A detailed step-by-step procedure for the design of a buck converter. Different active and passive components are selected as per the requirement specified in the design problem.
9. WAVEFORMS
9Design of Buck converter
Fig.3: Simulation results of designed buck converter
Simulation Results:
ΔIL =2.3-1.7 =0.6A
ΔVo=5.007-4.997=10mV
10. Output power, Pout = V # I = 5 * 2 = 10W
Capacitor loss = 0.01W (from ESR)
MOSFET loss = 0.3W (from RDSon)
Diodeloss = 0.47W (fromVDon)
Inductor loss = 0.15W (coreloss)
` Total loss = 0.93W
Efficiency =
Pout + losses
Pout =
10 + 0.93
10
= 91.5%
Diodelossrepresentsone- half of thetotal losses.
10Design of Buck converter
11. [1] Ned Mohan, Undeland and Robbin, ‘Power Electronics: Converters,
Application and Design’, John Wiley and sons Inc., Newyork,2006.
[2] Rashid M.H., ‘Power Electronics- Circuits, Device and Applications’,
Prentice Hall India, New Delhi, 2009.
[3] Datasheets
1N5820 http://www.farnell.com/datasheets/107972.pdf
IRFZ14 http://www.irf.com/product-info/datasheets/data/irfz14.pdf
Capacitor http://www.farnell.com/datasheets/1558295.pdf
11Design of Buck converter