2. Objectives: Define stoichiometry. Describe the importance of the mole ratio in stoichiometric calculations. Write a mole ratio relating two substances in a chemical equation.
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4. Involves the mass relationships between reactants and products in a chemical reaction.
11. Molar Mass Mass per mole (g/mol) Determine molar masses using the periodic table Composition stoichiometry Al Example: Al2O3 Al 1 x 26.98 = 26.98 g/mol Al 2 x 26.98 = 59.96 g O3 x 16.00 = 48.00 g 101.96 g/mol O2 O 2 x 16.00 = 32.00 g/mol Given Moles of one: can find the mass of that compound. Possible molar mass ratios 1 mol Al2O3 101.96 g Al2O3 101.96 g Al2O3 OR 10.0 mol Al2O3 x 1 mol Al2O3 101.96 g Al2O3 1 mol Al2O3 = 1020 g Al2O3 26.98 g Al 1 mol Al 1 mol Al OR 1 mol Al x 26.98 g Al 55.0 g Al 26.98 g Al 32.00 g O2 1 mol O2 = 2.04 mol Al OR 1 mol O2 32.00 g O2