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Rumus Matematik Tambahan
ALGEBRA
1
2
4
2
b b ac
x
a
  

2 am
 an
= a m + n
3 am
 an
= a m - n
4 (am
)n
= a mn
5 loga mn = log am + loga n
6 loga
n
m
= log am - loga n
7 log a mn
= n log a m
8 logab =
a
b
c
c
log
log
9 Tn = a + (n – 1)d
10 Sn = ])1(2[
2
dna
n

11 Tn = ar n-1
12 Sn =
r
ra
r
ra nn




1
)1(
@
1
)1(
, r  1
13
r
a
S


1
, r <1
CALCULUS
1 y = uv ,
dx
du
v
dx
dv
u
dx
dy

2
v
u
y  , 2
v
dx
dv
u
dx
du
v
dx
dy

 ,
3
dx
du
du
dy
dx
dy

4 Area under a curve
= 
b
a
y dx or
= 
b
a
x dy
5 Volume generated
= 
b
a
y2
 dx or
= 
b
a
x2
 dy
5 A point dividing a segment of a line
(x, y) = ,21





nm
mxnx





nm
myny 21
6 Area of triangle =
)()(
2
1
312312133221 1
yxyxyxyxyxyx 
1 Distance = 2 2
2 1 2 1( ) ( )x x y y  
2 Midpoint
(x , y) = 

 
2
21 xx
, 


2
21 yy
3 22
yxr 
4
2 2
xi y j
r
x y



GEOMETRY
RUMUS KUADRATIK
HUKUM INDEKS
HUKUM LOG
TUKAR ASAS LOG
SEBUTAN KE-(N) J.A
HASIL TAMBAH J.A
HASIL TAMBAH
KETAKTERHINGGAAN
SEBUTAN KE-(N) J.G
HASIL TAMBAH J.G
PEMBEZAAN
PETUA RANTAI
LUAS BAWAH LENGKUNG
PADA PAKSI-X
LUAS BAWAH LENGKUNG
PADA PAKSI-Y
ISIPADU JANAAN PADA
PAKSI-X
ISIPADU JANAAN PADA
PAKSI-Y
JARAK ANTARA DUA TITIK
TITIK TENGAH ANTARA DUA TITIK
MAGNITUDE VECTOR
UNIT VECTOR
LUAS SEGITIGA
TITIK YANG MEMBAHAGI ANTARA DUA TITIK
GABAN CYBER
3472/1
3472/1
STATISTICS
1 Arc length, s = r
2 Area of sector, A = 21
2
r 
3 sin 2
A + cos 2
A = 1
4 sec2
A = 1 + tan2
A
5 cosec2
A = 1 + cot2
A
6 sin 2A = 2 sinA cosA
7 cos 2A = cos2
A – sin2
A
= 2 cos2
A – 1
= 1– 2 sin2
A
8 tan 2A =
A
A
2
tan1
tan2

TRIGONOMETRY
9 sin (A B) = sinA cosB  cosA sinB
10 cos (A  B) = cosA cosB  sinA sinB
11 tan (A  B) =
BA
BA
tantan1
tantan


12
C
c
B
b
A
a
sinsinsin

13 a2
= b2
+ c2
– 2bc cosA
14 Area of triangle = Cabsin
2
1
1 x =
N
x
2 x =


f
fx
3  =
N
xx  2
)(
=
2_2
x
N
x


4  =

 
f
xxf 2
)(
=
2
2
x
f
fx



5 m = C
f
FN
L
m













 2
1
6 1
0
100
Q
I
Q
 
7


w
w
i
iiI
I
8
)!(
!
rn
n
Pr
n


9
!)!(
!
rrn
n
Cr
n


10 P(A B)=P(A)+P(B)–P(A B)
11 P(X=r) = rnr
r
n
qpC 
, p + q = 1
12 Mean, µ = np
13 npq
14 z =

x
LUAS SEGITIGA
PANJANG SISI @
LUAS SUDUT BAGI
SEGITIGA
HASIL
TAMBAH
& HASIL
TOLAK
TRIGONO
METRI
SUKATAN
MEMBULAT
P/LENGKUK
SUDUT
JEJARI
LUAS
SEKTOR
BULATAN
NOMBOR INDEK
@INDEK HARGA
MEDIAN
NILAI -Z
SISIHAN PIAWAI
MIN
INDEK KOMPOSIT
PILIHATUR
KOMBINASI
MIN
SISIHAN
PIAWAI
TABURAN BINOMIAL
KEBARANGKALIAN
IDENTITI
TRIGONOMETRI
SUDUT
BERGANDA
GABAN CYBER

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Rumus matematik-tambahan

  • 1. 1 3472/1 3472/2 Rumus Matematik Tambahan ALGEBRA 1 2 4 2 b b ac x a     2 am  an = a m + n 3 am  an = a m - n 4 (am )n = a mn 5 loga mn = log am + loga n 6 loga n m = log am - loga n 7 log a mn = n log a m 8 logab = a b c c log log 9 Tn = a + (n – 1)d 10 Sn = ])1(2[ 2 dna n  11 Tn = ar n-1 12 Sn = r ra r ra nn     1 )1( @ 1 )1( , r  1 13 r a S   1 , r <1 CALCULUS 1 y = uv , dx du v dx dv u dx dy  2 v u y  , 2 v dx dv u dx du v dx dy   , 3 dx du du dy dx dy  4 Area under a curve =  b a y dx or =  b a x dy 5 Volume generated =  b a y2  dx or =  b a x2  dy 5 A point dividing a segment of a line (x, y) = ,21      nm mxnx      nm myny 21 6 Area of triangle = )()( 2 1 312312133221 1 yxyxyxyxyxyx  1 Distance = 2 2 2 1 2 1( ) ( )x x y y   2 Midpoint (x , y) =     2 21 xx ,    2 21 yy 3 22 yxr  4 2 2 xi y j r x y    GEOMETRY RUMUS KUADRATIK HUKUM INDEKS HUKUM LOG TUKAR ASAS LOG SEBUTAN KE-(N) J.A HASIL TAMBAH J.A HASIL TAMBAH KETAKTERHINGGAAN SEBUTAN KE-(N) J.G HASIL TAMBAH J.G PEMBEZAAN PETUA RANTAI LUAS BAWAH LENGKUNG PADA PAKSI-X LUAS BAWAH LENGKUNG PADA PAKSI-Y ISIPADU JANAAN PADA PAKSI-X ISIPADU JANAAN PADA PAKSI-Y JARAK ANTARA DUA TITIK TITIK TENGAH ANTARA DUA TITIK MAGNITUDE VECTOR UNIT VECTOR LUAS SEGITIGA TITIK YANG MEMBAHAGI ANTARA DUA TITIK GABAN CYBER
  • 2. 3472/1 3472/1 STATISTICS 1 Arc length, s = r 2 Area of sector, A = 21 2 r  3 sin 2 A + cos 2 A = 1 4 sec2 A = 1 + tan2 A 5 cosec2 A = 1 + cot2 A 6 sin 2A = 2 sinA cosA 7 cos 2A = cos2 A – sin2 A = 2 cos2 A – 1 = 1– 2 sin2 A 8 tan 2A = A A 2 tan1 tan2  TRIGONOMETRY 9 sin (A B) = sinA cosB  cosA sinB 10 cos (A  B) = cosA cosB  sinA sinB 11 tan (A  B) = BA BA tantan1 tantan   12 C c B b A a sinsinsin  13 a2 = b2 + c2 – 2bc cosA 14 Area of triangle = Cabsin 2 1 1 x = N x 2 x =   f fx 3  = N xx  2 )( = 2_2 x N x   4  =    f xxf 2 )( = 2 2 x f fx    5 m = C f FN L m               2 1 6 1 0 100 Q I Q   7   w w i iiI I 8 )!( ! rn n Pr n   9 !)!( ! rrn n Cr n   10 P(A B)=P(A)+P(B)–P(A B) 11 P(X=r) = rnr r n qpC  , p + q = 1 12 Mean, µ = np 13 npq 14 z =  x LUAS SEGITIGA PANJANG SISI @ LUAS SUDUT BAGI SEGITIGA HASIL TAMBAH & HASIL TOLAK TRIGONO METRI SUKATAN MEMBULAT P/LENGKUK SUDUT JEJARI LUAS SEKTOR BULATAN NOMBOR INDEK @INDEK HARGA MEDIAN NILAI -Z SISIHAN PIAWAI MIN INDEK KOMPOSIT PILIHATUR KOMBINASI MIN SISIHAN PIAWAI TABURAN BINOMIAL KEBARANGKALIAN IDENTITI TRIGONOMETRI SUDUT BERGANDA GABAN CYBER