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T3 magnetic circuits

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T3 magnetic circuits

  1. 1. ELE101 / 102 Dept of E & E Engg, MIT Manipal 1 Tutorial [1] A circular iron ring has a mean circumference of 1.5m and a cross sectional area of 0.01m2 . A saw cut of 4mm wide is made in the ring Calculate the magnetizing current required to produce a flux of 0.8mWb in the air gap if a ring is wound with a coil of 175 turns. Assume μr = 400, λ = 1.25 What is the current required if the leakage flux is neglected? Ans: 3.156 A, 2.816 A
  2. 2. ELE 101 / 102 Dept of E & E Engg, MIT Manipal 2 [2] A steel ring 10 cm mean radius and of circular cross-section 1 cm in radius has an air gap of 1 mm length. It is wound uniformly with 500 turns of wire carrying current of 3 A. The air gap takes 60 % of the total MMF. Neglecting magnetic leakage find the total reluctance 4.22178 × 106 AT / Wb Tutorial
  3. 3. ELE 101 / 102 Dept of E & E Engg, MIT Manipal 3 [3] The magnetic frame shown in figure is built up of iron of square cross section of 3 cm side and each air gap is 2 mm wide. Each of the coil has 1000 turns and the exciting current is 1 A. The µr of part A and part B may be taken as 1000 and 1200 respectively. Calculate (i) Reluctance of part A (ii) Reluctance of part B (iii) Reluctance of air gaps (iv) Total Reluctance of complete magnetic circuit (v) MMF produced and (vi) Flux set up in the circuit PART A PART B 3 cm 10 cm 2 mm 3 cm 20 cm Tutorial 0.17684 × 106 AT / Wb, 0.2505 × 106 AT / Wb, 3.537 × 106 AT / Wb, 3.9643 × 106 AT / Wb, 2000 AT, 0.5045 mWb
  4. 4. ELE 101 / 102 Dept of E&E MIT Manipal 1 Tutorial [4] A magnetic circuit made of silicon steel is as shown. The central limb has a cross sectional area of 800 mm2 and a coil of 500 turns. Each of the side limbs has an area of 500 mm2 . Calculate the magnetizing current required to produce a flux of 1 mWb in the 1 mm air gap if μr=1000, length BE = 150 mm; length BAGIDE = length BCHJFE = 250 mm. Assume a leakage factor of 1.2 1mm 5mm A B C D E F G H I J ANS: 4.58 A
  5. 5. ELE 101 / 102 Dept of E & E Engg, MIT Manipal 5 Tutorial Φ 1 Φ2 Φ3 A B C DE F [5] A 710 turns coil is wound on the central limb of the cast steel symmetrical frame of uniform cross section 16 cm2 is as shown. Calculate the current required to produce a flux of 1.8 mWb in an air gap of 0.2 cm length. Given lAFEB = lACDB = 25 cm, lAB = 12.5 cm. The magnetization details is as follows H 300 500 600 700 900 1092 B 0.1 0.45 0.562 0.775 1 1.125 Ans: I = 2.92 A
  6. 6. ELE 101 / 102 Dept of E & E Engg, MIT Manipal 5 Tutorial Φ 1 Φ2 Φ3 A B C DE F [5] A 710 turns coil is wound on the central limb of the cast steel symmetrical frame of uniform cross section 16 cm2 is as shown. Calculate the current required to produce a flux of 1.8 mWb in an air gap of 0.2 cm length. Given lAFEB = lACDB = 25 cm, lAB = 12.5 cm. The magnetization details is as follows H 300 500 600 700 900 1092 B 0.1 0.45 0.562 0.775 1 1.125 Ans: I = 2.92 A

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