‫⎞2 ⎛‬ ‫5‬ ‫=‪A‬‬ ‫× +‬ ‫;;‬ ‫⎜= ‪B‬‬ ‫⎟‬ ‫⎜×‬ ‫⎟‬ ‫;;‬ ‫× 53 = ‪C‬‬ ‫6 7 3‬ ‫⎠ 3 ⎝‬ ‫⎠ 3 ⎝‬ ‫7‬ ‫2( – ﺑﺴﻂ ﻣﺎ ﻳﻠﻲ :‬ ‫‪a +a‬‬ ‫= ‪D = 2 63 + 2 7 − 175 ;; F‬‬ ‫) 0>‪( a‬‬ ‫‪a+ a‬‬ ‫3( – ﻧﻌﺘﺒﺮ اﻟﻌﺪدﻳﻦ ‪ a‬و ‪ b‬ﺑﺤﻴﺚ : 2 + 3 = ‪ a‬و 6 + 1 = ‪. b‬‬ ‫ا ( -- أﻧﺸﺮ و ﺑﺴﻂ ﻣﺎ ﻳﻠﻲ : 2 ‪ a‬و 2 ‪. b‬‬ ‫ب ( -- ﻗﺎرن اﻟﻌﺪدﻳﻦ اﻵﺕﻴﻴﻦ : 3 4 و 6 2 .‬ ‫ج ( -- اﺳﺘﻨﺘﺞ ﻣﻘﺎرﻧﺔ اﻟﻌﺪدﻳﻦ : ‪ a‬و ‪. b‬‬ ‫3‬ ‫4( – اﺣﺬف اﻟﺠﺬر اﻟﻤﺮﺑﻊ ﻣﻦ ﻣﻘﺎم ﻣﺎ ﻳﻠﻲ :‬ ‫1− 3‬ ‫ﺗﻤﺮﻳﻦ 2‬ ‫ﻧﻌﺘﺒﺮ اﻟﺘﻌﺒﻴﺮ : 2)5 − ‪. E = (3x − 5)(x + 2) − (3x‬‬ ‫1( – أﻧﺸﺮ ﺙﻢ ﺑﺴﻂ اﻟﺘﻌﺒﻴﺮ ‪. E‬‬ ‫2( – ﺑﻴﻦ أن : )2 + ‪. E = (3x − 5)(−x‬‬ ‫3( – اﺳﺘﻨﺘﺞ ﺣﻞ اﻟﻤﻌﺎدﻟﺔ : 0 = ‪. E‬‬ ‫ﺗﻤﺮﻳﻦ 3‬ ‫1( – إذا ﻋﻠﻤﺖ أن : 3 ≤ 5 ≤ 2 و 4 ≤ 11 ≤ 3 .‬ ‫5‬ ‫.‬ ‫و‬ ‫و 11 − 5‬ ‫ﻓﺄﻃﺮ : 11 + 5‬ ‫11‬ ‫2( – ﺣﻞ ﻣﺎ ﻳﻠﻲ :‬ ‫3 + ‪7x‬‬ ‫.‬ ‫ج ( -- ‪< x‬‬ ‫ب ( -- 2 − ‪2(x − 3) ≤ 7x‬‬ ‫أ ( -- ‪7x − 20 = 5x‬‬ ‫5‬ ‫3( – ‪ ABC‬ﻣﺜﻠﺚ ﺑﺤﻴﺚ : ‪ AB = 4cm‬و ‪ AC = 5cm‬و ‪ BC = 6cm‬و ] ‪M ∈ [ AB‬‬ ‫و ‪ . M C = y‬إذا ﻋﻠﻤﺖ أن ﻟﻠﻤﺜﻠﺜﻴﻦ ﻧﻔﺲ اﻟﻤﺤﻴﻂ ﻓﻘﺎرن : ‪ x‬و ‪. y‬‬ ‫ﺗﻤﺮﻳﻦ 4‬ ‫‪ EFG‬ﻣﺜﻠﺚ ﻣﺘﺴﺎوي اﻟﺴﺎﻗﻴﻦ رأﺳﻪ ‪ E‬ﺑﺤﻴﺚ : ‪ EG = 6cm‬و ‪ FG = 8cm‬و ‪ I‬ﻣﻨﺘﺼﻒ ]‪[FG‬‬ ‫ﻟﺘﻜﻦ ‪ M‬ﻧﻘﻄﺔ ﻣﻦ ]‪ [EG‬ﺑﺤﻴﺚ : ‪ EM = 1,8cm‬و ‪ N‬ﻧﻘﻄﺔ ﻣﻦ ]‪ [FG‬ﺑﺤﻴﺚ : ‪ FN = 2,4cm‬و ‪K‬‬ ‫ﻧﻘﻄﺔ ﺕﻘﺎﻃﻊ ]‪ [EI‬و ]‪. [MN‬‬ ‫1( – أﻧﺠﺰ اﻟﺸﻜــــﻞ.‬ ‫2( -- أ ( -- ﺑﻴﻦ أن : )‪. (MN) // (EF‬‬ ‫ب( -- أﺣﺴﺐ : ‪ KN‬و ‪. KM‬‬ ‫‪gsm :063.15.37.85 / www.anissmaths.ift.cx‬‬ ‫ﻣﻮﻗﻊ اﻟﺮﻳﺎﺿﻴﺎت ﺑﺎﻟﺜﺎﻧﻮي اﻹﻋﺪادي ﻟﻸﺳﺘﺎذ : اﻟﻤﻬﺪي ﻋﻨﻴﺲ /‬
  • 2. ‫ﺗﻤﺮﻳﻦ 5‬ ‫31 2 = ‪. BC‬‬ ‫‪ AC = 6cm‬و‬ ‫‪ ABC _ I‬ﻣﺜﻠﺚ ﺑﺤﻴﺚ : ‪ AB = 4cm‬و‬ ‫1( – ﺑﻴﻦ أن اﻟﻤﺜﻠﺚ ‪ ABC‬ﻗﺎﺋﻢ اﻟﺰاوﻳﺔ.‬ ‫2( – ﻟﺘﻜﻦ ‪ M‬ﻣﻨﺘﺼﻒ ]‪. [AC‬‬ ‫أ( -- أﻧﺠﺰ اﻟﺸﻜﻞ.‬ ‫ب( -- ﺕﺤﻘﻖ أن : .‪. BM = 5cm‬‬ ‫‪. cos AB‬‬ ‫‪ˆM‬‬ ‫ˆ‬ ‫3( – أﺣﺴﺐ : ‪ sin ABM‬و‬ ‫4( – ﻟﺘﻜﻦ ‪ H‬اﻟﻤﺴﻘﻂ اﻟﻌﻤﻮدي ﻟﻠﻨﻘﻄﺔ ‪ C‬ﻋﻠﻰ اﻟﻤﺴﺘﻘﻴﻢ )‪. (BM‬‬ ‫ˆ‬ ‫ˆ‬ ‫أ ( -- ﺑﻴﻦ أن : ‪. ABM = MCH‬‬ ‫‪MH‬‬ ‫.‬ ‫ب ( -- أﺣﺴﺐ :‬ ‫‪CH‬‬ ‫1‬ ‫= °05 ‪. tg 40° + tg‬‬ ‫‪ _ II‬ﺑﻴﻦ أن :‬ ‫°04 ‪cos 40° × sin‬‬ ‫/ 58.73.51.360: ‪gsm‬‬ ‫‪www.anissmaths.ift.cx‬‬ ‫ﻣﻮﻗﻊ اﻟﺮﻳﺎﺿﻴﺎت ﺑﺎﻟﺜﺎﻧﻮي اﻹﻋﺪادي ﻟﻸﺳﺘﺎذ : اﻟﻤﻬﺪي ﻋﻨﻴﺲ /‬