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A = Ao. e – Λt => Ao/2 = Ao e – Λ10 => ½ = e – Λ10 =>
 ln ( ½ ) = ln ( e – Λ10 ) => ln (2-1 ) = ln ( e – Λ10 ) =>
=> - ln (2) = ln ( e – Λ10 ) => - ln (2) = - Λ10 =>
=> ln (2) = Λ10 => Λ = ln (2)/10 s-1
f = 1/ T = N / t => f = 5 / 10 => f = ½ s-1 => f = ½ Hz
f = 1/ T => ½ =1/ Τ => Τ = 2 s
A = Ao. e – Λt =>A15 =10-1e – Λt =>A15 =10-1e – ln2/10 t
=>A15 =10-1e – ln2/10 κΤ
=>A15 =10-1e – ln2/10 15 Τ
=>A15 =10-1e – ln2/10 15 2 =>
=>A15 =10-1e – ln2/10 . 15.2 => A15 =10-1e – ln2 /10 . 15.2
ln2 /10 . 15.2 = ln2 /10 .30 = ln2 . 30 /10 = ln2 .3
=> A15 =10-1e – 3. ln2 => A15 =10-1e – ln2 3
=> A15 =10-1/e ln2 3 => A15 =10-1/8 => A15 =1.25 10-1 m
e ln2 3 = 8
A = Ao. e – Λt => 2,5 = 10 . e – ln2/10t =>
2,5 = 10 . e – ln2/10t => 2,5 /10 = e – ln2/10t =>
1 /4 = e – ln2/10t => 1 /22 = e – ln2/10t =>
=> 2-2 = e – ln2/10t => ln (2-2 )= -ln2/10t =>
=> ln (2-2 )= -ln2/10t => -2 ln2= - ln2/10 t =>
=> -2 = - 1/10 t => 2 = 1/10 t => 2 .10 = t =>
=> t = 20 s
W = Eτελ- Eαρχ = > W = Εο. e -2Λt- Eο
= > W = Εο. e -2ln2/10t- Eο
= > W = Εο. ( e -2ln2/10t- 1)
= > W = Εο. ( e -2ln2/10. 10- 1)
= > W = Εο. ( e -2ln2- 1)
= > W = Εο. ( e -2ln2- 1) =>
=> W = Εο. ( 1 /e 2ln2- 1) =>
=> W = Εο. ( 1 /e ln2 2- 1) =>
W = Εο. ( 1 /22- 1) =>
=> W = Εο. ( 1 /4- 1) => W = Εο. ( -3 /4) J

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2024-NATIONAL-LEARNING-CAMP-AND-OTHER.pptx2024-NATIONAL-LEARNING-CAMP-AND-OTHER.pptx
2024-NATIONAL-LEARNING-CAMP-AND-OTHER.pptx
 
This PowerPoint helps students to consider the concept of infinity.
This PowerPoint helps students to consider the concept of infinity.This PowerPoint helps students to consider the concept of infinity.
This PowerPoint helps students to consider the concept of infinity.
 

258 - Askhsh fthinousa talantosh

  • 1.
  • 2. A = Ao. e – Λt => Ao/2 = Ao e – Λ10 => ½ = e – Λ10 =>  ln ( ½ ) = ln ( e – Λ10 ) => ln (2-1 ) = ln ( e – Λ10 ) => => - ln (2) = ln ( e – Λ10 ) => - ln (2) = - Λ10 => => ln (2) = Λ10 => Λ = ln (2)/10 s-1
  • 3. f = 1/ T = N / t => f = 5 / 10 => f = ½ s-1 => f = ½ Hz f = 1/ T => ½ =1/ Τ => Τ = 2 s
  • 4. A = Ao. e – Λt =>A15 =10-1e – Λt =>A15 =10-1e – ln2/10 t =>A15 =10-1e – ln2/10 κΤ =>A15 =10-1e – ln2/10 15 Τ =>A15 =10-1e – ln2/10 15 2 => =>A15 =10-1e – ln2/10 . 15.2 => A15 =10-1e – ln2 /10 . 15.2 ln2 /10 . 15.2 = ln2 /10 .30 = ln2 . 30 /10 = ln2 .3 => A15 =10-1e – 3. ln2 => A15 =10-1e – ln2 3 => A15 =10-1/e ln2 3 => A15 =10-1/8 => A15 =1.25 10-1 m e ln2 3 = 8
  • 5. A = Ao. e – Λt => 2,5 = 10 . e – ln2/10t => 2,5 = 10 . e – ln2/10t => 2,5 /10 = e – ln2/10t => 1 /4 = e – ln2/10t => 1 /22 = e – ln2/10t => => 2-2 = e – ln2/10t => ln (2-2 )= -ln2/10t =>
  • 6. => ln (2-2 )= -ln2/10t => -2 ln2= - ln2/10 t => => -2 = - 1/10 t => 2 = 1/10 t => 2 .10 = t => => t = 20 s
  • 7. W = Eτελ- Eαρχ = > W = Εο. e -2Λt- Eο = > W = Εο. e -2ln2/10t- Eο = > W = Εο. ( e -2ln2/10t- 1) = > W = Εο. ( e -2ln2/10. 10- 1) = > W = Εο. ( e -2ln2- 1)
  • 8. = > W = Εο. ( e -2ln2- 1) => => W = Εο. ( 1 /e 2ln2- 1) => => W = Εο. ( 1 /e ln2 2- 1) => W = Εο. ( 1 /22- 1) => => W = Εο. ( 1 /4- 1) => W = Εο. ( -3 /4) J