Hi

1. †Mvovb Av`k© D”P we`¨vjq
†kªYx: 5g
cvV¨m~Px: 2018
welqt evsjv
wba©vwiZ eBt
(1) evsjv Avgvi eB -‡evW© K©Z„K cªKvwkZ
(2) †mvbvgwb‡`i e¨vKiY I wbwg©Z
cÖkœaviv gvbe›Ub:
*cÖ`Ë Aby‡”Q` / KweZv / Qov (cvV¨eB †_‡K ) c‡o
1‡_‡K 4 µwgK ch©šÍ cÖ‡¤œi DËi wjLb |
1. eûwbev©Pwb cÖkœ: (5wU) 15= 5
2. cÖ‡kœi DËi wjLb: (3wU) 1+1+1=3
3. kãv_© wjLb: (4wU) 4
4.Aby‡”Q` /KweZv s‡ki g~jfve wjLb t 1wU 3
* cÖ`Ë Aby‡”Q` /KweZvsk (cvV¨eB ew&nf©~Z ) c‡o 5,6 I
7 bs
µwgK cÖ‡kœi DËi _vK‡e |
5. mwVK DËic‡Î wjLb(†hvM¨Zv wfwËK 5wU eûwbev©Pbx
cÖkœ _vK‡e) 15=5
6. cÖ`Ë k‡ãi A_© ey‡S k~Y¨¯’vb c~iY KiY
(‡hvM¨Zv wfwËK 5wU k~Y¨¯’&vb _vK‡e)
25=10
7. Aby‡”Q` c‡o cÖkœ¸‡jvi DËi wjLb /eywS‡q wjLb
(‡hvM¨ZvwfwËK 3wU cÖkœ _vK‡e GeÖs cÖwZwUi DËi
wjL‡Z n‡e ) 53=15
8. hy³eY© wefvRb I ev‡K¨ cÖ‡qvM (†hvM¨ZvwfwËK )
25=10
9. ‡KvbwU †Kvb c` Zv wjLb (‡hvM¨ZvwfwËK )
25=10
10. GKK_vq cÖKvk (5wU )/ wµqvc‡`i PwjZiƒc wjLb | (5wU
‡hvM¨ZvwfwËK ) 5
11. wecixZ / mgv_©K kã wjLb (5wU )|
5
12.KweZvi PiY mvwR‡q wjLb Ges KweZv, Kwei bvg
&cÖ‡kœvËi wjLb
K) KweZvi PiY¸‡jv mvwR‡h ‡j_v- 3
L) KweZvskUzKz †Kvb KweZvi Ask-
1.5
M) KweZvwUi Kwei bvg-
1.5
cÂg # cvZv-1

2. N) KweZvsk n‡Z cÖkœ (1wU)- A_ev weivg wUý ewm‡q
Aby‡”Q`wU cybivq ‡jL- 1
13. dig c~iY KiY (†hvM¨ZvwfwËK ) 5
14.`iLv¯Í / wPwV wjLb(†hvM¨ZvwfwËK)
15. iPbv wjLb ( 4wU iPbv ‡`Iqv _vK‡e Gi g‡a¨ 1wUi DËi
w`‡Z n‡e |
BwC‡Z †`Iqv _vK‡e | (200 k‡ãi g‡a¨ wjL‡Z n‡e|)
(†hvM¨ZvwfwËK) 10
‡gvU = 100
1g ‡kªYx cixÿv-10
M`¨vsk c`¨vsk
1) GB †`‡k GB gvbyl 1) msKí
2) my›`i e‡bi cÖvYx
1g wgWU©vg cixÿv -40
M`¨vsk c`¨vsk
3) nvwZ Avi †kqv‡ji Mí 2) dzUej †L‡jvqvi
4) ex‡ii i‡³ ¯^vaxb G †`k 3) †deªæqvwii Mvb
5) k‡Li g„rwkí 4) kã `~lY
e¨vKib t c` , GK K_vq cÖKvk
iPbv t 1) wkÿv¸iæi gh©v`v, 2) wcÖq FZz|
Aa©evwl©K cixÿv-100
M`¨vsk c`¨vsk
6) ¯§iYxq hviv wPiw`b 5) ¯^‡`k
7) KvÂbgvjv Avi KvKubgvjv 6) Nvm dzj
8) gvwUi wb‡Pi †h kni 7) wkÿv¸iæi gh©v`v
9) AevK Rjcvb
10) fveyK †Q‡jwU
* e¨vKiY t hy³eY©, c`, GK K_vq cÖKvk, wecixZ kã,
mgv_©K kã, wµqvc‡`i PwjZ iƒc , weivg
wPý|
*wPwV / `iLv¯Í t ‡kÖYx cvV`vb Abyhvqx|
*dig c~iYKiY t ‡hvM¨ZvwfwËK|
cÂg # cvZv-2

3. * iPbv t
3) k‡Li grwkí, 4) we¯§qKi cÖvY x RMr
5) GKRb exi gyw³‡hv×v 6) my›`i e‡bi cÖvYx
7) ¯§ibxq hviv wPiw`b, 8) Avgv‡`i GB †`k
9) evsjv‡`‡ki cyivKx©wZ , 10) GKwU
HwZnvwmK ¯’vb
11) we`vq nR¡, 12) gvIjvbv Ave`yj nvwg` Lvb
fvmvbx|
2q †kÖwY cvixÿv -10
M`¨vsk c`¨vsk
1) we`vq nR¡ 1) `yB Zxi
2) †`‡L Gjvg bvqvMÖv
2q wgWUvg© cixÿv -40
M`¨vsk c`¨vsk
13) gvIjvbv Ave`yj nvwg`
fvmvbx
9) †iŠ`ª ‡j‡L Rq |
14) kwn` wZZygxi
15) A‡cÿv
e¨vKiYt Aa©evwl©K cixÿvi cyYiv‡jvPbv|
iPbvt 13) knx` wZZygxi, 14) QvÎ Rxeb, 15) elv©©Kvj
PyivšÍ g‡Wj †U÷ cixÿv -100
iPbvt
16) evsjv‡`‡ki gyw³‡hv×, 17) ‡Zvgvi wcÖq kL 18)
Kw¤úDUvi,
19) Aa¨vemvq, 20) Avgvi wcÖq Kwe, 21) ¯^‡`k ‡cªg, 22)
eB ‡gjv,
23) ‰kke ¯Í…wZ, 24) †Zvgvi †cvlv cÖvYx, 25) my›`i eb|
wet `ªt †evW© KZ©„K wba©vwiZ cvV¨ eB‡qi m¤ú~Y©
wm‡jevm
cÂg cvZv-3

4. Goran Adarshaw High School
Class five
Subject: English
 Selected Book: English for Today
- By Board.
 Scholarship Foundation English
- By Md. Nasser Uddin & Md. Abul Hossin .
Distribution of marks:
Read the text and answer the questions 1, 2, 3 and 4.
1. Multiple choice questions 10
2. Matching / Fill in the blanks. 05
3. Answering questions 10
4. Short Composition. 10
Read the text and answer the questions 5,6,7,8 and 9
(This text will not be taken from English for Today) 5
Multiple choice questions 10
6. Fill in the blanks with the given words. 05
7. Answering short questions. 10
8. Personal Letter . 10
9.Making Wh questions. 10
10. Answering questions (competency based ). 1+2+3=6
11. Short question or Fill in the gaps
(by using information) 05
12. Rearrange 05
13. Fillings the forms 04
Total= 100
cÂg cvZv-4
N.B. Name of the Exam & Topes to be read.
1st
class Test - 10 Marks
Modal Question: 1-3 ( Q . No . 2.4.9.12.13)
1st
Mid Term - 40 Marks
Model Questions : 4-6( Q.No.3.9.10.11.12.13)
Half –Yearly Exam -100 Marks
English for Today –( Unit-1-20)
Model Question:1-10
Name of Exam and Topics to be read
2nd
class Test -10 Marks
Modal Questions: Spring Day, Laila and Bithe .
2nd
Mid Term - 40 Marks .
Modal Question :Cyclone Ayla , Liberation War Museum ,
The Olympic Games, Birthday Party .
Modal Test :
English for Today : Unit (21-25).
Whole PEC syllabus.
welqt MwYZ
wba©vwiZ eBt MwYZ- (†evW© eB)
cÖkœaviv I gvbe›Ub t
1) eû wbe©vPbx cÖkœ (24wU cÖkœ _vK‡e, hvi g‡a¨ 1g
20wU n‡e †hvM¨ZvwfwËK ) 124=24
2) mswÿß cÖ‡kœi DËi (10wU
cÖkœ _vK‡e , hvi g‡a¨ cª_g 4wU n‡e ‡hvM¨ZvwfwËK)|
110=10

5. 3) Pi cÖwµqv m¤úwK©Z
mgm¨vewj (2wU cÖkœ _vK‡e ,hvi g‡a¨ 1wU n‡jv
‡hvM¨ZvwfwËK | 8
4) j,mv,¸,I M,mv,My (2wU cÖkœ _vK‡e , hvi g‡a¨ 1wU
n‡jv ‡hvM¨ZvwfwËK | 8
5)mvaviY fMœvsk m¤úwK©Z mgm¨v (2wU cÖkœ _vK‡e
, hvi g‡a¨ 1wU n‡jv ‡hvM¨ZvwfwËK|
8
6) Mo m¤úwK©Z mgm¨v (2wU cÖkœ _vK‡e , hvi g‡a¨
1wU n‡jv ‡hvM¨ZvwfwËK| 8
7) `kwgK fMœvsk / kZKiv m¤úwK©Z mgm¨v (2wU cÖkœ
_vK‡e , hvi g‡a¨ 1wU n‡jv
‡hvM¨ZvwfwËK| 8
8) R¨vwgwZ t K) wb‡`©kbv Abymv‡i wPÎ
AsKb | L) wPÎ mn ‰ewkó¨ wjLb (3wU
g‡a¨ 2wU DËi w`‡Z n‡e) 4+6=10
9) cwigvc m¤úwK©Z mgm¨v( 2wU cÖkœ _vK‡e , hvi g‡a¨
1wU n‡jv ‡hvM¨ZvwfwËK| 8
10) mgq/DcvË web¨vmKiY
m¤úwK©Z mgm¨v (2wU cÖkœ _vK‡e , hvi g‡a¨ 1wU
n‡jv ‡hvM¨ZvwfwËK| 8
‡gvU= 100
cvV¨ m~Px
‡kÖYx cixÿv -1g 40
1g n‡Z 3q Aa¨vq ch©šÍ |(3wU n‡Z 2wU )
3wU mvavib AsK _vK‡e 2wUi DËi w`‡Z n‡e (1g n‡Z 3q
Aa¨vq ch©šÍ)
1g wgWUvg© cixÿv-40
m„Rbkxj cÖ¤œ 5wU _vK‡e , 3wUi DËi w`‡Z n‡e
38=24
10wU eû wbev©Pbx _vK‡e 10wUi DËi w`‡Z n‡e 110=10
6wU mswÿß cÖkœ _vK‡e , 6wU DËi w`‡Z n‡e 16=6
(4_© Aa¨vq n‡Z 8g Aa¨vq ch©šÍ)
Aa©-evwl©K cixÿv -100
1g n‡Z 10g Aa¨vq ch©šÍ |
2q ‡kÖbx cixÿv -10
cÖ‡kœi aviv I gvbe›Ub t
1) 1g n‡Z 3q Aa¨vq ch©šÍ |
2) 5g n‡Z 8g Aa¨vq ch©šÍ |
2q wgWUvg© cixÿv -40
4_© n‡Z 10g Aa¨vq ch©šÍ |
1g g‡Wj †U÷-100
cvV¨eB‡qi me Aa¨vq
welqt evsjv‡`k I
wek¦cwiPq
wba©vwiZ eBt evsjv‡`k I wek¦cwiPq(‡evW© eB)
c~Y©gvb t 100
cÖ‡kœi aviv I gvbe›Ub
1) eûwbev©Pbx cÖkœ:( 50wU cÖkœ _vK‡e,40wU
‡hvM¨ZvwfwËK ) 150=50
2)mswÿß cÖkœ (15wU cÖkœ _vK‡e, 10wU n‡e
†hvM¨ZvwfwËK ) 115=15
3) KvVv‡gve× cÖkœ (10wU cÖkœ _vK‡e, 6wU n‡e
†hvM¨Zv
wfwËK Ges 1wU ‡h †Kvb DËi w`‡Z n‡e )|
57=35
‡gvU =100
1g ‡kªYx cixÿv-10

6. 1g Aa¨vq t Avgv‡`i gyw³hy×
2q Aa¨vq t e„wUk kvmb
1g wgWUv©g cixÿv -40
enywbev©Pbx cÖkœ 20wU 120=20
KvVv‡gve× cÖkœ 04wU 45=20
1g,2q,3q,4_©,5g Aa¨vq
Aa©-evwl©K cixÿv -100
1g Aa¨vq t Avgv‡`i gyw³hy×
2q Aa¨vq t weªwUk kvmb
3q Aa¨vq t evsjv‡`‡ki HwZnvwmK ¯’vb I wb`©kb
4_© Aa¨vq t Avgv‡`i A_©bxwZ ,K…wl I wkí
5g Aa¨vq t RbmsL¨v
6ô Aa¨vq t Rjevqy I `~‡hv©M
7g Aa¨vq t gvbevwaKvi
8g Aa¨vq t bvix-cyiæl mgZv
9g Aa¨vq t Avgv‡`i `vwqZ¡ I KZ©e¨
1g ‡kÖYx cixÿv -10
10g Aa¨vq t MYZvwš¿K g‡bvfve
11Zg Aa¨vq t evsjv‡`‡ki ÿz`ª b„-‡Mvwô
wØZxq wgWU©vg cixÿv40
10g Aa¨vq t MYZvwš¿K g‡bvfve
11Zg Aa¨vq t evsjv‡`‡ki ÿz`ª b„-‡Mvôx
12Zg Aa¨vq t evsjv‡`k I wek¦
(evwl©K / g‡Wj †U÷t m¤ú~b© eB cyb‡ivjvPbv)
welq t Bmjvg I ˆbwZK wkÿv
wba©vwiZ eBt
Bmjvg I ‰bwZK wkÿv(‡evW© eB cÖKvwkZ )
c~Y©gvb t100
cÖ‡kœi aviv I gvbe›Ub
1.eûwbev©Pbx cÖkœ (50wU cÖkœ _vK‡e , 50wUi DËi
w`‡Z n‡e ) 150=50
2. mswÿß cÖkœ (15wU cÖkœ _vK‡e , 10wUi DËi w`‡Z
n‡e ) 115=15
3. KvVv‡gve× cÖkœt(K,L,M,M mn †h †Kvb 7wUi DËi
w`‡Z n‡e)
2. mswÿß cÖkœ (15wU cÖkœ _vK‡e , 10wUi DËi w`‡Z
n‡e ) 115=15
3. KvVv‡gve× cÖkœt(K,L,M,M mn cÖkœ _vK‡e ,7wUi
DËi w`‡Z n‡e)57=35
‡gvU=100
1g †kªYx cixÿv -10
1g Aa¨vq t c„ôv bs -01 †_‡K 99 ch©šÍ |
2q Aa¨vq t c„ôv bs -22 †_‡K 38 ch©šÍ |
1g wgWUvg© cixÿv -40
1g Aa¨vq t c„ôv bs 01 †_‡K 09 ch©šÍ|
2q Aa¨vq t c„ôv bs -22†_‡K 38 ch©šÍ|
3q Aa¨vq t c„ôv bs -64 †_‡K 74 ch©šÍ|
Aa© -evwl©K cixÿv-100|
1g Aa¨vq t AvKvB` -wek¦vm (c„ôv bs -01 †_‡K 09
ch©šÍ)|
2q Aa¨vq t Bev`Z (c„ôv bs -22 †_‡K 38 ch©šÍ)|
3q Aa¨vq tAvLjvK ev PwiÎ I ‰bwZK g~j¨‡eva( c„ôvbs -
68 †_‡K74 ch©šÍ)|
4_© Aa¨vq tKziAvb gwR` wkÿv (c„ôv bs -91†_‡K 96
ch©šÍ)|
5g Aa¨vq t gnvbex (mvt) Gi Rxebv`k© I Ab¨vb¨
bweM‡Yi cwiPq( c„ôv bs -105 †_‡K 114 ch©šÍ|
2q ‡kªYx cixÿv -10
1g Aa¨vq t c„ôv bs -10 †_‡K 17 ch©šÍ|

7. 2q Aa¨vq t c„ôv bs -40 †_‡K 57 ch©šÍ|
2q wgWUvg© cixÿv -40
2q Aa¨vq t c„ôv bs -40 †_‡K 57 ch©šÍ
3q Aa¨vq t c„ôv bs -76 †_‡K 84 ch©šÍ
24_© Aa¨vq t c„ôv bs -97 †_‡K 101 ch©šÍ
PovšÍ g‡Wj †U÷ cixÿv-100
1g Aa¨vq t c„ôv bs -10 †_‡K 17 ch©šÍ
2q Aa¨vq t c„ôv bs -40 †_‡K 57 ch©šÍ
3q Aa¨vq t c„ôv bs -74 †_‡K 84 ch©šÍ
4_© Aa¨vq t c„ôv bs -97 †_‡K 101 ch©šÍ
5g Aa¨vq t c„ôv bs -115 †_‡K 131 ch©šÍ
cÖv_wgK weÄvb
wbav©wiZ eB t
cªv_wgK weÄvb ( †evW© eB cÖKvwkZ)
cyY©gvb t100
cÖ‡kœi aviv I gvbe›Ub
1.eûwbev©Pbx cÖkœ (50wU cÖkœ _vK‡e , 50wUi
DËi w`‡Z n‡e ) 150=50
2. mswÿß cÖkœ (15wU cÖkœ _vK‡e , 15wUi DËi
w`‡Z n‡e ) 115=15
3. KvVv‡gve× cÖkœt(K,L,M,M mn cÖkœ _vK‡e ,7wUi
DËi w`‡Z n‡e)
57=35
‡gvU =
100
1g †kÖYx cixÿv -10
cÖ_g Aa¨vq t Avgv‡`i cwi‡ek (c„ôv bs -2-8 ch©šÍ)
wØZxq Aa¨vq t cwi‡ek `~lY (c„ôv bs -9-14 ch©šÍ)
1g wgWUvg© cixÿv -40
cÖ_g Aa¨vq †_‡K 5g Aa¨vq ch©šÍ |(c„ôv bs 2-40 ch©šÍ)
Aa©- evwl©K cixÿv -100
6ô Aa¨vq †_‡K Øv`k Aa¨vq ch©šÍ (c„ôv bs -41‡_‡K
88ch©šÍ)
1g †kªYx cixÿv -10
·qv`k Aa¨vq t cÖvK…wZK m¯ú` (c„ôv bs 89-92 ch©šÍ )
PZy`©k Aa¨vq t RbmsL¨v I cÖvK…wZK cwi‡ek (c„ôv bs
93-97)
2q wgWUvg© cixÿv -2018Bs
6ô Aa¨vq t my¯’ Rxe‡bi Rb¨ Lv`¨ ch©šÍ (c„ôv bs -
41‡_‡K 46ch©šÍ)
7g Aa¨vq t ¯^v¯’ wewa ch©šÍ (c„ôv bs -47‡_‡K
52ch©šÍ)
&·qv`k Aa¨vq t cÖvK…wZK cwi‡ek (c„ôv bs -89 ‡_‡K
92ch©šÍ)
PZz`©k Aa¨vqt RbmsL¨v I cÖvK„wZK cwi‡ek | (c„ôv bs
-93‡_‡K 97 ch©šÍ)|
evwl©K/ g‡Wj †U÷ -100
m¤ú~b© eB |