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R e p u b l i c o f th e P h i l ip p in e s
 Department of Education
Region VII, Central Visayas
 D i v i s i o n o f M an d a u e C i t y




 OHM’S LAW
          Prepared by:

JOEMIL REY BOLAMBAO
           IV – Descartes

   KEVIN JAY MABUTI
           IV – Descartes

         Submitted to:

 MRS. EVELYN LAURON
          Physics Teacher
I.    Title Page
II. Table of Contents
III. Guide Card
IV. Introduction
V.    Activity Card #1
VI. Activity Card #2
VII. Assessment Card #1
VIII. Enrichment Card #1
IX. Enrichment Card #2
X.    Answer Cards
XI. Reference Card
BOOKS

  Giancoli, Douglas C. (1995). Physics: Principles with
  Applications (4th ed ed.). London: Prentice Hall.
  ISBN 0-13-102153-2.


  John O'Malley, Schaum's outline of theory and
  problems of basic circuit analysis, p.19, McGraw-Hill
  Professional, 1992 ISBN 0070478244




INTERNET

  http://en.wikipedia.org/wiki/Ohm’s_Law

  http://www.petsdo.com/blog/Origin_of_Ohm’s_Law

  http://en.wikipedia.org/wiki/Resistivity

  http://www.physicslab.com/Ohms%20%Law
Olah Amigos! Olah Boots! I am
                           SIMDORA, the knowledge explorer. Today, we
                           will be going into another fun and exciting
                           adventure as we journey in the world of science.
                           We will know more about the Ohm’s Law.
What is Ohm’s
Law?




       This Strategic Intervention Material (SIM) is designed to give you a wide
    understanding regarding Ohm’s Law. After going through this SIM, the reader is
    expected to:

           Define and state the Ohm’s Law
           Identify the relationship of Voltage, Current and Resistance
           Solve problems involving the relationship of Voltage, Current and Resistance
           Apply Ohm’s Law in practical situations.

        Now that you know what we will be encountering, here is a short review about the
    topic.
Olah Amigos! I heard the Boots doesn’t exactly know what
                  Ohm’s Law. To know more about it we will be going to the
                  house of Mr. George Simon Ohm. To get there, we must
                  pass the brain maze, down to the Electric Castle and Then
                  to Mr. Ohm’s House. Remember, Maze, Castle, Ohm’s
                  House. Say it with me. Maze, Castle, Ohm’s House.....




Ohm's law states that the current through a conductor between two points is
directly proportional to the potential difference or voltage across the two points, and
inversely proportional to the resistance between them.

The mathematical equation that describes this relationship is:




        where I is the current through the resistance in units of amperes, V is the
        potential difference measured across the resistance in units of volts, and R is
        the resistance of the conductor in units of ohms. More specifically, Ohm's law
        states that the R in this relation is constant, independent of the current.

        The law was named after the German physicist Georg Ohm, who, in a treatise
        published in 1827, described measurements of applied voltage and current
        through simple electrical circuits containing various lengths of wire. He
        presented a slightly more complex equation than the one above to explain
        his experimental results. The above equation is the modern form of Ohm's
        law.
Let’s went to Mr. George Ohm’s House. Where should we go
first? Do you know where should we go first?
The Brain Maze, right. Will you help me cross the brain maze?
Thank you! Now let’s go cross the maze!

Activity 1:         THE BRAIN MAZE
Start

  A
            D                G               H


                C                    I
        B
                     E                   K
                         F                        L
                             J
                                                 End
 These little brain monsters won’t let you pass unless you defeat them by answering their
 questions. Select your answers from the answer pool.

 A. The potential difference measured across the resistance.
 B. Who pioneered the study on the relationship of current, voltage and resistance?
 C. Unit of measurement for current.
 (D)____ states that the current through a (E)____ between two points is (F)____ proportional
 to the (G)_______ difference or voltage across the two points, and (H)_____ proportional to
 the resistance between them.
 I. Unit of measurement for resistance.
 J. The mathematical equation of the relationship of current, voltage and resistance.
 K. A device use to measure current.
 L. It is the measure of how much current can flow through a component.
                              Ohm’s Law
                     Ammeter
                        Ampere      Directly    Voltage        V
                                                          I=
                             George Ohm                        R             Ohm
                                         Potential
                                             Inversely Resistance
                             Conductor
We’ve made it through the brain maze. Now we’re
                            heading towards the castle. My friend told me that
                            the castle’s door will only open if you can close all
                            its windows. Will you help me close the windows?




Activity 2. The Electric Castle’s Entrance

         To open the door of the Castle, we must close all its
windows, but the problem is that every window may only be
closed by the exact current, resistance and voltage of its
circuit. Complete the table below to close the windows and
open the Door of the Castle.



      The castle has 13 windows.

       Window Number               Voltage              Current              Resistance
             1                     15 volts            30 amperes             ___ ohms
             2                     21 volts           ___ amperes                3 ohms
             3                    220 volts            20 amperes             ___ ohms
             4                    ___ volts            30 amperes              15 ohms
             5                    110 volts           ___ amperes              10 ohms
             6                      3 volts            12 amperes             ___ ohms
             7                    ___ volts            50 amperes              25 ohms
             8                     15 volts            30 amperes             ___ ohms
             9                    ___ volts            21 amperes                7 ohms
            10                    120 volts            30 amperes             ___ ohms
            11                      6 volts           ___ amperes              15 ohms
            12                    ___ volts            30 amperes              10 ohms
            13                    ___ volts            30 amperes                5 ohms
Welcome to my Castle!
                           I’ve heard that you gone along an electrifying
                           journey. Let’s see what you have learned. Here
                           are my little playing circuits.


                             My friends will help me in
                             playing with your circuits.

Activity 2. Playing With Circuits
Solve the following circuit problems. Zeus might help you in
your journey.

1. An emf source of 6.0V is connected to a purely resistive
lamp and a current of 2.0 amperes flows. All the wires are
resistance-free. What is the resistance of the lamp?

The current flowing in a circuit containing four resistors
connected in series is I = 1.0 A. The potential drops across the
first, second and third resistors are, respectively: V = 5 V, V = 8
V and V = 7 V. The equivalent resistance of the circuit is R = 30
    . (Hint: Resistors connected in series have the same current flows
through each one.)
2-5. Resistance of each resistor in the circuit R1, R2, R3 & R4
6. Voltage drop on the fourth resistor.
7. Find the total voltage supplied by the battery

8-10. (3 points) In the following schematic diagram, find the
total current, I.
(Hint: Currents through branches of a parallel circuit add to give the
total current and Voltage in each resistor is the same as the total
voltage.)
                                 Very Clever! As a reward, I’ll use my
                                 power to transport you directly inside the
                                 house of Mr. Ohm.
We did it! We made through the house of Mr. Ohms
 but it looks like he is not here so let’s just explores his
 place and learn more about Ohm’s Law.




Ohm's Law defines the relationships between (P) power, (E) voltage, (I) current, and (R)
resistance. One ohm is the resistance value through which one volt will maintain a current
of one ampere.
(I) Current is what flows on a wire or conductor like water flowing down a river. Current
flows from negative to positive on the surface of a conductor. Current is measured in (A)
amperes or amps.
(E) Voltage is the difference in electrical potential between two points in a circuit. It's the
push or pressure behind current flow through a circuit, and is measured in (V) volts.
(R) Resistance determines how much current will flow through a component. Resistors are
used to control voltage and current levels. A very high resistance allows a small amount of
current to flow. A very low resistance allows a large amount of current to flow. Resistance
is measured in ohms.
(P) Power is the amount of current times the voltage level at a given point measured in
wattage or watts.
I am sure that your brain is going short circuit right
now. Let’s relax and look back to the history of Ohm’s
Law.




                              The Origin of Ohm's Law

               Georg Simon Ohm was born in Bavaria in 1789. His father

      taught him philosophy, chemistry, mathematics and physics. In 1806 he became

      a mathematics teacher in Switzerland. In 1811 he received a doctorate from

      Erlangen and became a mathematics lecturer there. In 1817 he took a position as

      professor of mathematics and physics at the Jesuit Gymnasium of Cologne. In

      1820 he learned of Oersted's electromagnetism discovery and began

      experimenting with electricity in the school's physics laboratory where he

      convinced himself of what is now known as Ohm's law. In 1825 he published a

      paper that explains the decrease in electromagnetic force (which is proportional

      to current) around a wire as its length is increased. He published two papers in

      1826 that mathematically describe electrical conduction in circuits. In 1827 he

      published his famous book Die Galvanische Kette, mathematisch bearbeitet,

      which contains what we now know as Ohm's law. His theories were scorned at

      the time and he was forced to resign his teaching position because of them.
(Assessment)

1. An emf source of 6.0V is connected to a purely resistive lamp and a current of 2.0 amperes
flows. All the wires are resistance-free. What is the resistance of the lamp?




The gain of potential energy occurs as a charge passes through the battery, that is, it gains a
potential of   =6.0V. No energy is lost to the wires, since they are assumed to be resistance-
free. By conservation of energy, the potential that was gained (i.e.     =V=6.0V) must be lost in
the resistor. So, by Ohm's Law:
          V=IR
          R=V/I
          R = 3.0

2-7. The current flowing in a circuit containing four resistors connected in series is I = 1.0 A. The
potential drops across the first, second and third resistors are, respectively: V = 5 V, V = 8 V and
V = 7 V.
The equivalent resistance of the circuit is R = 30 .

  2-5. Resistance of each resistor in the circuit R1, R2,
  R3 & R4
  6. Voltage drop on the fourth resistor.
  7. Find the total voltage supplied by the battery




    Hints

         1. How are resistors related when connected in series?
         2. What is true about potential drops of resistors when connected in series?
         3. You will need to use Ohm's Law.
Solution



                                           First, let's label the diagram with the information given
                                           in the question.

                                           There are several ways of solving this problem (see
                                           alternate solutions), but this tutorial will only go through
                                           one of these ways.



Because the resistors are connected in series, then the same current flows through each one.
Using the Ohm's Law, we can find the resistances of the first, second and third resistors.




           Now, using the equivalent resistance, we can find the resistance in the fourth resistor.
           This is a series circuit, so the equivalent resistance is the sum of the individual
           resistances.




           The current flowing through the fourth resistor is also I=1.0A. Using Ohm's Law again,
           we find the voltage across this resistor.




           The total voltage supplied by the battery must equal to the total voltage drop across the
           circuit (this is known as Kirchhoff's Voltage Law). So, we must sum up the voltage drops
           across the resistors.
(8-10) In the following schematic diagram, find the total current, I.




You will need Ohm's Law.
    1. How are resistors related when connected in parallel?
    2. What is the potential drop across each resistor?
    3. How does current behave in parallel branches?
Solution
We know the total potential of this circuit,
          = 12.0 V
So, between points A and B, the potential must drop 12.0V. Also, the potential drop
across branches of a circuit are equal. That is,


We can use Ohm's Law
         V = IR or I = V/R
to find the current across each resistor.




        Recall that the currents through branches of a parallel circuit add to give the
        total current. That is, the total current 'splits up' so that part of the total current
        travels down each branch. Because of conservation of charge, the sum of the
        currents in each branch must equal the amount going into the branch. (This is
        Kirchhoff's Current Law.)

        So, adding up the three currents, we get:




                So, the total current is I = 12.0A.
Activity 2. The Electric Castle’s Entrance

        To open the door of the Castle, we must close all its windows, but the
problem is that every window may only be closed by the exact current, resistance
and voltage of its circuit. Complete the table below to close the windows and open
the Door of the Castle.
 The castle has 13 windows.

  Window Number              Voltage             Current            Resistance
        1                    15 volts           30 amperes            0.5 ohms
        2                    21 volts            7 amperes              3 ohms
        3                   220 volts           20 amperes             11 ohms
        4                   450 volts           30 amperes             15 ohms
        5                   110 volts           11 amperes             10 ohms
        6                     3 volts           12 amperes           0.25 ohms
        7                  6250 volts           50 amperes             25 ohms
        8                    15 volts           30 amperes            0.5 ohms
        9                   147 volts           21 amperes              7 ohms
       10                   120 volts           30 amperes              4 ohms
       11                     6 volts          0.4 amperes             15 ohms
       12                   300 volts           30 amperes             10 ohms
       13                   150 volts           30 amperes              5 ohms


          In completing the table above we use the following formula.

          For Voltage: V = I x R

          For Current: I = V / R

          For Current: R = V / I
Activity 1:         THE BRAIN MAZE
Start

  A
            D                G              H


                C                   I
        B
                     E                  K
                         F                      L
                             J
                                                End

        These little brain monsters won’t let you pass unless you defeat them by answering
        their questions. Select your answers from the answer pool.

        A. Voltage is the potential difference measured across the resistance.
        B. George Simon Ohm pioneered the study on the relationship of current, voltage
        and resistance.
        C. Ampere is a unit of measurement for current.
        (D) Ohm’s Law states that the current through a (E) Conductor between two points is
        (F) Directly proportional to the (G) Potential difference or voltage across the two
        points, and (H) Inversely proportional to the resistance between them.
        I. Ohm is a unit of measurement for resistance.
        J. The mathematical equation of the relationship of current, voltage and resistance is



        K. Ammeter is a device use to measure current.
        L. Resistance is the measure of how much current can flow through a component.

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  • 1. R e p u b l i c o f th e P h i l ip p in e s Department of Education Region VII, Central Visayas D i v i s i o n o f M an d a u e C i t y OHM’S LAW Prepared by: JOEMIL REY BOLAMBAO IV – Descartes KEVIN JAY MABUTI IV – Descartes Submitted to: MRS. EVELYN LAURON Physics Teacher
  • 2. I. Title Page II. Table of Contents III. Guide Card IV. Introduction V. Activity Card #1 VI. Activity Card #2 VII. Assessment Card #1 VIII. Enrichment Card #1 IX. Enrichment Card #2 X. Answer Cards XI. Reference Card
  • 3. BOOKS Giancoli, Douglas C. (1995). Physics: Principles with Applications (4th ed ed.). London: Prentice Hall. ISBN 0-13-102153-2. John O'Malley, Schaum's outline of theory and problems of basic circuit analysis, p.19, McGraw-Hill Professional, 1992 ISBN 0070478244 INTERNET http://en.wikipedia.org/wiki/Ohm’s_Law http://www.petsdo.com/blog/Origin_of_Ohm’s_Law http://en.wikipedia.org/wiki/Resistivity http://www.physicslab.com/Ohms%20%Law
  • 4. Olah Amigos! Olah Boots! I am SIMDORA, the knowledge explorer. Today, we will be going into another fun and exciting adventure as we journey in the world of science. We will know more about the Ohm’s Law. What is Ohm’s Law? This Strategic Intervention Material (SIM) is designed to give you a wide understanding regarding Ohm’s Law. After going through this SIM, the reader is expected to: Define and state the Ohm’s Law Identify the relationship of Voltage, Current and Resistance Solve problems involving the relationship of Voltage, Current and Resistance Apply Ohm’s Law in practical situations. Now that you know what we will be encountering, here is a short review about the topic.
  • 5. Olah Amigos! I heard the Boots doesn’t exactly know what Ohm’s Law. To know more about it we will be going to the house of Mr. George Simon Ohm. To get there, we must pass the brain maze, down to the Electric Castle and Then to Mr. Ohm’s House. Remember, Maze, Castle, Ohm’s House. Say it with me. Maze, Castle, Ohm’s House..... Ohm's law states that the current through a conductor between two points is directly proportional to the potential difference or voltage across the two points, and inversely proportional to the resistance between them. The mathematical equation that describes this relationship is: where I is the current through the resistance in units of amperes, V is the potential difference measured across the resistance in units of volts, and R is the resistance of the conductor in units of ohms. More specifically, Ohm's law states that the R in this relation is constant, independent of the current. The law was named after the German physicist Georg Ohm, who, in a treatise published in 1827, described measurements of applied voltage and current through simple electrical circuits containing various lengths of wire. He presented a slightly more complex equation than the one above to explain his experimental results. The above equation is the modern form of Ohm's law.
  • 6. Let’s went to Mr. George Ohm’s House. Where should we go first? Do you know where should we go first? The Brain Maze, right. Will you help me cross the brain maze? Thank you! Now let’s go cross the maze! Activity 1: THE BRAIN MAZE Start A D G H C I B E K F L J End These little brain monsters won’t let you pass unless you defeat them by answering their questions. Select your answers from the answer pool. A. The potential difference measured across the resistance. B. Who pioneered the study on the relationship of current, voltage and resistance? C. Unit of measurement for current. (D)____ states that the current through a (E)____ between two points is (F)____ proportional to the (G)_______ difference or voltage across the two points, and (H)_____ proportional to the resistance between them. I. Unit of measurement for resistance. J. The mathematical equation of the relationship of current, voltage and resistance. K. A device use to measure current. L. It is the measure of how much current can flow through a component. Ohm’s Law Ammeter Ampere Directly Voltage V I= George Ohm R Ohm Potential Inversely Resistance Conductor
  • 7. We’ve made it through the brain maze. Now we’re heading towards the castle. My friend told me that the castle’s door will only open if you can close all its windows. Will you help me close the windows? Activity 2. The Electric Castle’s Entrance To open the door of the Castle, we must close all its windows, but the problem is that every window may only be closed by the exact current, resistance and voltage of its circuit. Complete the table below to close the windows and open the Door of the Castle. The castle has 13 windows. Window Number Voltage Current Resistance 1 15 volts 30 amperes ___ ohms 2 21 volts ___ amperes 3 ohms 3 220 volts 20 amperes ___ ohms 4 ___ volts 30 amperes 15 ohms 5 110 volts ___ amperes 10 ohms 6 3 volts 12 amperes ___ ohms 7 ___ volts 50 amperes 25 ohms 8 15 volts 30 amperes ___ ohms 9 ___ volts 21 amperes 7 ohms 10 120 volts 30 amperes ___ ohms 11 6 volts ___ amperes 15 ohms 12 ___ volts 30 amperes 10 ohms 13 ___ volts 30 amperes 5 ohms
  • 8. Welcome to my Castle! I’ve heard that you gone along an electrifying journey. Let’s see what you have learned. Here are my little playing circuits. My friends will help me in playing with your circuits. Activity 2. Playing With Circuits Solve the following circuit problems. Zeus might help you in your journey. 1. An emf source of 6.0V is connected to a purely resistive lamp and a current of 2.0 amperes flows. All the wires are resistance-free. What is the resistance of the lamp? The current flowing in a circuit containing four resistors connected in series is I = 1.0 A. The potential drops across the first, second and third resistors are, respectively: V = 5 V, V = 8 V and V = 7 V. The equivalent resistance of the circuit is R = 30 . (Hint: Resistors connected in series have the same current flows through each one.) 2-5. Resistance of each resistor in the circuit R1, R2, R3 & R4 6. Voltage drop on the fourth resistor. 7. Find the total voltage supplied by the battery 8-10. (3 points) In the following schematic diagram, find the total current, I. (Hint: Currents through branches of a parallel circuit add to give the total current and Voltage in each resistor is the same as the total voltage.) Very Clever! As a reward, I’ll use my power to transport you directly inside the house of Mr. Ohm.
  • 9. We did it! We made through the house of Mr. Ohms but it looks like he is not here so let’s just explores his place and learn more about Ohm’s Law. Ohm's Law defines the relationships between (P) power, (E) voltage, (I) current, and (R) resistance. One ohm is the resistance value through which one volt will maintain a current of one ampere. (I) Current is what flows on a wire or conductor like water flowing down a river. Current flows from negative to positive on the surface of a conductor. Current is measured in (A) amperes or amps. (E) Voltage is the difference in electrical potential between two points in a circuit. It's the push or pressure behind current flow through a circuit, and is measured in (V) volts. (R) Resistance determines how much current will flow through a component. Resistors are used to control voltage and current levels. A very high resistance allows a small amount of current to flow. A very low resistance allows a large amount of current to flow. Resistance is measured in ohms. (P) Power is the amount of current times the voltage level at a given point measured in wattage or watts.
  • 10. I am sure that your brain is going short circuit right now. Let’s relax and look back to the history of Ohm’s Law. The Origin of Ohm's Law Georg Simon Ohm was born in Bavaria in 1789. His father taught him philosophy, chemistry, mathematics and physics. In 1806 he became a mathematics teacher in Switzerland. In 1811 he received a doctorate from Erlangen and became a mathematics lecturer there. In 1817 he took a position as professor of mathematics and physics at the Jesuit Gymnasium of Cologne. In 1820 he learned of Oersted's electromagnetism discovery and began experimenting with electricity in the school's physics laboratory where he convinced himself of what is now known as Ohm's law. In 1825 he published a paper that explains the decrease in electromagnetic force (which is proportional to current) around a wire as its length is increased. He published two papers in 1826 that mathematically describe electrical conduction in circuits. In 1827 he published his famous book Die Galvanische Kette, mathematisch bearbeitet, which contains what we now know as Ohm's law. His theories were scorned at the time and he was forced to resign his teaching position because of them.
  • 11. (Assessment) 1. An emf source of 6.0V is connected to a purely resistive lamp and a current of 2.0 amperes flows. All the wires are resistance-free. What is the resistance of the lamp? The gain of potential energy occurs as a charge passes through the battery, that is, it gains a potential of =6.0V. No energy is lost to the wires, since they are assumed to be resistance- free. By conservation of energy, the potential that was gained (i.e. =V=6.0V) must be lost in the resistor. So, by Ohm's Law: V=IR R=V/I R = 3.0 2-7. The current flowing in a circuit containing four resistors connected in series is I = 1.0 A. The potential drops across the first, second and third resistors are, respectively: V = 5 V, V = 8 V and V = 7 V. The equivalent resistance of the circuit is R = 30 . 2-5. Resistance of each resistor in the circuit R1, R2, R3 & R4 6. Voltage drop on the fourth resistor. 7. Find the total voltage supplied by the battery Hints 1. How are resistors related when connected in series? 2. What is true about potential drops of resistors when connected in series? 3. You will need to use Ohm's Law.
  • 12. Solution First, let's label the diagram with the information given in the question. There are several ways of solving this problem (see alternate solutions), but this tutorial will only go through one of these ways. Because the resistors are connected in series, then the same current flows through each one. Using the Ohm's Law, we can find the resistances of the first, second and third resistors. Now, using the equivalent resistance, we can find the resistance in the fourth resistor. This is a series circuit, so the equivalent resistance is the sum of the individual resistances. The current flowing through the fourth resistor is also I=1.0A. Using Ohm's Law again, we find the voltage across this resistor. The total voltage supplied by the battery must equal to the total voltage drop across the circuit (this is known as Kirchhoff's Voltage Law). So, we must sum up the voltage drops across the resistors.
  • 13. (8-10) In the following schematic diagram, find the total current, I. You will need Ohm's Law. 1. How are resistors related when connected in parallel? 2. What is the potential drop across each resistor? 3. How does current behave in parallel branches? Solution We know the total potential of this circuit, = 12.0 V So, between points A and B, the potential must drop 12.0V. Also, the potential drop across branches of a circuit are equal. That is, We can use Ohm's Law V = IR or I = V/R to find the current across each resistor. Recall that the currents through branches of a parallel circuit add to give the total current. That is, the total current 'splits up' so that part of the total current travels down each branch. Because of conservation of charge, the sum of the currents in each branch must equal the amount going into the branch. (This is Kirchhoff's Current Law.) So, adding up the three currents, we get: So, the total current is I = 12.0A.
  • 14. Activity 2. The Electric Castle’s Entrance To open the door of the Castle, we must close all its windows, but the problem is that every window may only be closed by the exact current, resistance and voltage of its circuit. Complete the table below to close the windows and open the Door of the Castle. The castle has 13 windows. Window Number Voltage Current Resistance 1 15 volts 30 amperes 0.5 ohms 2 21 volts 7 amperes 3 ohms 3 220 volts 20 amperes 11 ohms 4 450 volts 30 amperes 15 ohms 5 110 volts 11 amperes 10 ohms 6 3 volts 12 amperes 0.25 ohms 7 6250 volts 50 amperes 25 ohms 8 15 volts 30 amperes 0.5 ohms 9 147 volts 21 amperes 7 ohms 10 120 volts 30 amperes 4 ohms 11 6 volts 0.4 amperes 15 ohms 12 300 volts 30 amperes 10 ohms 13 150 volts 30 amperes 5 ohms In completing the table above we use the following formula. For Voltage: V = I x R For Current: I = V / R For Current: R = V / I
  • 15. Activity 1: THE BRAIN MAZE Start A D G H C I B E K F L J End These little brain monsters won’t let you pass unless you defeat them by answering their questions. Select your answers from the answer pool. A. Voltage is the potential difference measured across the resistance. B. George Simon Ohm pioneered the study on the relationship of current, voltage and resistance. C. Ampere is a unit of measurement for current. (D) Ohm’s Law states that the current through a (E) Conductor between two points is (F) Directly proportional to the (G) Potential difference or voltage across the two points, and (H) Inversely proportional to the resistance between them. I. Ohm is a unit of measurement for resistance. J. The mathematical equation of the relationship of current, voltage and resistance is K. Ammeter is a device use to measure current. L. Resistance is the measure of how much current can flow through a component.