1. Demand
Description Current allowance (Amps)
Load Group
of load per unit Calculation
Circuit No (column 1)
(given list) (column 2)
L1 L2 L3
3 A (1st 20)
1 A (i) 13 Lighting points na 3.0
2 A (next 20)
2 A (i) 14 Lighting points 3 A (1st 20) na 3.0
3 A (i) 15 Lighting points 3 A (1st 20) na 3.0
8 + (4 x 2) = 16
8 single +
socket points +
4 B (i) 10 A (1st 20) 10.0
1 (pool filter
4 double outlets
pump) = 17
7 single +
7 + (5 x 2) =
5 B (i) 10 A (1st 20) 10.0
17 socket points
5 double outlets
One 15 A 10 A
B (ii) single phase (See note on group na 10.0
6
outlet in Table C1, B (ii))
50%
7 C Cook top 4200/240 x 0.5 8.8
(or x 0.5)
50%
8 C Oven rating 5200/240 x 0.5 10.8
(or x 0.5)
Pump rating = 4.3 A so socket outlet to
be used for pump supply.
9 B (i) Pool filter pump na
Socket will be part of circuit L1 so
Included with circuit 4 calculations
Air conditioner 75%
10 D 23.6 x 0.75 17.7 17.7 17.7
(23.6 A) (or x 0.75)
11a OPHWS
F Full load current 15.0
bottom element 3600/240
11b OPHWS Included
F Full load current 0.0
top element above
Total demand current per phase 40.7 39.5 46.5