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# Soal dan pembahasan un matematika smp 2014 paket 1

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Soal dan pembahasan un matematika smp 2014 paket 1

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### Soal dan pembahasan un matematika smp 2014 paket 1

1. 1. www.siap-osn.blogspot.com @ Agustus 2014 SD.A 2 SMPN 1 Tambelangan Soal dan Pembahasan UN MATEMATIKA SMP 2014 / Page 1 Download Soal dan Pembahasan UN Matematika SMP 2014 Untuk Paket Soal Lainnya di “ www.siap-osn.blogspot.com ”
2. 2. www.siap-osn.blogspot.com @ Agustus 2014 SD.A 2 SMPN 1 Tambelangan Soal dan Pembahasan UN MATEMATIKA SMP 2014 / Page 2 Download Soal dan Pembahasan UN Matematika SMP 2014 Untuk Paket Soal Lainnya di “ www.siap-osn.blogspot.com ” PAKET 1 www.siap-osn.blogspot.com 5 5 = 5 5 . 5 5 = 5 5 5 = 5 60 ∶ 5 = 60: 5 = 12 = 4 .3 = 4 . 3 = 2 3 64 5 6 = 26 5 6 = 26 . 5 6 = 25 = 32 𝑎𝑦𝑎𝑚 = 60 → 𝑝𝑒𝑟𝑠𝑒𝑑𝑖𝑎𝑎𝑛 𝑚𝑎𝑘𝑎𝑛𝑎𝑛 = 24 𝑕𝑎𝑟𝑖 𝑎𝑦𝑎𝑚 = 60 − 15 = 45 → 𝑝𝑒𝑟𝑠𝑒𝑑𝑖𝑎𝑎𝑛 𝑚𝑎𝑘𝑎𝑛𝑎𝑛 = 60 45 .24 = 32 𝑕𝑎𝑟𝑖 2 1 3 + 5 1 4 − 1 1 2 = 7 3 + 21 4 − 3 2 = 28 12 + 63 12 − 18 12 = 73 12 = 6 1 12
3. 3. www.siap-osn.blogspot.com @ Agustus 2014 SD.A 2 SMPN 1 Tambelangan Soal dan Pembahasan UN MATEMATIKA SMP 2014 / Page 3 Download Soal dan Pembahasan UN Matematika SMP 2014 Untuk Paket Soal Lainnya di “ www.siap-osn.blogspot.com ” 𝑏 = 𝑈9 − 𝑈5 9 − 5 = 20 − 8 4 = 12 4 = 3 𝑈10 = 𝑈9 + 10 − 9 . 𝑏 = 20 + 1 . 3 = 20 + 3 = 23 𝑏 = 𝑈7 − 𝑈3 7 − 3 = 38 − 18 4 = 20 4 = 5 𝑎 = 𝑈1 = 𝑈3 + 1 − 3 . 𝑏 = 18 − 2 . 5 = 18 − 10 = 8 𝑆𝑛 = 𝑛 2 . 2𝑎 + 𝑛 − 1 . 𝑏 𝑆24 = 24 2 . 2 . 8 + 24 − 1 . 5 = 12 . 16 + 115 = 12 .131 = 1572 𝐵𝑎𝑟𝑖𝑠𝑎𝑛 𝑘𝑢𝑟𝑠𝑖 ∶ 20 , 23 , … , 𝑈20 𝑎 = 20 𝑏 = 3 𝑆 𝑛 = 𝑛 2 . 2𝑎 + 𝑛 − 1 . 𝑏 𝑆20 = 20 2 . 2 . 20 + 20 − 1 . 3 = 10 . 40 + 57 = 10 .97 = 970 𝑘𝑢𝑟𝑠𝑖 920000 = 800000 + 9% . 𝑛 .800000 920000 − 800000 = 9 100 . 𝑛 .800000 120000 = 72000 . 𝑛 120000 72000 = 𝑛 5 3 = 𝑛 𝑛 = 5 3 𝑡𝑎𝑕𝑢𝑛 𝑛 = 5 3 .12 𝑏𝑢𝑙𝑎𝑛 𝑛 = 20 𝑏𝑢𝑙𝑎𝑛 2 . 𝑝 + 𝑙 = 144 2 . 3𝑥 + 10 + 𝑥 + 10 = 144 2 . 4𝑥 + 20 = 144 8𝑥 + 40 = 144 8𝑥 = 144 − 40 𝑥 = 104 8 = 13 𝑝 = 3𝑥 + 10 = 3 .13 + 10 = 39 + 10 = 49 𝑐𝑚 𝑙 = 𝑥 + 10 = 13 + 10 = 23 𝑐𝑚 5𝑥 − 3𝑥 = 12 + 8 2𝑥 = 20 𝑥 = 20 2 𝑥 = 10 → 𝑥 + 3 = 10 + 3 = 13 𝑖 9𝑎𝑏 + 21𝑎𝑐 = 3𝑎 . 3𝑏 + 7𝑐 𝑖𝑖 𝑥2 − 9 = 𝑥2 − 32 = 𝑥 − 3 . 𝑥 + 3 𝑖𝑖𝑖 3𝑝2 − 𝑝 − 2 = 3𝑝 + 2 . 𝑝 − 1
4. 4. www.siap-osn.blogspot.com @ Agustus 2014 SD.A 2 SMPN 1 Tambelangan Soal dan Pembahasan UN MATEMATIKA SMP 2014 / Page 4 Download Soal dan Pembahasan UN Matematika SMP 2014 Untuk Paket Soal Lainnya di “ www.siap-osn.blogspot.com ” 𝑛 𝑃 ∪ 𝐶 = 40 ; 𝑛 𝑃 = 23 ; 𝑛 𝑃 ∩ 𝐶 = 12 𝑛 𝑃 ∪ 𝐶 = 𝑛 𝑃 + 𝑛 𝐶 − 𝑛 𝑃 ∩ 𝐶 40 = 23 + 𝑛 𝐶 − 12 40 = 11 + 𝑛 𝐶 40 − 11 = 𝑛 𝐶 29 = 𝑛 𝐶 𝑛 𝐶 = 29 𝑜𝑟𝑎𝑛𝑔 𝑛 𝑃 = 3 𝐵𝑎𝑛𝑦𝑎𝑘 𝑕𝑖𝑚𝑝𝑢𝑛𝑎𝑛 𝑏𝑎𝑔𝑖𝑎𝑛 𝑑𝑎𝑟𝑖 𝑃 = 2 𝑛 𝑃 = 23 = 8 3𝑥 + 4𝑦 = 17 → 3𝑥 + 4𝑦 = 17 4𝑥 − 2𝑦 = 8 → 8𝑥 − 4𝑦 = 16 11𝑥 = 33 𝑥 = 33 11 = 3 𝑥 = 3 → 3𝑥 + 4𝑦 = 17 3 . 3 + 4𝑦 = 17 9 + 4𝑦 = 17 4𝑦 = 17 − 9 𝑦 = 8 4 = 2 2𝑥 + 3𝑦 = 2 . 3 + 3 . 2 = 6 + 6 = 12 3𝐴 + 5𝐵 = 39000 → 3𝐴 + 5𝐵 = 39000 𝐴 + 𝐵 = 11000 → 3𝐴 + 3𝐵 = 33000 2𝐵 = 6000 𝐵 = 6000 2 = 3000 𝐵 = 3000 → 𝐴 + 𝐵 = 11000 𝐴 + 3000 = 11000 𝐴 = 11000 − 3000 𝐴 = 8000 4𝐴 + 2𝐵 = 4 . 8000 + 2 . 3000 = 32000 + 6000 = 38000 𝑓 𝑥 = 3𝑥 + 5 𝑓 𝑎 = 3𝑎 + 5 = −7 3𝑎 = −7 − 5 𝑎 = −12 3 𝑎 = −4
5. 5. www.siap-osn.blogspot.com @ Agustus 2014 SD.A 2 SMPN 1 Tambelangan Soal dan Pembahasan UN MATEMATIKA SMP 2014 / Page 5 Download Soal dan Pembahasan UN Matematika SMP 2014 Untuk Paket Soal Lainnya di “ www.siap-osn.blogspot.com ” 𝑥 = 0 → 𝑦 = 2 . 0 − 1 𝑦 = −1 0, −1 𝑦𝑎𝑛𝑔 𝑚𝑒𝑚𝑒𝑛𝑢 𝑕𝑖 𝑔𝑎𝑚𝑏𝑎𝑟 𝑝𝑎𝑑𝑎 𝑝𝑖𝑙𝑖 𝑕𝑎𝑛 𝐴 𝑑𝑎𝑛 𝐵 𝑥 = 2 → 𝑦 = 2 . 2 − 1 𝑦 = 4 − 1 𝑦 = 3 2,3 𝐽𝑎𝑑𝑖 𝑦𝑎𝑛𝑔 𝑚𝑒𝑚𝑒𝑛𝑢 𝑕𝑖 𝑔𝑎𝑚𝑏𝑎𝑟 𝑝𝑎𝑑𝑎 𝑝𝑖𝑙𝑖 𝑕𝑎𝑛 𝐴 𝑃 −3 𝑥1 , 8 𝑦1 𝑑𝑎𝑛 𝑄 2 𝑥2 , 5 𝑦2 𝑚 𝑃𝑄 = 𝑦2 − 𝑦1 𝑥2 − 𝑥1 = 5 − 8 2 − (−3) = −3 2 + 3 = − 3 5 𝑆𝑦𝑎𝑟𝑎𝑡 𝑡𝑒𝑔𝑎𝑘 𝑙𝑢𝑟𝑢𝑠 ∶ 𝑚 . 𝑚 𝑃𝑄 = −1 𝑚 . − 3 5 = −1 𝑚 = −1 . − 5 3 𝑚 = 5 3 𝐴. 3𝑥 − 5𝑦 − 14 = 0 → 𝑚 = 3 5 𝐵. 3𝑥 + 5𝑦 + 14 = 0 → 𝑚 = − 3 5 𝐶. 5𝑥 + 3𝑦 − 42 = 0 → 𝑚 = − 5 3 𝐷. 5𝑥 − 3𝑦 − 42 = 0 → 𝑚 = 5 3
6. 6. www.siap-osn.blogspot.com @ Agustus 2014 SD.A 2 SMPN 1 Tambelangan Soal dan Pembahasan UN MATEMATIKA SMP 2014 / Page 6 Download Soal dan Pembahasan UN Matematika SMP 2014 Untuk Paket Soal Lainnya di “ www.siap-osn.blogspot.com ” 𝐴 2 𝑥1 , 7 𝑦1 ; 𝐵 −3 𝑥2 , −3 𝑦2 ; 𝐶 3 𝑥 , 𝑎 𝑦 𝑦 − 𝑦1 𝑦2 − 𝑦1 = 𝑥 − 𝑥1 𝑥2 − 𝑥1 𝑎 − 7 −3 − 7 = 3 − 2 −3 − 2 𝑎 − 7 −10 = 1 −5 𝑎 − 7 = 1 −5 . −10 𝑎 − 7 = 2 𝑎 = 2 + 7 𝑎 = 9 𝑃𝑎𝑛𝑗𝑎𝑛𝑔 𝑡𝑎𝑙𝑖 𝑛𝑖𝑙𝑎𝑖 𝑎𝑠𝑙𝑖 = 1502 + 1502 = 1502 .2 = 150 2 𝑃𝑎𝑛𝑗𝑎𝑛𝑔 𝑡𝑎𝑙𝑖 𝑝𝑒𝑛𝑑𝑒𝑘𝑎𝑡𝑎𝑛 = 1502 + 1502 = 22500 + 22500 = 45000 ≈ 44944 = 212 𝑚 𝐶𝐸 𝐴𝐶 = 𝐷𝐸 𝐴𝐵 𝐶𝐸 15 = 8 12 𝐶𝐸 = 8 12 .15 𝐶𝐸 = 10 𝑐𝑚
7. 7. www.siap-osn.blogspot.com @ Agustus 2014 SD.A 2 SMPN 1 Tambelangan Soal dan Pembahasan UN MATEMATIKA SMP 2014 / Page 7 Download Soal dan Pembahasan UN Matematika SMP 2014 Untuk Paket Soal Lainnya di “ www.siap-osn.blogspot.com ” 𝐿 𝑎𝑟𝑠𝑖𝑟𝑎𝑛 = 1 4 . 𝐿 𝑉𝑊𝑋𝑌 = 1 4 . 102 = 1 4 .100 = 25 𝑐𝑚2 𝐴𝐵 𝐶𝐷 = 𝐴𝐸 𝐸𝐶 = 𝐵𝐸 𝐸𝐷
8. 8. www.siap-osn.blogspot.com @ Agustus 2014 SD.A 2 SMPN 1 Tambelangan Soal dan Pembahasan UN MATEMATIKA SMP 2014 / Page 8 Download Soal dan Pembahasan UN Matematika SMP 2014 Untuk Paket Soal Lainnya di “ www.siap-osn.blogspot.com ” 𝐾𝑏𝑎𝑛𝑔𝑢𝑛 = 2 . 17 + 8 + 5 + 6 + 5 + 4 = 2 . 45 = 90 𝑐𝑚 𝑃𝑎𝑛𝑗𝑎𝑔 𝑏𝑢𝑠𝑢𝑟 𝐴𝐵 = ∠𝐴𝑂𝐵 360 𝑜 . 𝐾𝑙𝑖𝑛𝑔𝑘𝑎𝑟𝑎𝑛 = 60 𝑜 360 𝑜 .2 . 𝜋 . 𝑟 = 60 𝑜 360 𝑜 .2 . 3,14 .10 = 10,466 = 10,47 𝑐𝑚 ∠𝐴 + ∠𝐵 = 180 𝑜 5𝑦 − 16 𝑜 + 2𝑦 𝑜 = 180 𝑜 5𝑦 𝑜 − 16 𝑜 + 2𝑦 𝑜 = 180 𝑜 7𝑦 𝑜 − 16 𝑜 = 180 𝑜 7𝑦 𝑜 = 180 𝑜 + 16 𝑜 7𝑦 𝑜 = 196 𝑜 𝑦 𝑜 = 196 𝑜 7 𝑦 𝑜 = 28 𝑜 ∠𝐴 = 5𝑦 − 16 𝑜 = 5 .28 − 16 𝑜 = 140 − 16 𝑜 = 124 𝑜 𝐴𝐵 = 𝑃𝐿2 + 𝑅 − 𝑟 2 = 242 + 12 − 5 2 = 242 + 72 = 576 + 49 = 625 = 25 𝑐𝑚
9. 9. www.siap-osn.blogspot.com @ Agustus 2014 SD.A 2 SMPN 1 Tambelangan Soal dan Pembahasan UN MATEMATIKA SMP 2014 / Page 9 Download Soal dan Pembahasan UN Matematika SMP 2014 Untuk Paket Soal Lainnya di “ www.siap-osn.blogspot.com ” 𝑉𝑝𝑟𝑖𝑠𝑚𝑎 = 𝐿𝑡𝑟𝑎𝑝𝑒𝑠𝑖𝑢𝑚 . 𝑡 𝑝𝑟𝑖𝑠𝑚𝑎 = 1 2 . 𝐽𝑢𝑚𝑙𝑎𝑕 𝑠𝑖𝑠𝑖 𝑠𝑒𝑗𝑎𝑗𝑎𝑟 . 𝑡𝑡𝑟𝑎𝑝𝑒𝑠𝑖𝑢𝑚 . 𝑡 𝑝𝑟𝑖𝑠𝑚𝑎 = 1 2 . 8 + 12 .5 . 10 = 50 . 10 = 500 𝑐𝑚3 𝐿 𝑝𝑒𝑟𝑚𝑢𝑘𝑎𝑎𝑛 𝑙𝑖𝑚𝑎𝑠 = 𝐿 𝑝𝑒𝑟𝑠𝑒𝑔𝑖 𝐴𝐵𝐶𝐷 + 4 . 𝐿 𝑠𝑒𝑔𝑖𝑡𝑖𝑔𝑎 𝐵𝐶𝑇 = 𝐴𝐵2 + 4 . 1 2 . 𝐵𝐶 . 𝑇𝑃 = 162 + 4 . 1 2 .16 .17 = 256 + 544 = 800 𝑐𝑚2 𝐴𝐵 = 𝐵𝐶 = 𝐾𝑝𝑒𝑟𝑠𝑒𝑔𝑖 𝐴𝐵𝐶𝐷 4 = 64 4 = 16 𝑂𝑃 = 1 2 . 𝐴𝐵 = 1 2 .16 = 8 𝑇𝑃 = 𝑂𝑇2 + 𝑂𝑃2 = 152 + 82 = 225 + 64 = 289 = 17 𝑂𝐷 = 𝑟 = 1 2 . 𝐴𝐵 = 1 2 .14 = 7 𝑂𝑃 = 36 − 𝐴𝐷 = 36 − 12 = 24 𝐷𝑃 = 𝑠 = 𝑂𝐷2 + 𝑂𝑃2 = 72 + 242 = 49 + 576 = 625 = 25 𝐿 𝑝𝑒𝑟𝑚𝑢𝑘𝑎𝑎𝑛 𝑏𝑎𝑛𝑔𝑢𝑛 = 𝐿 𝑝𝑒𝑟𝑚𝑢𝑘𝑎𝑎𝑛 𝑡𝑎𝑏𝑢𝑛𝑔 𝑡𝑎𝑛𝑝𝑎 𝑡𝑢𝑡𝑢𝑝 + 𝐿 𝑠𝑒𝑙𝑖𝑚𝑢 𝑡 𝑘𝑒𝑟𝑢𝑐𝑢𝑡 = 𝜋𝑟2 + 2𝜋𝑟𝑡 + 𝜋𝑟𝑠 = 22 7 . 72 + 2 . 22 7 .7 .12 + 22 7 .7 .25 = 154 + 528 + 550 = 682 + 550 = 1232 𝑐𝑚2 𝑅𝑢𝑠𝑢𝑘 = 𝐴𝐵, 𝐵𝐶, 𝐶𝐷, 𝐷𝐸, 𝐸𝐹, 𝐹𝐴, 𝐴𝑇, 𝐵𝑇, 𝐶𝑇, 𝐷𝑇, 𝐸𝑇, 𝐹𝑇 → 12 𝑆𝑖𝑠𝑖 = 𝐴𝐵𝐶𝐷𝐸𝐹, 𝐴𝐵𝑇, 𝐵𝐶𝑇, 𝐶𝐷𝑇, 𝐷𝐸𝑇, 𝐸𝐹𝑇, 𝐹𝐴𝑇 → 7
10. 10. www.siap-osn.blogspot.com @ Agustus 2014 SD.A 2 SMPN 1 Tambelangan Soal dan Pembahasan UN MATEMATIKA SMP 2014 / Page 10 Download Soal dan Pembahasan UN Matematika SMP 2014 Untuk Paket Soal Lainnya di “ www.siap-osn.blogspot.com ” 𝑥 = 3 .3 + 4 .5 + 5 .12 + 6 .7 + 7 .6 + 8 .4 + 9 .3 3 + 5 + 12 + 7 + 6 + 4 + 3 = 232 40 = 5,8 𝐵𝑎𝑛𝑦𝑎𝑘 𝑠𝑖𝑠𝑤𝑎 𝑦𝑎𝑛𝑔 𝑙𝑢𝑙𝑢𝑠 = 7 + 6 + 4 + 3 = 20 𝑜𝑟𝑎𝑛𝑔 𝑥 𝑔𝑎𝑏𝑢𝑛𝑔𝑎𝑛 = 𝑛 𝑝 . 𝑥 𝑝 + 133 + 127 𝑛 𝑝 + 1 + 1 = 23 .130 + 133 + 127 23 + 1 + 1 = 23 .130 + 260 25 = 23 .130 + 2 .130 25 = 130 . 23 + 2 25 = 130 . 25 25 = 130 𝑈𝑟𝑢𝑡𝑎𝑛 𝑑𝑎𝑡𝑎 ∶ 165, 166,168, 168,170, 171, 171 𝑀𝑒𝑑𝑖𝑎𝑛 , 172, 173, 173, 175, 178, 182 (𝐵𝑒𝑙𝑢𝑚 𝑡𝑒𝑛𝑡𝑢 𝑥 𝑔𝑎𝑏𝑢𝑛𝑔𝑎𝑛 = 130) (𝐵𝑒𝑙𝑢𝑚 𝑡𝑒𝑛𝑡𝑢 𝑥 𝑔𝑎𝑏𝑢𝑛𝑔𝑎𝑛 = 130) (𝐵𝑒𝑙𝑢𝑚 𝑡𝑒𝑛𝑡𝑢 𝑥 𝑔𝑎𝑏𝑢𝑛𝑔𝑎𝑛 = 130) (𝑃𝑎𝑠𝑡𝑖 𝑥 𝑔𝑎𝑏𝑢𝑛𝑔𝑎𝑛 = 130)
11. 11. www.siap-osn.blogspot.com @ Agustus 2014 SD.A 2 SMPN 1 Tambelangan Soal dan Pembahasan UN MATEMATIKA SMP 2014 / Page 11 Download Soal dan Pembahasan UN Matematika SMP 2014 Untuk Paket Soal Lainnya di “ www.siap-osn.blogspot.com ” 150 + 250 = 400 𝑜𝑟𝑎𝑛𝑔 𝑛 𝑏𝑜𝑙𝑎 𝑏𝑒𝑟𝑛𝑜𝑚𝑜𝑟 𝑙𝑒𝑏𝑖𝑕 𝑑𝑎𝑟𝑖 6 = 2 𝑛 𝑆 = 8 𝑃 𝑏𝑜𝑙𝑎 𝑏𝑒𝑟𝑛𝑜𝑚𝑜𝑟 𝑙𝑒𝑏𝑖𝑕 𝑑𝑎𝑟𝑖 6 = 𝑛 𝑏𝑜𝑙𝑎 𝑏𝑒𝑟𝑛𝑜𝑚𝑜𝑟 𝑙𝑒𝑏𝑖𝑕 𝑑𝑎𝑟𝑖 6 𝑛 𝑆 = 2 8