Salient Features of India constitution especially power and functions
3º ESO: ELECTRICITY
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14. 6.2 Electric currents The electric current can be transformed into these energies. Also, you can get the electricity back from these energies, so, it is reversible energy. Calorific energy Light energy Mechanical energy Magnetic energy Electric energy
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51. 6.5 Electric circuit. Symbols Generator Battery Battery association Conductors: When two conductors are crossed without any contact we indicate it with a curve
53. 6.5 Electric circuit. Symbols Protection elements Fuse Receptors: Lamp Resistances: they have two symbols Engines
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65. 6.6 Electric associations Voltage Series Parallel Voltage is distributed between elements, that is the reason why they have less energy for each lamp, so the light is lower. Voltage is the same in all elements, so all the lamps have the same energy and the light is higher.
66. Intensity Series Parallel All the lamps are in line, so they create a high resistance, that is the reason why the intensity is lower but the battery will have a longer life. All lamps are separated so they create a low resistance, that is the reason why the intensity through the lamps is higher, but the battery will have a shorter life
67. CUT Circuit Series Parallel If there is any cut along the conductor, the electric current will not be able to go from the positive to the negative pole. If there is any cut along the conductor, the electric current can go through any other way
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71. 6.7 Electric energy production Alessandro Volta (1777-1851) Mr Michael Faraday had an idea, if a electric current can create an artificial magnet Can a magnet create an artificial electric current?
72. 6.7 Electric energy production Alessandro Volta (1777-1851) YES!!!! So Mr Michael Faraday discovered that we can create electricity with a magnet that is moving near a close circuit
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85. Point out in the table if the engine and lamps works for the following situations A closed B open A open B closed A closed B closed Engine lamp 1 lamp 2
86. Calculate the value of the intensity in these cases: V ( V ) R ( ) I (A) 8 2 7 2 4 8 300 6 21 7 1000000 20
87. 6.4 Ohm’s law Calculations with Ohm’s law 5º Exercise Solution V ( V ) R ( ) I (A) 2 2 2 4
88. 6.4 Ohm’s law Calculations with Ohm’s law Solution V ( V ) R ( ) I (A) 2 4 10 5
89. 6.4 Ohm’s law Calculations with Ohm’s law Solution exercise V ( V ) R ( ) I (A) 5 10 20 1000
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