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6.7 Graph and Solving Quadratic Inequalities
Method of Graph sketching
Forms of Quadratic Inequalities y<ax 2 +bx+c y>ax 2 +bx+c y ≤ax 2 +bx+c y≥ax 2 +bx+c ,[object Object],[object Object]
Steps for graphing ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Example: Graph y  ≤ x 2 +6x- 4 *  Vertex: (-3,-13) *  Opens up, solid line ,[object Object],[object Object],[object Object],So, shade where the point is NOT! Test point
Graph:  y>-x 2 +4x-3 ,[object Object],[object Object],*  Test point (0,0) 0>-0 2 +4(0)-3 0>-3 ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Test Point
Last Example!  Sketch the intersection of the given inequalities. 1  y ≥x 2   and  2  y≤-x 2 +2x+4 ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],SOLUTION!
Solving Quadratic Inequalities
Solve the quadratic inequality  x 2  – 5 x  + 6 > 0 graphically. Example 1:
Procedures:   Step (2):   we  have  y  = ( x  – 2)( x –  3) , i.e.  y  = 0, when  x  = 2 or  x  = 3. Factorize  x 2  – 5 x  + 6, The corresponding quadratic function is    y  =  x 2  – 5 x  + 6 Sketch the graph of  y  =  x 2  – 5 x  + 6. Step (1): Step (3): Step (4): Find the solution from the graph.
Sketch the graph  y =   x 2  – 5 x  + 6 . What is the solution of  x 2  – 5 x  + 6 > 0  ?   x y 0 y  = ( x  – 2)( x –  3) ,    y  = 0, when  x  = 2 or  x  = 3.  2 3
x y 0 We need to solve  x  2  – 5 x  + 6 > 0, The  portion  of the graph  above the x-axis  represents  y > 0 (i.e.  x  2  – 5 x  + 6 > 0) The  portion  of the graph  below the x-axis  represents  y < 0 (i.e.  x  2  – 5 x  + 6 < 0) above the x-axis. so we choose the portion 2 3
x y 0 When  x < 2 , the curve is above the x-axis i.e., y  >  0 x 2  – 5x + 6  >  0 When  x > 3 , the curve is above the x-axis i.e., y  >  0 x 2  – 5x + 6  >  0 2 3
From the sketch, we obtain the solution   or
Graphical Solution: 0 2 3
Solve the quadratic inequality  x 2  – 5 x  + 6 < 0 graphically. Example 2: Same method as example 1 !!!
x y 0 When  2 < x < 3 , the curve is below the x-axis i.e., y  <  0 x 2  – 5 x  + 6  <  0 2 3
From the sketch, we obtain the solution   2 <  x  < 3
Graphical Solution: 0 2 3
[object Object],Exercise 1 : x  < –2 or  x  > 1 Answer: Find the x-intercepts of the curve: (x + 2)(x – 1)=0 x = –2 or x = 1 x y 0 0 – 2 1 – 2 1
[object Object],Exercise 2 : – 3 <  x  < 4 Answer: Find the x-intercepts of the curve: x 2  – x – 12 = 0 (x + 3)(x – 4)=0 x = –3 or x = 4 x y 0 0 – 3 4 – 3 4
Solve Exercise 3 : – 7 <  x  < 5 Solution: Find the x-intercepts of the curve: (x + 7)(x – 5)=0 x = –7 or x = 5 x y 0 0 – 7 5 – 7 5
Solve Exercise 4 : Solution: Find the x-intercepts of the curve: (x + 3)(3x – 2)=0 x = –3 or x = 2/3 x     –3 or  x     2/3 x y 0 – 3 2 3 0 – 3 2 3

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6.7 quadratic inequalities

  • 1. 6.7 Graph and Solving Quadratic Inequalities
  • 2. Method of Graph sketching
  • 3.
  • 4.
  • 5.
  • 6.
  • 7.
  • 9. Solve the quadratic inequality x 2 – 5 x + 6 > 0 graphically. Example 1:
  • 10. Procedures: Step (2): we have y = ( x – 2)( x – 3) , i.e. y = 0, when x = 2 or x = 3. Factorize x 2 – 5 x + 6, The corresponding quadratic function is y = x 2 – 5 x + 6 Sketch the graph of y = x 2 – 5 x + 6. Step (1): Step (3): Step (4): Find the solution from the graph.
  • 11. Sketch the graph y = x 2 – 5 x + 6 . What is the solution of x 2 – 5 x + 6 > 0 ? x y 0 y = ( x – 2)( x – 3) ,  y = 0, when x = 2 or x = 3.  2 3
  • 12. x y 0 We need to solve x 2 – 5 x + 6 > 0, The portion of the graph above the x-axis represents y > 0 (i.e. x 2 – 5 x + 6 > 0) The portion of the graph below the x-axis represents y < 0 (i.e. x 2 – 5 x + 6 < 0) above the x-axis. so we choose the portion 2 3
  • 13. x y 0 When x < 2 , the curve is above the x-axis i.e., y > 0 x 2 – 5x + 6 > 0 When x > 3 , the curve is above the x-axis i.e., y > 0 x 2 – 5x + 6 > 0 2 3
  • 14. From the sketch, we obtain the solution or
  • 16. Solve the quadratic inequality x 2 – 5 x + 6 < 0 graphically. Example 2: Same method as example 1 !!!
  • 17. x y 0 When 2 < x < 3 , the curve is below the x-axis i.e., y < 0 x 2 – 5 x + 6 < 0 2 3
  • 18. From the sketch, we obtain the solution 2 < x < 3
  • 20.
  • 21.
  • 22. Solve Exercise 3 : – 7 < x < 5 Solution: Find the x-intercepts of the curve: (x + 7)(x – 5)=0 x = –7 or x = 5 x y 0 0 – 7 5 – 7 5
  • 23. Solve Exercise 4 : Solution: Find the x-intercepts of the curve: (x + 3)(3x – 2)=0 x = –3 or x = 2/3 x  –3 or x  2/3 x y 0 – 3 2 3 0 – 3 2 3