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Kinematic Analysis: Scope
•Need to know the dynamic forces to be able to compute stresses in the components
• Dynamic forces are proportional to acceleration (Newton second law)
• Goal shifts to finding acceleration of all the moving parts in the assembly
•In order to calculate the accelerations:
• need to find the positions of all the links , for all increments in input motion
• differentiate the position eqs. to find velocities, diff. again to get accelerations
Velocity analysis: overview of methods
Graphical methods
Relative velocity method
Instantaneous centre method
Vector loop method
Velocity of any point on a link with respect to another point on the same link
Is always perpendicular to the line joining these points on the configuration (or space) diagram
Velocity: Rate of change of position with respect to time
Velocity analysis: Relative velocity method
Only direction known
Completely known
Complex Motion as a case of pure rotation
As the position of link AB goes on changing, so does
the centre I, about which AB is assumed to be rotating.
Hence, the name Instantaneous Centre.
The locus of all such instantaneous centres is known
as centrode.
A line drawn through an instantaneous centre and
perpendicular to the plane of motion is an
instantaneous axis.
The locus of instantaneous axis is known as axode.
(axis+centrode=axode)
Velocity analysis: Instantaneous centre method
Locating an Instantaneous Center of Rotation, and its use
Just two directions of velocities,
help locate the IcR
One complete velocity (magnitude + direction)
&
one other velocity direction,
helps find velocity of any other point.
Velocity analysis: Instantaneous centre method
VA: Known full
VB: Only direction
No relative motion between A and B
Lami’s theorem to triangle ABI
Locating an Instantaneous Center of Rotation, and its use
Velocity analysis: Instantaneous centre method
More on Instantaneous Centres
No of Instantaneous Centres = No. of possible combinations of two links
= No. of combinations of n links taken two at a time
pes of Instantaneous Centres
Fixed: Remain in the same place for all
configurations of the mechanism
Permanent: Change positions but the
nature of joints is permanent
Neither fixed nor permanent
Velocity analysis: Instantaneous centre method
Primary IcR
Secondary IcR
Rules for locating Instantaneous Centres
For two links
connected
by a pin joint,
the IcR lies
on the centre
of the pin
When the two links
have a pure rolling
(no slipping) contact,
the IcR lies on their
point of contact
When the two links have a sliding contact, the IcR lies on the
common normal at the point of contact
The ICR lies
at infinity, and
each point on
the slider has
the same
velocity
The ICR lies
on the centre of
curvature, of the
curvilinear path,
at that instant
The ICR lies on
the centre of
curvature, which
being the centre
of the circle is
fixed for all
configurations of
the links.
Velocity analysis: Instantaneous centre method
Aronhold Kennedy (or Three Centres in Line) Theorem
Velocity analysis: Instantaneous centre method
Three links: A, B, & C, having
relative plane motion.
Aronhold Kennedy’s theorem:
if three bodies move relative
to each other, they have three
Instantaneous centres, and
they lie on a straight line.
Ibc must lie on the line joining Iab and Iac
Consider Ibc lying outside the line joining Iab and Iac. Now Ibc belongs to both the links B and C.
Consider Ibc ϵ link B: VBC must be perpendicular to the line joining Iab and Ibc.
Consider Ibc ϵ link C: VBC must be perpendicular to the line joining Iac and Ibc.
But Ibc is a unique point; and hence, regardless of whether it ϵ link B or Link C, it should have a
unique velocity (magnitude and direction). This is possible only when the three instantaneous
centres, namely, Iab, Iac and Ibc lie on the same straight line.
The exact location of Ibc on the line Iab Iac depends on the directions and magnitudes of the angular
Velocities of B and C relative to A.
Velocity analysis: Instantaneous centre method
Pin jointed
4-bar mechanism
1. Determine the number of instantaneous
centres (N) by using the relation
2. Make a list of all the IcRs in the
mechanism
4. Locate the secondary IcRs using kennedy’s theorem: if three bodies move
relative to each other, they have three Instantaneous centres, and
they lie on a straight line.
a
b
c
d
To implement KnDT: Look for quadrilaterals in the circle diagram, and form diagonals. Clearly each
diagonal (say, 1-3) will form two adjacent triangles (1-3-4, and, 1-2-3), that is, each diagonal will
form 2 pairs of three bodies in relative motion, to each of which KnDT can be applied
I13 will lie on the intersection of I12-I23 (3 bodies: 1-2-3) and I14-I34 (3 bodies: 1-3-4), produced, if
necessary.
I24 will lie on the intersection of I12-I14 (3 bodies: 1-2-4) and I23-I34 (3 bodies: 2-3-4), produced, if
necessary.
Circle diagram
3. Locate by inspection, the primary IcRs,
and mark them by solid lines, on the
circle diagram
L
Velocity analysis: Instantaneous centre method
Step-I: Perpendiculars to the two known direction
of velocities of B & C help locate the IcR at O
Step-II: Point B belongs to both:
- the link AB, under pure rotation about A
- the link BC, under complex motion,
equivalent to pure rotation about O. ωAB * AB = ωBC * BO
Step-III: Point C belongs to both:
- the link CD, under pure rotation about D
- the link BC, under complex motion,
equivalent to pure rotation about O.
ωAB is given, and ωBC and ωCD are to be determined
ωCD * CD = ωBC * CO
ωBC
already known by now
Velocity analysis: Instantaneous centre method: Exp-I
Locate all the IcRs of the slider crank mech. shown in the figure. The lengths of crank OB and
connecting rod AB are 100 and 400 mm,
respectively. If the crank rotates clockwise
with an angular velocity of 10 rad/s, find:
(i) Velocity of the slider A, and
(ii) Angular velocity of the connecting rod AB.
known
I13 and I24 : unknown
Velocity analysis: Instantaneous centre method: Exp-I
To implement KnDT: Look for quadrilaterals in the
circle diagram, and form diagonals. Clearly each
diagonal (say, 1-3) will form two adjacent triangles
(1-3-4, and, 1-2-3), that is, each diagonal will
form 2 pairs of three bodies in relative motion,
to each of which KnDT can be applied
I24 will lie on the intersection of I12-I14 (3 bodies:
1-2-4) and I23-I34 (3 bodies: 2-3-4), produced, if
necessary.
I13 will lie on the intersection of I12-I23 (3 bodies:
1-2-3) and I14-I34 (3 bodies: 1-3-4), produced,
if necessary.
VA and wAB ?
I13 and I24 are unknown
AB is having a complex motion,
equivalent to pure rotation about I13
Velocity analysis: Rubbing velocity at a pin joint
Velocity analysis: Velocity difference (2 points on the same body)
Reference: Pivot is no longer the origian of GCS,
instead has a linear velocity
Reference: Pivot is no longer the origian of GCS, instead has a linear velocity
When P and A are not on the same body, the resultant vector Is different.
VPA as the Velocity difference
helps find the resultant.
VPA as the relative velocity is
the resultant.
VPA is not perpendicular to
the line joining P and A.
Velocity analysis: Relative Velocity (2 points on different bodies)
Velocity analysis: Velocity of slip
Both the links forming the sliding joint, are not grounded, implying
a floating sliding joint.
Notably, point A belongs to two different bodies, namely, 2 &3,
Implying case2: relative velocity.
Axis of Slip: Line along which sliding occurs between links 3 & 4.
Axis of transmission: The line along which we can transmit motion or
force across the slider joint (except friction - assumed negligible)
Velocity analysis: Velocity of slip
Intuition: The axis of 3 & 4 have a fixed geometric relationship,
hence the rate of change of θ3 θ4 will remain the same: ω3=ω4
VA3=VA2
Velocity analysis: Velocity of slip
Perpendicular to O2A
Sense as ω2
Velocity analysis: Velocity of slip
Velocity analysis:
Vector loop equations
&
Complex number notation
Velocity analysis: Refreshing basics from position analysis
The position of B with respect to A =
Absolute position of B minus that of A;
(absolute implying the origin of the GCS.)
Velocity analysis: Complex number notation
Velocity is rate of change of position with respect to time.
- Position ( R) is a vector quantity, so is velocity
- Velocity can be linear (V) or angular (θ)
The velocity vector is rotated through 90º w.r.t the original position vector,
where the sense of the velocity vector is dictated by the sign of ω,
where anticlockwise may be taken as positive
Reference: Global Co-ordinate System (pivot: GCS origin)
VP=VPA
Velocity analysis: Vector loop equation
Velocity analysis: Vector loop equation- Problem 1
θ1derivative = 0
θ3 ,θ4 ?
Velocity analysis: Vector loop equation- Problem 2
d, θ3 ?
Velocity analysis: Vector loop equation- Problem 3
b, θ4 ?
Velocity of slip
at point B
Angular Velocity
of link 4

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7.velocity analysis

  • 1. Kinematic Analysis: Scope •Need to know the dynamic forces to be able to compute stresses in the components • Dynamic forces are proportional to acceleration (Newton second law) • Goal shifts to finding acceleration of all the moving parts in the assembly •In order to calculate the accelerations: • need to find the positions of all the links , for all increments in input motion • differentiate the position eqs. to find velocities, diff. again to get accelerations
  • 2. Velocity analysis: overview of methods Graphical methods Relative velocity method Instantaneous centre method Vector loop method Velocity of any point on a link with respect to another point on the same link Is always perpendicular to the line joining these points on the configuration (or space) diagram Velocity: Rate of change of position with respect to time
  • 3. Velocity analysis: Relative velocity method Only direction known Completely known
  • 4. Complex Motion as a case of pure rotation As the position of link AB goes on changing, so does the centre I, about which AB is assumed to be rotating. Hence, the name Instantaneous Centre. The locus of all such instantaneous centres is known as centrode. A line drawn through an instantaneous centre and perpendicular to the plane of motion is an instantaneous axis. The locus of instantaneous axis is known as axode. (axis+centrode=axode) Velocity analysis: Instantaneous centre method
  • 5. Locating an Instantaneous Center of Rotation, and its use Just two directions of velocities, help locate the IcR One complete velocity (magnitude + direction) & one other velocity direction, helps find velocity of any other point. Velocity analysis: Instantaneous centre method
  • 6. VA: Known full VB: Only direction No relative motion between A and B Lami’s theorem to triangle ABI Locating an Instantaneous Center of Rotation, and its use Velocity analysis: Instantaneous centre method
  • 7. More on Instantaneous Centres No of Instantaneous Centres = No. of possible combinations of two links = No. of combinations of n links taken two at a time pes of Instantaneous Centres Fixed: Remain in the same place for all configurations of the mechanism Permanent: Change positions but the nature of joints is permanent Neither fixed nor permanent Velocity analysis: Instantaneous centre method Primary IcR Secondary IcR
  • 8. Rules for locating Instantaneous Centres For two links connected by a pin joint, the IcR lies on the centre of the pin When the two links have a pure rolling (no slipping) contact, the IcR lies on their point of contact When the two links have a sliding contact, the IcR lies on the common normal at the point of contact The ICR lies at infinity, and each point on the slider has the same velocity The ICR lies on the centre of curvature, of the curvilinear path, at that instant The ICR lies on the centre of curvature, which being the centre of the circle is fixed for all configurations of the links. Velocity analysis: Instantaneous centre method
  • 9. Aronhold Kennedy (or Three Centres in Line) Theorem Velocity analysis: Instantaneous centre method Three links: A, B, & C, having relative plane motion. Aronhold Kennedy’s theorem: if three bodies move relative to each other, they have three Instantaneous centres, and they lie on a straight line. Ibc must lie on the line joining Iab and Iac Consider Ibc lying outside the line joining Iab and Iac. Now Ibc belongs to both the links B and C. Consider Ibc ϵ link B: VBC must be perpendicular to the line joining Iab and Ibc. Consider Ibc ϵ link C: VBC must be perpendicular to the line joining Iac and Ibc. But Ibc is a unique point; and hence, regardless of whether it ϵ link B or Link C, it should have a unique velocity (magnitude and direction). This is possible only when the three instantaneous centres, namely, Iab, Iac and Ibc lie on the same straight line. The exact location of Ibc on the line Iab Iac depends on the directions and magnitudes of the angular Velocities of B and C relative to A.
  • 10. Velocity analysis: Instantaneous centre method Pin jointed 4-bar mechanism 1. Determine the number of instantaneous centres (N) by using the relation 2. Make a list of all the IcRs in the mechanism 4. Locate the secondary IcRs using kennedy’s theorem: if three bodies move relative to each other, they have three Instantaneous centres, and they lie on a straight line. a b c d To implement KnDT: Look for quadrilaterals in the circle diagram, and form diagonals. Clearly each diagonal (say, 1-3) will form two adjacent triangles (1-3-4, and, 1-2-3), that is, each diagonal will form 2 pairs of three bodies in relative motion, to each of which KnDT can be applied I13 will lie on the intersection of I12-I23 (3 bodies: 1-2-3) and I14-I34 (3 bodies: 1-3-4), produced, if necessary. I24 will lie on the intersection of I12-I14 (3 bodies: 1-2-4) and I23-I34 (3 bodies: 2-3-4), produced, if necessary. Circle diagram 3. Locate by inspection, the primary IcRs, and mark them by solid lines, on the circle diagram L
  • 11. Velocity analysis: Instantaneous centre method Step-I: Perpendiculars to the two known direction of velocities of B & C help locate the IcR at O Step-II: Point B belongs to both: - the link AB, under pure rotation about A - the link BC, under complex motion, equivalent to pure rotation about O. ωAB * AB = ωBC * BO Step-III: Point C belongs to both: - the link CD, under pure rotation about D - the link BC, under complex motion, equivalent to pure rotation about O. ωAB is given, and ωBC and ωCD are to be determined ωCD * CD = ωBC * CO ωBC already known by now
  • 12. Velocity analysis: Instantaneous centre method: Exp-I Locate all the IcRs of the slider crank mech. shown in the figure. The lengths of crank OB and connecting rod AB are 100 and 400 mm, respectively. If the crank rotates clockwise with an angular velocity of 10 rad/s, find: (i) Velocity of the slider A, and (ii) Angular velocity of the connecting rod AB. known I13 and I24 : unknown
  • 13. Velocity analysis: Instantaneous centre method: Exp-I To implement KnDT: Look for quadrilaterals in the circle diagram, and form diagonals. Clearly each diagonal (say, 1-3) will form two adjacent triangles (1-3-4, and, 1-2-3), that is, each diagonal will form 2 pairs of three bodies in relative motion, to each of which KnDT can be applied I24 will lie on the intersection of I12-I14 (3 bodies: 1-2-4) and I23-I34 (3 bodies: 2-3-4), produced, if necessary. I13 will lie on the intersection of I12-I23 (3 bodies: 1-2-3) and I14-I34 (3 bodies: 1-3-4), produced, if necessary. VA and wAB ? I13 and I24 are unknown AB is having a complex motion, equivalent to pure rotation about I13
  • 14. Velocity analysis: Rubbing velocity at a pin joint
  • 15. Velocity analysis: Velocity difference (2 points on the same body) Reference: Pivot is no longer the origian of GCS, instead has a linear velocity
  • 16. Reference: Pivot is no longer the origian of GCS, instead has a linear velocity When P and A are not on the same body, the resultant vector Is different. VPA as the Velocity difference helps find the resultant. VPA as the relative velocity is the resultant. VPA is not perpendicular to the line joining P and A. Velocity analysis: Relative Velocity (2 points on different bodies)
  • 17. Velocity analysis: Velocity of slip Both the links forming the sliding joint, are not grounded, implying a floating sliding joint. Notably, point A belongs to two different bodies, namely, 2 &3, Implying case2: relative velocity. Axis of Slip: Line along which sliding occurs between links 3 & 4. Axis of transmission: The line along which we can transmit motion or force across the slider joint (except friction - assumed negligible)
  • 18. Velocity analysis: Velocity of slip Intuition: The axis of 3 & 4 have a fixed geometric relationship, hence the rate of change of θ3 θ4 will remain the same: ω3=ω4 VA3=VA2
  • 19. Velocity analysis: Velocity of slip Perpendicular to O2A Sense as ω2
  • 21. Velocity analysis: Vector loop equations & Complex number notation
  • 22. Velocity analysis: Refreshing basics from position analysis The position of B with respect to A = Absolute position of B minus that of A; (absolute implying the origin of the GCS.)
  • 23. Velocity analysis: Complex number notation Velocity is rate of change of position with respect to time. - Position ( R) is a vector quantity, so is velocity - Velocity can be linear (V) or angular (θ) The velocity vector is rotated through 90º w.r.t the original position vector, where the sense of the velocity vector is dictated by the sign of ω, where anticlockwise may be taken as positive Reference: Global Co-ordinate System (pivot: GCS origin) VP=VPA
  • 24. Velocity analysis: Vector loop equation
  • 25. Velocity analysis: Vector loop equation- Problem 1 θ1derivative = 0 θ3 ,θ4 ?
  • 26. Velocity analysis: Vector loop equation- Problem 2 d, θ3 ?
  • 27. Velocity analysis: Vector loop equation- Problem 3 b, θ4 ? Velocity of slip at point B Angular Velocity of link 4