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7.7 Solving Radical Equations
p.453
What is a Radical Expression?
• A Radical Expression
is an equation that
has a variable in a
radicand or has a
variable with a
rational exponent.

3

x 10
2
3

yes

25

yes

3 x 10

no

( x 2)
Steps to solve a radical equation:
STEP 1: Isolate the radical on one side of the equation
(if possible)

STEP 2: Raise each side of the equation to a power equal to the
index of the radical to eliminate the radical
STEP 3: Solve the remaining polynomial equation.
CHECK YOUR RESULTS.
EXAMPLE – Solving a Radical
Equation
5x 1 6 0

5x 1 6
2

2

5x 1 (6 )

5x 1 36

5x 35
x 7

Square both sides to get rid of
the square root
EXAMPLE
x 15

3

x

2

2

x 15 (3

x 15 (3
x 15

24

3

16

x)

x )(3

9 6 x

15

16 15

x)
x

NO SOLUTION
Since 16 doesn’t plug in
as a solution.

9 6 x
6 x

4
x
16 x

1 3 4
1 1

Let’s Double Check
that this works

Note: You will get
Extraneous
Solutions from time
to time – always do
a quick check
Let’s Try Some
2

3x 2

6

2( x 2)

2
3

50
Let’s Try Some
2

3x 2

6

2( x 2)

2
3

50
SOLVING MORE COMPLEX
EQUATIONS
4( x 1)

2

101

20

2

4( x 1)
2
( x 1)
( x 1)
+ because we
are taking an
even power
(square root)
of both sides

81
81

( x 1) i
( x 1)

( x 1)

9i

x 1

9i

2

2

4

81

4

81

1
4

i 92

9i

2

1

9i

2
RADICAL EQUATIONS
3(5n 1)

1
3

2

3(5n 1)

1
3

2

1
3

(5n 1)
1 3
(5n 1) 3
(5n 1)

5n
5n

8

0
2

8

27

5n

RAISE BOTH SIDES
TO RECIPROCAL POWER

3

2

27
8

ISOLATE RADICAL / RATIONAL

3
3

SOLVE FOR THE VARIABLE

27

1
27
35

27

27

n

7

27
SOLVING MORE COMPLEX
EQUATIONS
(2 x 1)

0.5

(3x 4)

0.25

0

0.5

0.25

(2 x 1)
(3x 4)
0.5 4
0.25 4
[( 2 x 1) ] [(3x 4) ]
2
(2 x 1) 3 x 4

4x

2

4 x 1 3x 4

4x

2

Raise each side to the 4th
power. This will get you
integer powers – much
easier to work with!

x

x 3 0
3
, 1
4

Factor
Let’s Try Some . . . check for
extraneous solutions
(2 x 1)

0.5

(3x 4)

0.25

0
Let’s Try Some . . . check for
extraneous solutions
(2 x 1)

0.5

(3x 4)

0.25

0

x

3
, 1
4
Can graphing calculators help?
SURE!
x

1.
2.
3.
4.

x 2

Input x for Y1
Input x-2 for Y2
Graph
Find the points of
intersection
One Solution at (4, 2)
To see if this is extraneous or not, plug the x value
back into the equation. Does it work?

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7.7 Solving Radical Equations

  • 1. 7.7 Solving Radical Equations p.453
  • 2. What is a Radical Expression? • A Radical Expression is an equation that has a variable in a radicand or has a variable with a rational exponent. 3 x 10 2 3 yes 25 yes 3 x 10 no ( x 2)
  • 3. Steps to solve a radical equation: STEP 1: Isolate the radical on one side of the equation (if possible) STEP 2: Raise each side of the equation to a power equal to the index of the radical to eliminate the radical STEP 3: Solve the remaining polynomial equation. CHECK YOUR RESULTS.
  • 4. EXAMPLE – Solving a Radical Equation 5x 1 6 0 5x 1 6 2 2 5x 1 (6 ) 5x 1 36 5x 35 x 7 Square both sides to get rid of the square root
  • 5. EXAMPLE x 15 3 x 2 2 x 15 (3 x 15 (3 x 15 24 3 16 x) x )(3 9 6 x 15 16 15 x) x NO SOLUTION Since 16 doesn’t plug in as a solution. 9 6 x 6 x 4 x 16 x 1 3 4 1 1 Let’s Double Check that this works Note: You will get Extraneous Solutions from time to time – always do a quick check
  • 6. Let’s Try Some 2 3x 2 6 2( x 2) 2 3 50
  • 7. Let’s Try Some 2 3x 2 6 2( x 2) 2 3 50
  • 8. SOLVING MORE COMPLEX EQUATIONS 4( x 1) 2 101 20 2 4( x 1) 2 ( x 1) ( x 1) + because we are taking an even power (square root) of both sides 81 81 ( x 1) i ( x 1) ( x 1) 9i x 1 9i 2 2 4 81 4 81 1 4 i 92 9i 2 1 9i 2
  • 9. RADICAL EQUATIONS 3(5n 1) 1 3 2 3(5n 1) 1 3 2 1 3 (5n 1) 1 3 (5n 1) 3 (5n 1) 5n 5n 8 0 2 8 27 5n RAISE BOTH SIDES TO RECIPROCAL POWER 3 2 27 8 ISOLATE RADICAL / RATIONAL 3 3 SOLVE FOR THE VARIABLE 27 1 27 35 27 27 n 7 27
  • 10. SOLVING MORE COMPLEX EQUATIONS (2 x 1) 0.5 (3x 4) 0.25 0 0.5 0.25 (2 x 1) (3x 4) 0.5 4 0.25 4 [( 2 x 1) ] [(3x 4) ] 2 (2 x 1) 3 x 4 4x 2 4 x 1 3x 4 4x 2 Raise each side to the 4th power. This will get you integer powers – much easier to work with! x x 3 0 3 , 1 4 Factor
  • 11. Let’s Try Some . . . check for extraneous solutions (2 x 1) 0.5 (3x 4) 0.25 0
  • 12. Let’s Try Some . . . check for extraneous solutions (2 x 1) 0.5 (3x 4) 0.25 0 x 3 , 1 4
  • 13. Can graphing calculators help? SURE! x 1. 2. 3. 4. x 2 Input x for Y1 Input x-2 for Y2 Graph Find the points of intersection One Solution at (4, 2) To see if this is extraneous or not, plug the x value back into the equation. Does it work?