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Kelompok 1

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It's talk about The Circle Equation with Center P(a,b) and radius r

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Kelompok 1

  1. 1. MATH TASK<br />GROUP 1<br />DIAN PERMANA<br />ANNISA INDAH REZA<br />DHIA ATIKAH ALIYYU<br />USWATUN HASANAH<br />WAN ELSA <br />
  2. 2. The Circle Equation with Center P(a,b) and radius r !<br /> The general equation distance is :<br />(x2-x1)2 + (y2-y1)2 =r2<br /> So in the circle,<br />x1 = a y1 = b<br />x2 = x y2 = y<br />Then the circle equation become :<br />(x-a)2 + (y-b)2= r2<br />y<br />T(x,y)<br />r<br />P(a,b)<br />x<br />
  3. 3. Example . . .<br />Determine the circle equation with center P(-2,3) with the following requirement :<br />a. Passing through point Q(4,-1) <br />b. Meet an exatly one point X<br />c. Meet an exatly one point Y<br />
  4. 4. Answers . . .<br />1. a. Q(4,-1)<br /> P(2,-3)<br /> (4-2)2 +(-3+1)2 = r2<br /> (2)2 + (-2)2 = r2<br /> 8 = r2<br />(x-2)2 + (y+1)2 = 8<br />b. Meet an exatly one point X means r = b = 3<br /> (x-2) + (y+1) = 9<br />c. Meet an exatly one point Y means r = a = 2<br /> (x-2) + (y+1) = 4<br />

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