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INTRODUCTION
Definition

Computer Numerical Control (CNC) is one in which the functions and motions of a machine
tool are controlled by means of a prepared program containing coded alphanumeric data.
CNC can control the motions of the workpiece or tool, the input parameters such as feed,
depth of cut, speed, and the functions such as turning spindle on/off, turning coolant on/off.

Applications

The applications of CNC include both for machine tool as well as non-machine tool areas.
In the machine tool category, CNC is widely used for lathe, drill press, milling machine,
grinding unit, laser, sheet-metal press working machine, tube bending machine etc. Highly
automated machine tools such as turning center and machining center which change the
cutting tools automatically under CNC control have been developed. In the non-machine tool
category, CNC applications include welding machines (arc and resistance), coordinate
measuring machine, electronic assembly, tape laying and filament winding machines for
composites etc.

Advantages and Limitations

The benefits of CNC are (1) high accuracy in manufacturing, (2) short production time, (3)
greater manufacturing flexibility, (4) simpler fixturing, (5) contour machining (2 to 5 -axis
machining), (6) reduced human error. The drawbacks include high cost, maintenance, and the
requirement of skilled part programmer .

                              ELEMENTS OF A CNC

A CNC system consists of three basic components (Figure 2) :

       1.      Part program
       2.      Machine Control Unit (MCU)
       3.      Machine tool (lathe, drill press, milling machine etc)

Part Program

The part program is a detailed set of commands to be followed by the machine tool. Each
command specifies a position in the Cartesian coordinate system (x,y,z) or motion (workpiece
travel or cutting tool travel), machining parameters and on/off function. Part programmers
should be well versed with machine tools, machining processes, effects of process variables,
and limitations of CNC controls. The part program is written manually or by using computer-
assisted language such as APT (Automated Programming Tool).
MACHINE TOOL




Figure 2. A typical numerical control system for a milling machine

Machine Control Unit

The machine control unit (MCU) is a microcomputer that stores the program and executes the
commands into actions by the machine tool. The MCU consists of two main units: the data
processing unit (DPU) and the control loops unit (CLU). The DPU software includes control
system software, calculation algorithms, translation software that converts the part program
into a usable format for the MCU, interpolation algorithm to achieve smooth motion of the
cutter, editing of part program (in case of errors and changes) . The DPU processes the data
from the part program and provides it to the CLU which operates the drives attached to the
machine leadscrews and receives feedback signals on the actual position and velocity of each
one of the axes. A driver (dc motor) and a feedback device are attached to the leadscrew.
The CLU consists of the circuits for position and velocity control loops, deceleration and
backlash take up, function controls such as spindle on/off.
Machine Tool

The machine tool could be one of the following: lathe, milling machine, laser, plasma,
coordinate measuring machine etc. Figure 3 shows that a right-hand coordinate system is used
to describe the motions of a machine tool . There are three linear axes (x,y,z), three rotational
axes (i,j,k), and other axes such as tilt (9) are possible. For example, a 5-axis machine
implies any combination of x,y,z, i,j,k,and 6.




Figure 3 . Right-hand coordinate system used in drill press and lathe

                                                5
PRINCIPLES OF CNC

Basic Length Unit (BLU)


Each BLU unit corresponds to the position resolution of the axis of motion. For example,
1 BLU = 0.0001" means that the axis will move 0.0001" for every one electrical pulse
received by the motor . The BLU is also referred to as Bit (binary digit).

       Pulse = BLU = Bit

Point-to-Point Systems

Point-to-point systems are those that move the tool or the workpiece from one point to
another and then the tool performs the required task. Upon completion, the tool (or
workpiece) moves to the next position and the cycle is repeated (Figure 4). The simplest
example for this type of system is a drilling machine where the workpiece moves .

In this system, the feed rate and the path of the cutting tool (or workpiece) have no
significance on the machining process . The accuracy of positioning depends on the system's
resolution in terms of BLU (basic length unit) which is generally between 0 .001" and 0.0001" .

                                                                  Workpiece




Figure 4. Cutter path between holes in a point-to-point system



 Example 1


 The XY table of a drilling machine has to be moved from the point (1,1) to the point
 (6,3). Each axis can move at a velocity of 0.5"/sec, and the BLU is 0.0001", find the
 travel time and resolution.

 Travel time in X-axis is (6-1)/0 .5 = 10 sec, in Y-axis is (3-1)/0 .5= 4 sec .
 Travel time = 10 sec
 Resolution = BLU = 0.0001
Continuous Path Systems (Straight cut and Contouring systems)

These systems provide continuous path such that the tool can perform while the axes are
moving, enabling the system to generate angular surfaces, two-dimensional curves, or three-
dimensional contours . Example is a milling machine where such tasks are accomplished
(Figure 5). Each axis might move continuously at a different velocity. Velocity error is
significant in affecting the positions of the cutter (Figure 5). It is much more important in
circular contour cutting where one axis follows sine function while the other follows cosine
function. Figure 6 illustrates point-to-point and continuous path for various machines .




Figure 5. (a) Continuous path cutting and (b) Position error caused by the velocity error


 Example 2

 A CNC milling machine has to cut a slot located between the points (0,0) and (4,3)
 on the XY-plane where the dimensions are in inches. If the speed along the slot is to
 be 0.1 in/sec, find the cutting time and axial velocities.

 Distance traveled along the slot = (16+9)'"2 = 5"

 Cutting time = 5/0.1 = 50 sec

 Vx = xV/(x2+y2)" = 4(0.1)/5 = 0.08 in/sec
 Vy =yV/(x2+y2)'"2 = 3(0.1)/5 = 0.06 in/sec

 If the velocity is Y-axis is off by 10%, what would be the new position ?

 New velocity in y is 0.9 x 0 .06 = 0.054 in/sec

 In 50 sec, the y- will move a distance [50(0.054)] = 2 .7 in.
Point-to-point                      Point-to-point and
                                                                 straight line
                                              Drilling and
                                              boring




                             2-axis contouring with              3-aris contouring
                             switchable plane                    oontinuous path

                                                2-axis contour
                                                milling                         milling




Figure 6. Schematic illustration of drilling, boring, and milling with various paths.

Interpolator

The input speed of l in/sec in example 2 is converted into the velocity components by an
interpolator called the linear interpolator whose function is to provide the velocity signals to x
and y directions. Similarly we have circular and parabolic interpolators. See Figure 7.




                                          i'f                                    Quadrant ~   ----    Full
                                                                                                     circle




Figure 7.      Types of interpolation (a) linear, (b) continuous path approximated by
               incremental straight lines, and (c) circular
Incremental and Absolute systems

CNC systems are further divided into incremental and absolute systems (Figure 8). In
incremental mode, the distance is measured from one point to the next. For example, if you
want to drill five holes at different locations, the x-position commands are x + 500, + 200, +
600, - 300, -700, -300 . An absolute system is one in which all the moving commands are
referred from a reference point (zero point or origin) . For the above case, the x-position
commands are x 500,700, 1300, 1000, 300, 0. (Figure 8) . Both systems are incorporated in
most CNC systems. For an inexperienced operator, it is wise to use incremental mode.




              10


               8

               6




Figure 8.     (a) Absolute versus incremental ; In absolute positioning, the move is specified
              by x = 6, y = 8 ; in incremental, the move is specified by x=4, y=5 for the tool
              to be moved from (2,3) to (6,8)

              (b)   Drilling 5-holes at different locations

The absolute system has two significant advantages over the incremental system :

       Interruptions caused by, for example, tool breakage (or tool change, or checking
       the parts), would not affect the position at the interruption.

If a tool is to be replaced at some stage, the operator manually moves the table, exchanges the
tool, and has to return the table to the beginning of the segment in which the interruption has
occurred . In the absolute mode, the tool is automatically returned to the position. In
incremental mode, it is almost impossible to bring it precisely to that location unless you
repeat the part program

2.     Easy change of dimensional data
The incremental mode has two advantages over the absolute mode .

 1.     Inspection ofthe program is easier because the sum of position commands for each
        axis must be zero . A nonzero sum indicates an error . Such an inspection is impossible
        with the absolute system .

2.     Mirror image programming (for example, symmetrical geometry of the parts) is simple
       by changing the signs of the position commands.

Open Loop Control Systems

The open-loop control means that there is no feedback and uses stepping motors for driving
the leadscrew . A stepping motor is a device whose output shaft rotates through a fixed angle
in response to an input pulse (Figure 9) . The accuracy of the system depends on the motor's
ability to step through the exact number . The frequency of the stepping motor depends on the
load torque. The higher the load torque, lower would be the frequency . Excessive load torque
may occur in motors due to the cutting forces in machine tools . Hence this system is more
suitable for cases where the tool force does not exist (Example : laser cutting) .

                                                  Work table
                  Pulse
                  train     a stepping
                               motor

                                             Lead screw


                          Figure 9.      Open loop control system

The stepping motor is driven by a series of electrical pulses generated by the MCU . Each
pulse causes the motor to rotate a fraction of one revolution. The fraction is expressed in
terms of the step angle, oc, given by

               a = 360/N, degrees where N = number of pulses required for one revolution

If the motor receives "n" number of pulses then the total angle,

               A = n (360/N), degrees

In terms of the number of revolutions, it would be (n/N)

If there is a 1 :1 gear ratio between the motor and the leadscrew, then the leadscrew has (n/N)
revolutions . If the pitch of leadscrew is p (in/rev), then the distance traveled axially, say x,

              x = p(n/N)

can be used to achieve a specified x-increment in a point-to-point system.


                                                  10
The pulse frequency, f, in pulses/sec determines the travel speed of the tool or the workpiece .

       60 f = N (RPM) where N = number of pulses per revolution,
       RPM = RPM of the lead screw

The travel speed, V, is then given by V = p (RPM) where p pitch in in/rev


  Example 3

  A stepping motor has N = 150, p = 0.2"/rev ; If n = 2250 pulses, what is the distance
  traveled in x-direction ? What should be the pulse frequency for a travel speed of 16
  in./min ?

                  x = (0.2) (2250)/150 = 3"

         16'= 0 .2 (RPM), from which, RPM = 80

         f = (150) (80)/60 = 200 Hz



 Example 4

 A stepping motor of 200 steps per revolution is mounted on the leadscrew of a
 drilling machine. If the pitch is 0.1 in/rev.,

 a.      What is the BLU ?
 b.      If the motor receives a pulse frequency of 2000 Hz, what is the speed of the
              table ?

 a.      BLU = 0 .1/200 = 0.0005"

 b.      Table speed = (p) (RPM) = (0 .1) (60) (2000)/200 = 60 in/min


Closed-loop Control Systems

Closed -loop NC systems are appropriate when there is a force resisting the movement of the
tool/workpiece . Milling and turning are typical examples . In these systems (Figure 10) the DC
servomotors and feedback devices are used to ensure that the desired position is achieved .
The feedback sensor used is an optical encoder shown in Figure 11 . The encoder consists of
a light source, a photodetector, and a disk containing a series of slots. The encoder is
connected to the leadscrew . As the screw turns, the slots cause the light to be seen by the
photodetector as a series of flashs which are converted into an equivalent series of electrical
pulses which are then used to characterize the position and the speed. The equations remain
essentially the same as open-loop except that the angle between the slots in the disk is the
step angle, a.

Both the input to the control loop and the feedback signals are a sequence of pulses, each
pulse representing a BLU unit. The two sequences are correlated by a comparator and gives
a signal, by means of a digital-to-analog converter, (a signal representing the position error),
to operate the drive motor (DC servomotor) .


                                                                         Work table
              Input
                                                     do
                      Comparator         DAC                      Gear
                                                 servomotor

                                                                                      Position
                                               Feedback signal                         sensor




              Figure 10. Closed loop control system




                                                                           Signal pulses




                                                      Photocell                                  Time
                                   (a)                                          (b)




              Figure 11 . Optical Encoder (a) Device (b) Series of pulses emitted


                                                          12
Example 5

Consider a CNC worktable driven by a closed-loop control system consisting of a
servomotor, leadscrew, and optical encoder. The leadscrew has a pitch, p = 0.2" and
is coupled to the motor shaft with a screw to motor gear ratio of 1 :4. The encoder
generates 150 pulses per revolution of the leadscrew. If the number of pulses and the
pulse rate received by the control system are 2250 and 200 Hz respectively, calculate

      a.      Table speed
      b.      Motor speed in RPM
      c.      Distance traveled by the table


a.    V= p(RPM) = 0 .2(RPM) = (0 .2) (60 f)/N = (0 .2) (60) (200)/150 = 16 in/min

b.    RPM of the leadscrew = (60) (200)/(150) = 80
      RPM of the motor = 320

c.          x = p(n/N) = (0.2) (2250)/150 = 3"




Example 6

A do servomotor is coupled to a leadscrew which drives the table of a CNC machine
tool. A digital encoder, mounted at the end of the screw, emits 500 pulses per
revolution. If the pitch is 5 mm per rev, and the motor rotates 600 rpm (1 :1 gear
ratio), calculate the

a.    Table speed
b.    BLU
c.    Frequency of pulses transmitted by the encoder

a.    V= p(RPM) = 5 (600) = 3000 mm/min = 3 m/min

b.    BLU = 5/500 = 0.01 mm

c.    RPM = 600 = (60f)/N = 60 f/500 from which f = 5000 Hz




                                           13
PRECISION IN CNC MACHINING

The combined characteristics of the machine tool and the control determine the precision of
positioning . Three critical measures of precision are :

       o       Resolution
       o       Accuracy
       o       Repeatability

Control resolution (BLU) is the distance separating two adjacent points in the axis movement
(the smallest change in the position) . The electromechanical components of the positioning
system that affect the resolution are the leadscrew pitch, the gear ratio, and the step angle in
the stepping motor (open loop) or the angle between the slots in the encoder (closed-loop).
The control resolution for a 1 :1 gear ratio of a stepped motor is,

              Resolution = p/N     where p = pitch, and N = 360/a

Features smaller than the control resolution could not be produced . The programming
resolution can not exceed the control resolution .

Accuracy of a CNC system depends on the resolution, the computer control algorithms, and
the machine inaccuracies . The inaccuracy due to the resolution is considered to be (1/2)BLU
on the average. The control algorithm inaccuracy is due to the rounding off the errors in the
computer which is insignificant. The machine inaccuracy could be due to several reasons
(described below) . The designer minimizes this inaccuracy to be under (1/2)BLU and hence

              Accuracy = (1/2) Resolution + Machining inaccuracy = BLU

Repeatability is a statistical term associated with accuracy . It refers to the capability of a
positioning system to return to a programmed point, and is measured in terms of the errors
associated with the programmed point. The deviation from the control point (error) usually
follows a normal distribution in which case the repeatability may be given as +/- 3a where a
is the standard deviation. The repeatability is always better than the accuracy . The mechanical
inaccuracy can be considered as the repeatability . Figure 12 shows the difference between the
accuracy and the repeatability .

Machining Inaccuracy

Cutting tool deflection, machine tool chatter, mechanical linkage between the leadscrew and
the tool, and thermal deformations are the chief contributing factors . The leadscrew transmits
the power to the table or toolholder by means of a nut that engages the leadscrew . This will
create what is known as "backlash"due to the friction between the screw and the nut. If the
nut consists of ball bearings, the friction is reduced . Thermal deformations are significant.
For example, a temperature difference of 1 °C along 1000 mm can cause an error of 0.01 mm.

                                               14
EMEMOMME
 MOMEMENN
 MMMMMMMM
                                   MEME ME"O
                                   MEN"E"""
                                   MMOMMOME
                                                                     s
                                                                     ONNEEMEN
                                                                      EMOMMEN
                                                                     IMMEMENE
 MENNOMME                          EMMMOMME                          M"MM IMSN
 ME MEN                            .... ....                         ...LO...
   MI  No                          MEMM EME"                         MMMMMMMM
 MMEMEMEN                          MOMMOMME                          M"""M"N
                                   MEMEMMEN                          """" MM""
      Low Accuracy                       Low Accuracy                      High Accuracy
     Low Repeatability                 High Repeatability                High Repeatability




Figure 12. Diagram showing the difference between accuracy and repeatability



 Example 7

 What is the control resolution for a 4 :1 gear ratio (motor: leadscrew), pitch of
 leadscrew 0.2 in/rev, and the motor receives 600 pulses per revolution

 Since the motor shaft rotates 4 times faster than the leadscrew, N = 600/4 = 150
 Resolution = 0.2/150 = 0.001333"

 What would be the accuracy and repeatability if the machining inaccuracy is about
 (1/2)BLU ?

 Accuracy = 0.001333/2 + 0 .001333/2= 0.001333"

 Repeatability = +/- 0.00067"




                                             15
PART PROGRAMMING FOR CNC

The transfer of an engineering blueprint of a product to a part program can be performed
manually using a calculator or with the assistance of a computer language . A part programmer
must have an extensive knowledge of the machining processes and the capabilities of the
machine tools . In this section, we describe how the part programmers execute manually the
part programs.

First, the machining parameters are determined . Second, the optimal sequence of operations
is evaluated . Third, the tool path is calculated . Fourth, a program is written. Each line of the
program, referred to as a block, contains the required data for transfer from one point to the
next.

A typical line for a program is given below .

       N100 G91 X -5.0 Y7 .0 F100 S200 T01 M03 (EOB)

The significance of each term is explained below .

Sequence Number, N

Consisting of typically three digits, its purpose is to identify the specific machining operation
through the block number particularly when testing a part program.

Preparatory Function, G

It prepares the MCU circuits to perform a specific operation . The G-codes (some) are shown
in Table 1 . G91 implies incremental mode of operation.

Dimension Words

1.     Distance dimension words, X,Y,Z

2.     Circular dimension words, I,J,K for distances to the arc center

3.     Angular dimensions, A,B.C

While (1) and (3) are expressed either by incremental or absolute mode, (2) is always in given
in incremental mode. All angular dimensions are specified in revolutions or degrees.

In the above block, X moves a distance of 5 in. in the negative direction while Y moves a
distance of 7 in. in the positive direction. Other axes remain stationary. In some systems,
actual distances are used. In others, the dimension words are programmed in BLUs .



                                                16
Feedrate, F

It is expressed in in/min or mm/min and, is used in contouring or point-to-point or straight-cut
systems . For example, a feedrate of F100 implies 100 in/min or 100 mm/min . Feedrates are
independent of spindle speed.

In linear motions, the feedrate of the cutting tool is not corrected for the cutter radius . But
in circular motions, the feedrate should be corrected for the tool radius as follows :

               F = [(part contour radius ± tool radius)/part contour radius] (required feedrate)

For cutting around the outside of a circle, the plus sign in the above equation is used, and the
feedrate is increased. For cutting around the inside of a circle, the minus sign is used, and the
feedrate is decreased .


  Example 8

  See Figure 5(a). If the required feedrate is 6 in/min, part contour radius is 1 .5 in,
  and the cutter diameter is 1 in, what is the feedrate athe top and bottom circles ?

  Feedrate at the top is to be 8 in/min and at the bottom is to be 4 in/min.



Spindle speed, S

Programmed in rev/min, it is expressed as RPM or by a three-digit code number that is
related to the RPM.

Toolword, T

Consisting of a maximum of five digits, each cutting tool has a different code number. The
tool is automatically selected by the automatic tool changer when the code number is
programmed in a block.

Miscellaneous Function, M

Consisting of two digits, this word relates to the movement of the machine in terms of spindle
on/off, coolant on/off etc shown in Table 2.

EOB

The EOB character is used at the end of each block to complete a line.


                                                17
Table . .1   Preparatory commands (G-code)
                    G00   Point-to-point positioning
                    G01   Linear interpolation
                    G02   Clockwise circular interpolation
                    G03   Counter-clockwise circular interpolation
                    G04   Dwell
                    G05   Hold
                    G33   Thread cutting, constant lead
                    G40   Cancel tool nose radius compensation
                    G41   Tool nose radius compensation - left
                    G42   Tool nose radius compensation - right
                    G43   Cutter length compensation
                    G44   Cancel cutter length compensation
                    G70   Dimensions in inches
                    G71   Metric dimensions
                    G90   Absolute dimensions
                    G91   Incremental dimensions
                    G92   Datum offset



                    Table . .2 Miscellaneous commands (M-code)
                    M00   Program stop
                    M01   Optional stop
                    M02   End of program
                    M03   Spindle start clockwise
                    M04   Spindle start counter-clockwise
                    M05   Spindle stop
                    M06   Tool change
                    M07   Mist coolant on
                    M08   Flood coolant on
                    M09   Coolant off
                    M10   Clamp
                    Mll   Unclamp
                    M13   Spindle clockwise, coolant on
                    M14   Spindle counter-clockwise, coolant on
                    M30   End of tape, rewind




Tables 1 and 2 :   G and M codes used in CNC systems

                                                18
4-7-2     G Functions (SEICOS-MII)


   G code      Group                                  Function
    GOO                Positioning (rapid traverse)
    GO1                Linear interpolation (cutting feed)               .
                01
    G02                Circular interpolation CW
    G03                Circular interpolation CCW
    G04                Dwell


    G07         00     SIN interpolation (designation of virtual axis)
    G09                Exact stop check
    G10                Offset amount and work zero point offset amount setting
    G17                Designation of X-Y plane
    G18         02     Designation of Z-X plane
    G19                Designation of Y-Z plane
    G20         06     Inch input
    G21                Metric input;
    G22                Stored stroke, limi t,ON
                04~
    G23                Stored'--s troke"- limit OFF
    G27                Return to reference paint
    G28                Return to reference-pant:_-_. ..
    G29         00     Return from reference point               `'
    G30                Return to 2nd reference point             4
    G31                Skip function


    G40         07     Tool diameter compensation cancel
    G41                Tool diameter compensation to left
    G42                Tool diameter compensation to right
    G43                Tool length compensation
    G44         08     Tool length compensation
    G49                Tool length compensation cancel
    G45                Tool offset expansion
    G46         00     Tool offset reduction
    G47                Tool offset double expansion
    G48                Tool offset double reduction

    G50         11     Scaling cancel
    G51                Scaling

        G codes with "   " are set when the power is .turned on .
        G40, G49 and G80 are set by resetting the NC unit .
G code       Group                                 Function
  G52          00         .Local coordinate system setting
  G53                     Machine coordinate system selection
  G54                     Work coordinate system 1 selection
  G55          12         Work coordinate system 2 selection
  G56                     Work coordinate system 3 selection
  G57                     Work coordinate system 4 selection
  G58                     Work coordinate system 5 selection
  G59                     Work coordinate system .6 selection
  G60          00     I   One directional positioning
  G61                     Exact stop check mode
  G63          13     I Tapping mode
  G64                     Continuous cutting mode
  G65          00         Macro call
  G66          14         Macro modal call A
G67~                  C Macro modal call cancel

  G73                 + Pec k dri l ling cycle
  G74                     Reverse tapping cycle
  G76                 I Fine boring
G80                   ` Canned cycle cancel
  G81'                    Dr illing cycle, sp ot boring
  G82                     Drilling cycle, counter boring
  G83          09         Peck drilling cycle
  G84                 ( Tapping cycle
  G85                     Boring cycle
  G86     I               Boring cyc le
                      r
  G87                     Back boring cycle                     -'"
  G88                     Boring cycle
  G89     I               Boring cycle
  G90          03     L Absolute programming
  G91                     Incremental programming
  G92          00         Programming of absolute zero point




  G98          10     I   Initial level return (canned cycle)
  G99                     R point level return (canned cycle)
 G501          15         Programmable mirror image cancel
  G511                    Programmable mirror image


                                       4 - 30
4-7-3       M Functions
                                                                 (* : Optional function)


  M    I            Function name             M              Function name
                                                    Idle cutting time reduction
 00        Program stop                      *33
                                                    (modal)
                                                   (Idle cutting time reduction
 01        Optional stop                     *34
                                                    (unmodal)
 02        End of program                    *35    Automatic start ON

 03 (Spindle forward                         *36    Automatic start OFF
 04        Spindle reverse                   *37
                                                    Spindle no-load detect function
 05    (Spindle stop                         *38
                                                    stop

 06        Tool change ATC                   *39    M38 cancel

 *07       Mist coolant start                *40    Tool nose air blow ON

 08        Flood coolant start               *41    Tool nose air blow OFF

 09 (Mist coolant stop                       *42
 *10       Mist coolant attitude 1           *43

*11        Mist coolant attitude 2           *44

*12        Work count                        *45    Spare tool offset enabled

 13        Spindle forward & coolant start   ''*46 (Spare tool offset disabled
 14        Spindle reverse & coolant start   *47    Jet coolant start

 15        M13/M14 stop                      48    (Feed rate override enabled

*16i Measurement air blow ON                 49     Feed rate override 100%
*17        Measurement air blow OFF          *50    Oil hole coolant start
*18~ Measuring spindle orientation           *51
 19        Spindle orientation               *52    Tool breakage detect
*20~ Machining time monitoring               *53
*21                                          *54
 *22                                         *55
 *23                                         *56
 *24                                         *57
*25                                          *58
 *26       Melodia (1)                       *59
 *27       Melodia (2)                       *60    Work change APC
 *28       Setting load level 0              *61
 *29       Setting load level 1              *62
 30        End of tape                       *63

 *31       Chip conveyor start               *641
 *32       M33 cancel                        *65
M             Function name             M           Function name

*66
*67
*68   Additional axis clamp
*69   Additional axis unclimp
*70   M70 output
*71   M71 output
*72   M72 output
*73   M73 output
*74   Skip selection OFF
*75   Skip selection ON
*76                                              .
*77
*78   Additional axis clamp
*79   Additional axis unclamp
*80   Tool nose air blow ON
*81
*82
                                             i
*83
*84
*85
      Measurement NG tool breakage
*86
      detect
*87

*90
*91
*92
*93
*94
*95
*96
*97
 98   Subprogram call

 99   End of subprogram




                                4- 3 2
M             Maintenance mode
*1001 Arm swing-in to spindle side
*101
*102.   Arm advance
*103    Arm turn CW
*104    Arm turn CCW
*105    Arm retract
*106    Arm slide to home position__
*107
*108    Arm slide to magazine side
*109
*110
*111
*112
*113
*114
*115
*116
*117
*118
*119    Orientation
*120    Magazine positioning pin OUT
*121    Magazine positioning pin IN     1
*122
*123,
*124    Pallet slider advance (APC)
*125    Pallet unclamp          (APC)
*1261   Pallet slider retract   (APC)
*1271   Pallet right turn       (APC)
*128    Pallet left turn        (APC)       -
                                        1
*129    Pallet unclamp          (APC)




                                4-33

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Cnc notes (1)

  • 1. INTRODUCTION Definition Computer Numerical Control (CNC) is one in which the functions and motions of a machine tool are controlled by means of a prepared program containing coded alphanumeric data. CNC can control the motions of the workpiece or tool, the input parameters such as feed, depth of cut, speed, and the functions such as turning spindle on/off, turning coolant on/off. Applications The applications of CNC include both for machine tool as well as non-machine tool areas. In the machine tool category, CNC is widely used for lathe, drill press, milling machine, grinding unit, laser, sheet-metal press working machine, tube bending machine etc. Highly automated machine tools such as turning center and machining center which change the cutting tools automatically under CNC control have been developed. In the non-machine tool category, CNC applications include welding machines (arc and resistance), coordinate measuring machine, electronic assembly, tape laying and filament winding machines for composites etc. Advantages and Limitations The benefits of CNC are (1) high accuracy in manufacturing, (2) short production time, (3) greater manufacturing flexibility, (4) simpler fixturing, (5) contour machining (2 to 5 -axis machining), (6) reduced human error. The drawbacks include high cost, maintenance, and the requirement of skilled part programmer . ELEMENTS OF A CNC A CNC system consists of three basic components (Figure 2) : 1. Part program 2. Machine Control Unit (MCU) 3. Machine tool (lathe, drill press, milling machine etc) Part Program The part program is a detailed set of commands to be followed by the machine tool. Each command specifies a position in the Cartesian coordinate system (x,y,z) or motion (workpiece travel or cutting tool travel), machining parameters and on/off function. Part programmers should be well versed with machine tools, machining processes, effects of process variables, and limitations of CNC controls. The part program is written manually or by using computer- assisted language such as APT (Automated Programming Tool).
  • 2. MACHINE TOOL Figure 2. A typical numerical control system for a milling machine Machine Control Unit The machine control unit (MCU) is a microcomputer that stores the program and executes the commands into actions by the machine tool. The MCU consists of two main units: the data processing unit (DPU) and the control loops unit (CLU). The DPU software includes control system software, calculation algorithms, translation software that converts the part program into a usable format for the MCU, interpolation algorithm to achieve smooth motion of the cutter, editing of part program (in case of errors and changes) . The DPU processes the data from the part program and provides it to the CLU which operates the drives attached to the machine leadscrews and receives feedback signals on the actual position and velocity of each one of the axes. A driver (dc motor) and a feedback device are attached to the leadscrew. The CLU consists of the circuits for position and velocity control loops, deceleration and backlash take up, function controls such as spindle on/off.
  • 3. Machine Tool The machine tool could be one of the following: lathe, milling machine, laser, plasma, coordinate measuring machine etc. Figure 3 shows that a right-hand coordinate system is used to describe the motions of a machine tool . There are three linear axes (x,y,z), three rotational axes (i,j,k), and other axes such as tilt (9) are possible. For example, a 5-axis machine implies any combination of x,y,z, i,j,k,and 6. Figure 3 . Right-hand coordinate system used in drill press and lathe 5
  • 4. PRINCIPLES OF CNC Basic Length Unit (BLU) Each BLU unit corresponds to the position resolution of the axis of motion. For example, 1 BLU = 0.0001" means that the axis will move 0.0001" for every one electrical pulse received by the motor . The BLU is also referred to as Bit (binary digit). Pulse = BLU = Bit Point-to-Point Systems Point-to-point systems are those that move the tool or the workpiece from one point to another and then the tool performs the required task. Upon completion, the tool (or workpiece) moves to the next position and the cycle is repeated (Figure 4). The simplest example for this type of system is a drilling machine where the workpiece moves . In this system, the feed rate and the path of the cutting tool (or workpiece) have no significance on the machining process . The accuracy of positioning depends on the system's resolution in terms of BLU (basic length unit) which is generally between 0 .001" and 0.0001" . Workpiece Figure 4. Cutter path between holes in a point-to-point system Example 1 The XY table of a drilling machine has to be moved from the point (1,1) to the point (6,3). Each axis can move at a velocity of 0.5"/sec, and the BLU is 0.0001", find the travel time and resolution. Travel time in X-axis is (6-1)/0 .5 = 10 sec, in Y-axis is (3-1)/0 .5= 4 sec . Travel time = 10 sec Resolution = BLU = 0.0001
  • 5. Continuous Path Systems (Straight cut and Contouring systems) These systems provide continuous path such that the tool can perform while the axes are moving, enabling the system to generate angular surfaces, two-dimensional curves, or three- dimensional contours . Example is a milling machine where such tasks are accomplished (Figure 5). Each axis might move continuously at a different velocity. Velocity error is significant in affecting the positions of the cutter (Figure 5). It is much more important in circular contour cutting where one axis follows sine function while the other follows cosine function. Figure 6 illustrates point-to-point and continuous path for various machines . Figure 5. (a) Continuous path cutting and (b) Position error caused by the velocity error Example 2 A CNC milling machine has to cut a slot located between the points (0,0) and (4,3) on the XY-plane where the dimensions are in inches. If the speed along the slot is to be 0.1 in/sec, find the cutting time and axial velocities. Distance traveled along the slot = (16+9)'"2 = 5" Cutting time = 5/0.1 = 50 sec Vx = xV/(x2+y2)" = 4(0.1)/5 = 0.08 in/sec Vy =yV/(x2+y2)'"2 = 3(0.1)/5 = 0.06 in/sec If the velocity is Y-axis is off by 10%, what would be the new position ? New velocity in y is 0.9 x 0 .06 = 0.054 in/sec In 50 sec, the y- will move a distance [50(0.054)] = 2 .7 in.
  • 6. Point-to-point Point-to-point and straight line Drilling and boring 2-axis contouring with 3-aris contouring switchable plane oontinuous path 2-axis contour milling milling Figure 6. Schematic illustration of drilling, boring, and milling with various paths. Interpolator The input speed of l in/sec in example 2 is converted into the velocity components by an interpolator called the linear interpolator whose function is to provide the velocity signals to x and y directions. Similarly we have circular and parabolic interpolators. See Figure 7. i'f Quadrant ~ ---- Full circle Figure 7. Types of interpolation (a) linear, (b) continuous path approximated by incremental straight lines, and (c) circular
  • 7. Incremental and Absolute systems CNC systems are further divided into incremental and absolute systems (Figure 8). In incremental mode, the distance is measured from one point to the next. For example, if you want to drill five holes at different locations, the x-position commands are x + 500, + 200, + 600, - 300, -700, -300 . An absolute system is one in which all the moving commands are referred from a reference point (zero point or origin) . For the above case, the x-position commands are x 500,700, 1300, 1000, 300, 0. (Figure 8) . Both systems are incorporated in most CNC systems. For an inexperienced operator, it is wise to use incremental mode. 10 8 6 Figure 8. (a) Absolute versus incremental ; In absolute positioning, the move is specified by x = 6, y = 8 ; in incremental, the move is specified by x=4, y=5 for the tool to be moved from (2,3) to (6,8) (b) Drilling 5-holes at different locations The absolute system has two significant advantages over the incremental system : Interruptions caused by, for example, tool breakage (or tool change, or checking the parts), would not affect the position at the interruption. If a tool is to be replaced at some stage, the operator manually moves the table, exchanges the tool, and has to return the table to the beginning of the segment in which the interruption has occurred . In the absolute mode, the tool is automatically returned to the position. In incremental mode, it is almost impossible to bring it precisely to that location unless you repeat the part program 2. Easy change of dimensional data
  • 8. The incremental mode has two advantages over the absolute mode . 1. Inspection ofthe program is easier because the sum of position commands for each axis must be zero . A nonzero sum indicates an error . Such an inspection is impossible with the absolute system . 2. Mirror image programming (for example, symmetrical geometry of the parts) is simple by changing the signs of the position commands. Open Loop Control Systems The open-loop control means that there is no feedback and uses stepping motors for driving the leadscrew . A stepping motor is a device whose output shaft rotates through a fixed angle in response to an input pulse (Figure 9) . The accuracy of the system depends on the motor's ability to step through the exact number . The frequency of the stepping motor depends on the load torque. The higher the load torque, lower would be the frequency . Excessive load torque may occur in motors due to the cutting forces in machine tools . Hence this system is more suitable for cases where the tool force does not exist (Example : laser cutting) . Work table Pulse train a stepping motor Lead screw Figure 9. Open loop control system The stepping motor is driven by a series of electrical pulses generated by the MCU . Each pulse causes the motor to rotate a fraction of one revolution. The fraction is expressed in terms of the step angle, oc, given by a = 360/N, degrees where N = number of pulses required for one revolution If the motor receives "n" number of pulses then the total angle, A = n (360/N), degrees In terms of the number of revolutions, it would be (n/N) If there is a 1 :1 gear ratio between the motor and the leadscrew, then the leadscrew has (n/N) revolutions . If the pitch of leadscrew is p (in/rev), then the distance traveled axially, say x, x = p(n/N) can be used to achieve a specified x-increment in a point-to-point system. 10
  • 9. The pulse frequency, f, in pulses/sec determines the travel speed of the tool or the workpiece . 60 f = N (RPM) where N = number of pulses per revolution, RPM = RPM of the lead screw The travel speed, V, is then given by V = p (RPM) where p pitch in in/rev Example 3 A stepping motor has N = 150, p = 0.2"/rev ; If n = 2250 pulses, what is the distance traveled in x-direction ? What should be the pulse frequency for a travel speed of 16 in./min ? x = (0.2) (2250)/150 = 3" 16'= 0 .2 (RPM), from which, RPM = 80 f = (150) (80)/60 = 200 Hz Example 4 A stepping motor of 200 steps per revolution is mounted on the leadscrew of a drilling machine. If the pitch is 0.1 in/rev., a. What is the BLU ? b. If the motor receives a pulse frequency of 2000 Hz, what is the speed of the table ? a. BLU = 0 .1/200 = 0.0005" b. Table speed = (p) (RPM) = (0 .1) (60) (2000)/200 = 60 in/min Closed-loop Control Systems Closed -loop NC systems are appropriate when there is a force resisting the movement of the tool/workpiece . Milling and turning are typical examples . In these systems (Figure 10) the DC servomotors and feedback devices are used to ensure that the desired position is achieved . The feedback sensor used is an optical encoder shown in Figure 11 . The encoder consists of a light source, a photodetector, and a disk containing a series of slots. The encoder is connected to the leadscrew . As the screw turns, the slots cause the light to be seen by the
  • 10. photodetector as a series of flashs which are converted into an equivalent series of electrical pulses which are then used to characterize the position and the speed. The equations remain essentially the same as open-loop except that the angle between the slots in the disk is the step angle, a. Both the input to the control loop and the feedback signals are a sequence of pulses, each pulse representing a BLU unit. The two sequences are correlated by a comparator and gives a signal, by means of a digital-to-analog converter, (a signal representing the position error), to operate the drive motor (DC servomotor) . Work table Input do Comparator DAC Gear servomotor Position Feedback signal sensor Figure 10. Closed loop control system Signal pulses Photocell Time (a) (b) Figure 11 . Optical Encoder (a) Device (b) Series of pulses emitted 12
  • 11. Example 5 Consider a CNC worktable driven by a closed-loop control system consisting of a servomotor, leadscrew, and optical encoder. The leadscrew has a pitch, p = 0.2" and is coupled to the motor shaft with a screw to motor gear ratio of 1 :4. The encoder generates 150 pulses per revolution of the leadscrew. If the number of pulses and the pulse rate received by the control system are 2250 and 200 Hz respectively, calculate a. Table speed b. Motor speed in RPM c. Distance traveled by the table a. V= p(RPM) = 0 .2(RPM) = (0 .2) (60 f)/N = (0 .2) (60) (200)/150 = 16 in/min b. RPM of the leadscrew = (60) (200)/(150) = 80 RPM of the motor = 320 c. x = p(n/N) = (0.2) (2250)/150 = 3" Example 6 A do servomotor is coupled to a leadscrew which drives the table of a CNC machine tool. A digital encoder, mounted at the end of the screw, emits 500 pulses per revolution. If the pitch is 5 mm per rev, and the motor rotates 600 rpm (1 :1 gear ratio), calculate the a. Table speed b. BLU c. Frequency of pulses transmitted by the encoder a. V= p(RPM) = 5 (600) = 3000 mm/min = 3 m/min b. BLU = 5/500 = 0.01 mm c. RPM = 600 = (60f)/N = 60 f/500 from which f = 5000 Hz 13
  • 12. PRECISION IN CNC MACHINING The combined characteristics of the machine tool and the control determine the precision of positioning . Three critical measures of precision are : o Resolution o Accuracy o Repeatability Control resolution (BLU) is the distance separating two adjacent points in the axis movement (the smallest change in the position) . The electromechanical components of the positioning system that affect the resolution are the leadscrew pitch, the gear ratio, and the step angle in the stepping motor (open loop) or the angle between the slots in the encoder (closed-loop). The control resolution for a 1 :1 gear ratio of a stepped motor is, Resolution = p/N where p = pitch, and N = 360/a Features smaller than the control resolution could not be produced . The programming resolution can not exceed the control resolution . Accuracy of a CNC system depends on the resolution, the computer control algorithms, and the machine inaccuracies . The inaccuracy due to the resolution is considered to be (1/2)BLU on the average. The control algorithm inaccuracy is due to the rounding off the errors in the computer which is insignificant. The machine inaccuracy could be due to several reasons (described below) . The designer minimizes this inaccuracy to be under (1/2)BLU and hence Accuracy = (1/2) Resolution + Machining inaccuracy = BLU Repeatability is a statistical term associated with accuracy . It refers to the capability of a positioning system to return to a programmed point, and is measured in terms of the errors associated with the programmed point. The deviation from the control point (error) usually follows a normal distribution in which case the repeatability may be given as +/- 3a where a is the standard deviation. The repeatability is always better than the accuracy . The mechanical inaccuracy can be considered as the repeatability . Figure 12 shows the difference between the accuracy and the repeatability . Machining Inaccuracy Cutting tool deflection, machine tool chatter, mechanical linkage between the leadscrew and the tool, and thermal deformations are the chief contributing factors . The leadscrew transmits the power to the table or toolholder by means of a nut that engages the leadscrew . This will create what is known as "backlash"due to the friction between the screw and the nut. If the nut consists of ball bearings, the friction is reduced . Thermal deformations are significant. For example, a temperature difference of 1 °C along 1000 mm can cause an error of 0.01 mm. 14
  • 13. EMEMOMME MOMEMENN MMMMMMMM MEME ME"O MEN"E""" MMOMMOME s ONNEEMEN EMOMMEN IMMEMENE MENNOMME EMMMOMME M"MM IMSN ME MEN .... .... ...LO... MI No MEMM EME" MMMMMMMM MMEMEMEN MOMMOMME M"""M"N MEMEMMEN """" MM"" Low Accuracy Low Accuracy High Accuracy Low Repeatability High Repeatability High Repeatability Figure 12. Diagram showing the difference between accuracy and repeatability Example 7 What is the control resolution for a 4 :1 gear ratio (motor: leadscrew), pitch of leadscrew 0.2 in/rev, and the motor receives 600 pulses per revolution Since the motor shaft rotates 4 times faster than the leadscrew, N = 600/4 = 150 Resolution = 0.2/150 = 0.001333" What would be the accuracy and repeatability if the machining inaccuracy is about (1/2)BLU ? Accuracy = 0.001333/2 + 0 .001333/2= 0.001333" Repeatability = +/- 0.00067" 15
  • 14. PART PROGRAMMING FOR CNC The transfer of an engineering blueprint of a product to a part program can be performed manually using a calculator or with the assistance of a computer language . A part programmer must have an extensive knowledge of the machining processes and the capabilities of the machine tools . In this section, we describe how the part programmers execute manually the part programs. First, the machining parameters are determined . Second, the optimal sequence of operations is evaluated . Third, the tool path is calculated . Fourth, a program is written. Each line of the program, referred to as a block, contains the required data for transfer from one point to the next. A typical line for a program is given below . N100 G91 X -5.0 Y7 .0 F100 S200 T01 M03 (EOB) The significance of each term is explained below . Sequence Number, N Consisting of typically three digits, its purpose is to identify the specific machining operation through the block number particularly when testing a part program. Preparatory Function, G It prepares the MCU circuits to perform a specific operation . The G-codes (some) are shown in Table 1 . G91 implies incremental mode of operation. Dimension Words 1. Distance dimension words, X,Y,Z 2. Circular dimension words, I,J,K for distances to the arc center 3. Angular dimensions, A,B.C While (1) and (3) are expressed either by incremental or absolute mode, (2) is always in given in incremental mode. All angular dimensions are specified in revolutions or degrees. In the above block, X moves a distance of 5 in. in the negative direction while Y moves a distance of 7 in. in the positive direction. Other axes remain stationary. In some systems, actual distances are used. In others, the dimension words are programmed in BLUs . 16
  • 15. Feedrate, F It is expressed in in/min or mm/min and, is used in contouring or point-to-point or straight-cut systems . For example, a feedrate of F100 implies 100 in/min or 100 mm/min . Feedrates are independent of spindle speed. In linear motions, the feedrate of the cutting tool is not corrected for the cutter radius . But in circular motions, the feedrate should be corrected for the tool radius as follows : F = [(part contour radius ± tool radius)/part contour radius] (required feedrate) For cutting around the outside of a circle, the plus sign in the above equation is used, and the feedrate is increased. For cutting around the inside of a circle, the minus sign is used, and the feedrate is decreased . Example 8 See Figure 5(a). If the required feedrate is 6 in/min, part contour radius is 1 .5 in, and the cutter diameter is 1 in, what is the feedrate athe top and bottom circles ? Feedrate at the top is to be 8 in/min and at the bottom is to be 4 in/min. Spindle speed, S Programmed in rev/min, it is expressed as RPM or by a three-digit code number that is related to the RPM. Toolword, T Consisting of a maximum of five digits, each cutting tool has a different code number. The tool is automatically selected by the automatic tool changer when the code number is programmed in a block. Miscellaneous Function, M Consisting of two digits, this word relates to the movement of the machine in terms of spindle on/off, coolant on/off etc shown in Table 2. EOB The EOB character is used at the end of each block to complete a line. 17
  • 16. Table . .1 Preparatory commands (G-code) G00 Point-to-point positioning G01 Linear interpolation G02 Clockwise circular interpolation G03 Counter-clockwise circular interpolation G04 Dwell G05 Hold G33 Thread cutting, constant lead G40 Cancel tool nose radius compensation G41 Tool nose radius compensation - left G42 Tool nose radius compensation - right G43 Cutter length compensation G44 Cancel cutter length compensation G70 Dimensions in inches G71 Metric dimensions G90 Absolute dimensions G91 Incremental dimensions G92 Datum offset Table . .2 Miscellaneous commands (M-code) M00 Program stop M01 Optional stop M02 End of program M03 Spindle start clockwise M04 Spindle start counter-clockwise M05 Spindle stop M06 Tool change M07 Mist coolant on M08 Flood coolant on M09 Coolant off M10 Clamp Mll Unclamp M13 Spindle clockwise, coolant on M14 Spindle counter-clockwise, coolant on M30 End of tape, rewind Tables 1 and 2 : G and M codes used in CNC systems 18
  • 17. 4-7-2 G Functions (SEICOS-MII) G code Group Function GOO Positioning (rapid traverse) GO1 Linear interpolation (cutting feed) . 01 G02 Circular interpolation CW G03 Circular interpolation CCW G04 Dwell G07 00 SIN interpolation (designation of virtual axis) G09 Exact stop check G10 Offset amount and work zero point offset amount setting G17 Designation of X-Y plane G18 02 Designation of Z-X plane G19 Designation of Y-Z plane G20 06 Inch input G21 Metric input; G22 Stored stroke, limi t,ON 04~ G23 Stored'--s troke"- limit OFF G27 Return to reference paint G28 Return to reference-pant:_-_. .. G29 00 Return from reference point `' G30 Return to 2nd reference point 4 G31 Skip function G40 07 Tool diameter compensation cancel G41 Tool diameter compensation to left G42 Tool diameter compensation to right G43 Tool length compensation G44 08 Tool length compensation G49 Tool length compensation cancel G45 Tool offset expansion G46 00 Tool offset reduction G47 Tool offset double expansion G48 Tool offset double reduction G50 11 Scaling cancel G51 Scaling G codes with " " are set when the power is .turned on . G40, G49 and G80 are set by resetting the NC unit .
  • 18. G code Group Function G52 00 .Local coordinate system setting G53 Machine coordinate system selection G54 Work coordinate system 1 selection G55 12 Work coordinate system 2 selection G56 Work coordinate system 3 selection G57 Work coordinate system 4 selection G58 Work coordinate system 5 selection G59 Work coordinate system .6 selection G60 00 I One directional positioning G61 Exact stop check mode G63 13 I Tapping mode G64 Continuous cutting mode G65 00 Macro call G66 14 Macro modal call A G67~ C Macro modal call cancel G73 + Pec k dri l ling cycle G74 Reverse tapping cycle G76 I Fine boring G80 ` Canned cycle cancel G81' Dr illing cycle, sp ot boring G82 Drilling cycle, counter boring G83 09 Peck drilling cycle G84 ( Tapping cycle G85 Boring cycle G86 I Boring cyc le r G87 Back boring cycle -'" G88 Boring cycle G89 I Boring cycle G90 03 L Absolute programming G91 Incremental programming G92 00 Programming of absolute zero point G98 10 I Initial level return (canned cycle) G99 R point level return (canned cycle) G501 15 Programmable mirror image cancel G511 Programmable mirror image 4 - 30
  • 19. 4-7-3 M Functions (* : Optional function) M I Function name M Function name Idle cutting time reduction 00 Program stop *33 (modal) (Idle cutting time reduction 01 Optional stop *34 (unmodal) 02 End of program *35 Automatic start ON 03 (Spindle forward *36 Automatic start OFF 04 Spindle reverse *37 Spindle no-load detect function 05 (Spindle stop *38 stop 06 Tool change ATC *39 M38 cancel *07 Mist coolant start *40 Tool nose air blow ON 08 Flood coolant start *41 Tool nose air blow OFF 09 (Mist coolant stop *42 *10 Mist coolant attitude 1 *43 *11 Mist coolant attitude 2 *44 *12 Work count *45 Spare tool offset enabled 13 Spindle forward & coolant start ''*46 (Spare tool offset disabled 14 Spindle reverse & coolant start *47 Jet coolant start 15 M13/M14 stop 48 (Feed rate override enabled *16i Measurement air blow ON 49 Feed rate override 100% *17 Measurement air blow OFF *50 Oil hole coolant start *18~ Measuring spindle orientation *51 19 Spindle orientation *52 Tool breakage detect *20~ Machining time monitoring *53 *21 *54 *22 *55 *23 *56 *24 *57 *25 *58 *26 Melodia (1) *59 *27 Melodia (2) *60 Work change APC *28 Setting load level 0 *61 *29 Setting load level 1 *62 30 End of tape *63 *31 Chip conveyor start *641 *32 M33 cancel *65
  • 20. M Function name M Function name *66 *67 *68 Additional axis clamp *69 Additional axis unclimp *70 M70 output *71 M71 output *72 M72 output *73 M73 output *74 Skip selection OFF *75 Skip selection ON *76 . *77 *78 Additional axis clamp *79 Additional axis unclamp *80 Tool nose air blow ON *81 *82 i *83 *84 *85 Measurement NG tool breakage *86 detect *87 *90 *91 *92 *93 *94 *95 *96 *97 98 Subprogram call 99 End of subprogram 4- 3 2
  • 21. M Maintenance mode *1001 Arm swing-in to spindle side *101 *102. Arm advance *103 Arm turn CW *104 Arm turn CCW *105 Arm retract *106 Arm slide to home position__ *107 *108 Arm slide to magazine side *109 *110 *111 *112 *113 *114 *115 *116 *117 *118 *119 Orientation *120 Magazine positioning pin OUT *121 Magazine positioning pin IN 1 *122 *123, *124 Pallet slider advance (APC) *125 Pallet unclamp (APC) *1261 Pallet slider retract (APC) *1271 Pallet right turn (APC) *128 Pallet left turn (APC) - 1 *129 Pallet unclamp (APC) 4-33